Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (645)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Haritha drove the first 4h of her journey at 50 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 83 $\frac{km}{h}$ for 4h and then slowed down to 48 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Ramani drove the first 3h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 80 $\frac{km}{h}$ for 2h and then slowed down to 60 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Ponnalagu drove the first 2h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 75 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 76 $\frac{km}{h}$ for 1h and then slowed down to 52 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Nandini drove the first 4h of her journey at 50 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 74 $\frac{km}{h}$ for 1h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Pavi drove the first 3h of her journey at 50 $\frac{km}{h.}$
Driving at an average speed of 65 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

10)

Mr Goh drove at 72 $\frac{km}{h}$ for 2h and then slowed down to 56 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

SOLUTION 1 :

Step 1:	Distance covered at a speed of 50 $\frac{km}{h}$	→	50 $\frac{km}{h}$ x 4 h
		=	200 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 5 h
		=	400 km

Step 3:	Total distance	→	200 km + 400 km
		=	600 km

Step 4:	Total time	→	4 h + 5 h
		=	9 h

Step 5:	Average speed	→	600 km ÷ 9 h
		=	66.66667 $\frac{km}{h}$
		≈	66.67 $\frac{km}{h}$

Answer: 80.94 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 83 $\frac{km}{h}$	→	83 $\frac{km}{h}$ x 4 h
		=	332 km

Step 2:	Distance covered at a speed of 48 $\frac{km}{h}$	→	48 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	48 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	12 km

Step 3:	Total distance	→	332 km + 12 km
		=	344 km

Step 4:	Total time	→	4 h + $\frac{1}{4}$ h
		=	4 $\frac{1}{4}$ h

Step 5:	Average speed	→	344 km ÷ 4 $\frac{1}{4}$ h
		=	80.94118 $\frac{km}{h}$
		≈	80.94 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 3 h
		=	165 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 5 h
		=	400 km

Step 3:	Total distance	→	165 km + 400 km
		=	565 km

Step 4:	Total time	→	3 h + 5 h
		=	8 h

Step 5:	Average speed	→	565 km ÷ 8 h
		=	70.625 $\frac{km}{h}$
		≈	70.63 $\frac{km}{h}$

Answer: 77.78 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 2 h
		=	160 km

Step 2:	Distance covered at a speed of 60 $\frac{km}{h}$	→	60 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	60 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	15 km

Step 3:	Total distance	→	160 km + 15 km
		=	175 km

Step 4:	Total time	→	2 h + $\frac{1}{4}$ h
		=	2 $\frac{1}{4}$ h

Step 5:	Average speed	→	175 km ÷ 2 $\frac{1}{4}$ h
		=	77.77778 $\frac{km}{h}$
		≈	77.78 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 2 h
		=	90 km

Step 2:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 7 h
		=	525 km

Step 3:	Total distance	→	90 km + 525 km
		=	615 km

Step 4:	Total time	→	2 h + 7 h
		=	9 h

Step 5:	Average speed	→	615 km ÷ 9 h
		=	68.33333 $\frac{km}{h}$
		≈	68.33 $\frac{km}{h}$

Answer: 71.20 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 76 $\frac{km}{h}$	→	76 $\frac{km}{h}$ x 1 h
		=	76 km

Step 2:	Distance covered at a speed of 52 $\frac{km}{h}$	→	52 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	52 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	13 km

Step 3:	Total distance	→	76 km + 13 km
		=	89 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	89 km ÷ 1 $\frac{1}{4}$ h
		=	71.2 $\frac{km}{h}$
		≈	71.20 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 50 $\frac{km}{h}$	→	50 $\frac{km}{h}$ x 4 h
		=	200 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 7 h
		=	560 km

Step 3:	Total distance	→	200 km + 560 km
		=	760 km

Step 4:	Total time	→	4 h + 7 h
		=	11 h

Step 5:	Average speed	→	760 km ÷ 11 h
		=	69.09091 $\frac{km}{h}$
		≈	69.09 $\frac{km}{h}$

Answer: 67.20 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 74 $\frac{km}{h}$	→	74 $\frac{km}{h}$ x 1 h
		=	74 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	74 km + 10 km
		=	84 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	84 km ÷ 1 $\frac{1}{4}$ h
		=	67.2 $\frac{km}{h}$
		≈	67.20 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 50 $\frac{km}{h}$	→	50 $\frac{km}{h}$ x 3 h
		=	150 km

Step 2:	Distance covered at a speed of 65 $\frac{km}{h}$	→	65 $\frac{km}{h}$ x 5 h
		=	325 km

Step 3:	Total distance	→	150 km + 325 km
		=	475 km

Step 4:	Total time	→	3 h + 5 h
		=	8 h

Step 5:	Average speed	→	475 km ÷ 8 h
		=	59.375 $\frac{km}{h}$
		≈	59.38 $\frac{km}{h}$

10)

Answer: 70.22 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 72 $\frac{km}{h}$	→	72 $\frac{km}{h}$ x 2 h
		=	144 km

Step 2:	Distance covered at a speed of 56 $\frac{km}{h}$	→	56 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	56 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	14 km

Step 3:	Total distance	→	144 km + 14 km
		=	158 km

Step 4:	Total time	→	2 h + $\frac{1}{4}$ h
		=	2 $\frac{1}{4}$ h

Step 5:	Average speed	→	158 km ÷ 2 $\frac{1}{4}$ h
		=	70.22222 $\frac{km}{h}$
		≈	70.22 $\frac{km}{h}$