Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (645)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Mr Goh drove at 65 $\frac{km}{h}$ for 3h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Tamilselvi drove the first 2h of her journey at 50 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 81 $\frac{km}{h}$ for 2h and then slowed down to 48 $\frac{km}{h}$ for the next 45 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Haritha drove the first 2h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 66 $\frac{km}{h}$ for 1h and then slowed down to 52 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Parveen drove the first 3h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 65 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 80 $\frac{km}{h}$ for 4h and then slowed down to 56 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Ramani drove the first 2h of her journey at 50 $\frac{km}{h.}$
Driving at an average speed of 70 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 83 $\frac{km}{h}$ for 1h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

10)

Mithra drove the first 2h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 70 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Answer: 63.08 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 65 $\frac{km}{h}$	→	65 $\frac{km}{h}$ x 3 h
		=	195 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	195 km + 10 km
		=	205 km

Step 4:	Total time	→	3 h + $\frac{1}{4}$ h
		=	3 $\frac{1}{4}$ h

Step 5:	Average speed	→	205 km ÷ 3 $\frac{1}{4}$ h
		=	63.07692 $\frac{km}{h}$
		≈	63.08 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 50 $\frac{km}{h}$	→	50 $\frac{km}{h}$ x 2 h
		=	100 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 6 h
		=	480 km

Step 3:	Total distance	→	100 km + 480 km
		=	580 km

Step 4:	Total time	→	2 h + 6 h
		=	8 h

Step 5:	Average speed	→	580 km ÷ 8 h
		=	72.5 $\frac{km}{h}$
		≈	72.50 $\frac{km}{h}$

Answer: 72.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 81 $\frac{km}{h}$	→	81 $\frac{km}{h}$ x 2 h
		=	162 km

Step 2:	Distance covered at a speed of 48 $\frac{km}{h}$	→	48 $\frac{km}{h}$ x $\frac{45}{60}$ h
		=	48 $\frac{km}{h}$ x $\frac{3}{4}$ h
		=	36 km

Step 3:	Total distance	→	162 km + 36 km
		=	198 km

Step 4:	Total time	→	2 h + $\frac{3}{4}$ h
		=	2 $\frac{3}{4}$ h

Step 5:	Average speed	→	198 km ÷ 2 $\frac{3}{4}$ h
		=	72 $\frac{km}{h}$
		≈	72.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 2 h
		=	110 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 6 h
		=	480 km

Step 3:	Total distance	→	110 km + 480 km
		=	590 km

Step 4:	Total time	→	2 h + 6 h
		=	8 h

Step 5:	Average speed	→	590 km ÷ 8 h
		=	73.75 $\frac{km}{h}$
		≈	73.75 $\frac{km}{h}$

Answer: 63.20 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 66 $\frac{km}{h}$	→	66 $\frac{km}{h}$ x 1 h
		=	66 km

Step 2:	Distance covered at a speed of 52 $\frac{km}{h}$	→	52 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	52 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	13 km

Step 3:	Total distance	→	66 km + 13 km
		=	79 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	79 km ÷ 1 $\frac{1}{4}$ h
		=	63.2 $\frac{km}{h}$
		≈	63.20 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 3 h
		=	135 km

Step 2:	Distance covered at a speed of 65 $\frac{km}{h}$	→	65 $\frac{km}{h}$ x 7 h
		=	455 km

Step 3:	Total distance	→	135 km + 455 km
		=	590 km

Step 4:	Total time	→	3 h + 7 h
		=	10 h

Step 5:	Average speed	→	590 km ÷ 10 h
		=	59 $\frac{km}{h}$
		≈	59.00 $\frac{km}{h}$

Answer: 78.59 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 4 h
		=	320 km

Step 2:	Distance covered at a speed of 56 $\frac{km}{h}$	→	56 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	56 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	14 km

Step 3:	Total distance	→	320 km + 14 km
		=	334 km

Step 4:	Total time	→	4 h + $\frac{1}{4}$ h
		=	4 $\frac{1}{4}$ h

Step 5:	Average speed	→	334 km ÷ 4 $\frac{1}{4}$ h
		=	78.58824 $\frac{km}{h}$
		≈	78.59 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 50 $\frac{km}{h}$	→	50 $\frac{km}{h}$ x 2 h
		=	100 km

Step 2:	Distance covered at a speed of 70 $\frac{km}{h}$	→	70 $\frac{km}{h}$ x 5 h
		=	350 km

Step 3:	Total distance	→	100 km + 350 km
		=	450 km

Step 4:	Total time	→	2 h + 5 h
		=	7 h

Step 5:	Average speed	→	450 km ÷ 7 h
		=	64.28571 $\frac{km}{h}$
		≈	64.29 $\frac{km}{h}$

Answer: 74.40 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 83 $\frac{km}{h}$	→	83 $\frac{km}{h}$ x 1 h
		=	83 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	83 km + 10 km
		=	93 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	93 km ÷ 1 $\frac{1}{4}$ h
		=	74.4 $\frac{km}{h}$
		≈	74.40 $\frac{km}{h}$

10)

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 2 h
		=	90 km

Step 2:	Distance covered at a speed of 70 $\frac{km}{h}$	→	70 $\frac{km}{h}$ x 7 h
		=	490 km

Step 3:	Total distance	→	90 km + 490 km
		=	580 km

Step 4:	Total time	→	2 h + 7 h
		=	9 h

Step 5:	Average speed	→	580 km ÷ 9 h
		=	64.44444 $\frac{km}{h}$
		≈	64.44 $\frac{km}{h}$