Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (645)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Mr Goh drove at 66 $\frac{km}{h}$ for 2h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Indra drove the first 3h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 65 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 75 $\frac{km}{h}$ for 3h and then slowed down to 44 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Parveen drove the first 4h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 75 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 78 $\frac{km}{h}$ for 4h and then slowed down to 44 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Swathi drove the first 3h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 66 $\frac{km}{h}$ for 3h and then slowed down to 48 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Ovini drove the first 2h of her journey at 50 $\frac{km}{h.}$
Driving at an average speed of 70 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 70 $\frac{km}{h}$ for 3h and then slowed down to 40 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

10)

Thamarai drove the first 4h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 70 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Answer: 63.11 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 66 $\frac{km}{h}$	→	66 $\frac{km}{h}$ x 2 h
		=	132 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	132 km + 10 km
		=	142 km

Step 4:	Total time	→	2 h + $\frac{1}{4}$ h
		=	2 $\frac{1}{4}$ h

Step 5:	Average speed	→	142 km ÷ 2 $\frac{1}{4}$ h
		=	63.11111 $\frac{km}{h}$
		≈	63.11 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 3 h
		=	165 km

Step 2:	Distance covered at a speed of 65 $\frac{km}{h}$	→	65 $\frac{km}{h}$ x 7 h
		=	455 km

Step 3:	Total distance	→	165 km + 455 km
		=	620 km

Step 4:	Total time	→	3 h + 7 h
		=	10 h

Step 5:	Average speed	→	620 km ÷ 10 h
		=	62 $\frac{km}{h}$
		≈	62.00 $\frac{km}{h}$

Answer: 72.62 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 3 h
		=	225 km

Step 2:	Distance covered at a speed of 44 $\frac{km}{h}$	→	44 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	44 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	11 km

Step 3:	Total distance	→	225 km + 11 km
		=	236 km

Step 4:	Total time	→	3 h + $\frac{1}{4}$ h
		=	3 $\frac{1}{4}$ h

Step 5:	Average speed	→	236 km ÷ 3 $\frac{1}{4}$ h
		=	72.61538 $\frac{km}{h}$
		≈	72.62 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 4 h
		=	220 km

Step 2:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 5 h
		=	375 km

Step 3:	Total distance	→	220 km + 375 km
		=	595 km

Step 4:	Total time	→	4 h + 5 h
		=	9 h

Step 5:	Average speed	→	595 km ÷ 9 h
		=	66.11111 $\frac{km}{h}$
		≈	66.11 $\frac{km}{h}$

Answer: 76.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 78 $\frac{km}{h}$	→	78 $\frac{km}{h}$ x 4 h
		=	312 km

Step 2:	Distance covered at a speed of 44 $\frac{km}{h}$	→	44 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	44 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	11 km

Step 3:	Total distance	→	312 km + 11 km
		=	323 km

Step 4:	Total time	→	4 h + $\frac{1}{4}$ h
		=	4 $\frac{1}{4}$ h

Step 5:	Average speed	→	323 km ÷ 4 $\frac{1}{4}$ h
		=	76 $\frac{km}{h}$
		≈	76.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 3 h
		=	135 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 6 h
		=	480 km

Step 3:	Total distance	→	135 km + 480 km
		=	615 km

Step 4:	Total time	→	3 h + 6 h
		=	9 h

Step 5:	Average speed	→	615 km ÷ 9 h
		=	68.33333 $\frac{km}{h}$
		≈	68.33 $\frac{km}{h}$

Answer: 64.62 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 66 $\frac{km}{h}$	→	66 $\frac{km}{h}$ x 3 h
		=	198 km

Step 2:	Distance covered at a speed of 48 $\frac{km}{h}$	→	48 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	48 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	12 km

Step 3:	Total distance	→	198 km + 12 km
		=	210 km

Step 4:	Total time	→	3 h + $\frac{1}{4}$ h
		=	3 $\frac{1}{4}$ h

Step 5:	Average speed	→	210 km ÷ 3 $\frac{1}{4}$ h
		=	64.61538 $\frac{km}{h}$
		≈	64.62 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 50 $\frac{km}{h}$	→	50 $\frac{km}{h}$ x 2 h
		=	100 km

Step 2:	Distance covered at a speed of 70 $\frac{km}{h}$	→	70 $\frac{km}{h}$ x 6 h
		=	420 km

Step 3:	Total distance	→	100 km + 420 km
		=	520 km

Step 4:	Total time	→	2 h + 6 h
		=	8 h

Step 5:	Average speed	→	520 km ÷ 8 h
		=	65 $\frac{km}{h}$
		≈	65.00 $\frac{km}{h}$

Answer: 67.69 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 70 $\frac{km}{h}$	→	70 $\frac{km}{h}$ x 3 h
		=	210 km

Step 2:	Distance covered at a speed of 40 $\frac{km}{h}$	→	40 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	40 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	10 km

Step 3:	Total distance	→	210 km + 10 km
		=	220 km

Step 4:	Total time	→	3 h + $\frac{1}{4}$ h
		=	3 $\frac{1}{4}$ h

Step 5:	Average speed	→	220 km ÷ 3 $\frac{1}{4}$ h
		=	67.69231 $\frac{km}{h}$
		≈	67.69 $\frac{km}{h}$

10)

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 4 h
		=	220 km

Step 2:	Distance covered at a speed of 70 $\frac{km}{h}$	→	70 $\frac{km}{h}$ x 7 h
		=	490 km

Step 3:	Total distance	→	220 km + 490 km
		=	710 km

Step 4:	Total time	→	4 h + 7 h
		=	11 h

Step 5:	Average speed	→	710 km ÷ 11 h
		=	64.54545 $\frac{km}{h}$
		≈	64.55 $\frac{km}{h}$