Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (645)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Mr Goh drove at 75 $\frac{km}{h}$ for 1h and then slowed down to 48 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Nandini drove the first 2h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 75 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 82 $\frac{km}{h}$ for 2h and then slowed down to 56 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Poongodi drove the first 2h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 70 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 69 $\frac{km}{h}$ for 3h and then slowed down to 48 $\frac{km}{h}$ for the next 45 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Chellamal drove the first 2h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 75 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 73 $\frac{km}{h}$ for 3h and then slowed down to 48 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Ramani drove the first 3h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 70 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 84 $\frac{km}{h}$ for 3h and then slowed down to 48 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

10)

Panimalar drove the first 4h of her journey at 50 $\frac{km}{h.}$
Driving at an average speed of 85 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Answer: 69.60 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 1 h
		=	75 km

Step 2:	Distance covered at a speed of 48 $\frac{km}{h}$	→	48 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	48 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	12 km

Step 3:	Total distance	→	75 km + 12 km
		=	87 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	87 km ÷ 1 $\frac{1}{4}$ h
		=	69.6 $\frac{km}{h}$
		≈	69.60 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 2 h
		=	90 km

Step 2:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 5 h
		=	375 km

Step 3:	Total distance	→	90 km + 375 km
		=	465 km

Step 4:	Total time	→	2 h + 5 h
		=	7 h

Step 5:	Average speed	→	465 km ÷ 7 h
		=	66.42857 $\frac{km}{h}$
		≈	66.43 $\frac{km}{h}$

Answer: 79.11 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 82 $\frac{km}{h}$	→	82 $\frac{km}{h}$ x 2 h
		=	164 km

Step 2:	Distance covered at a speed of 56 $\frac{km}{h}$	→	56 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	56 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	14 km

Step 3:	Total distance	→	164 km + 14 km
		=	178 km

Step 4:	Total time	→	2 h + $\frac{1}{4}$ h
		=	2 $\frac{1}{4}$ h

Step 5:	Average speed	→	178 km ÷ 2 $\frac{1}{4}$ h
		=	79.11111 $\frac{km}{h}$
		≈	79.11 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 2 h
		=	90 km

Step 2:	Distance covered at a speed of 70 $\frac{km}{h}$	→	70 $\frac{km}{h}$ x 6 h
		=	420 km

Step 3:	Total distance	→	90 km + 420 km
		=	510 km

Step 4:	Total time	→	2 h + 6 h
		=	8 h

Step 5:	Average speed	→	510 km ÷ 8 h
		=	63.75 $\frac{km}{h}$
		≈	63.75 $\frac{km}{h}$

Answer: 64.80 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 69 $\frac{km}{h}$	→	69 $\frac{km}{h}$ x 3 h
		=	207 km

Step 2:	Distance covered at a speed of 48 $\frac{km}{h}$	→	48 $\frac{km}{h}$ x $\frac{45}{60}$ h
		=	48 $\frac{km}{h}$ x $\frac{3}{4}$ h
		=	36 km

Step 3:	Total distance	→	207 km + 36 km
		=	243 km

Step 4:	Total time	→	3 h + $\frac{3}{4}$ h
		=	3 $\frac{3}{4}$ h

Step 5:	Average speed	→	243 km ÷ 3 $\frac{3}{4}$ h
		=	64.8 $\frac{km}{h}$
		≈	64.80 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 2 h
		=	90 km

Step 2:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 6 h
		=	450 km

Step 3:	Total distance	→	90 km + 450 km
		=	540 km

Step 4:	Total time	→	2 h + 6 h
		=	8 h

Step 5:	Average speed	→	540 km ÷ 8 h
		=	67.5 $\frac{km}{h}$
		≈	67.50 $\frac{km}{h}$

Answer: 71.08 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 73 $\frac{km}{h}$	→	73 $\frac{km}{h}$ x 3 h
		=	219 km

Step 2:	Distance covered at a speed of 48 $\frac{km}{h}$	→	48 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	48 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	12 km

Step 3:	Total distance	→	219 km + 12 km
		=	231 km

Step 4:	Total time	→	3 h + $\frac{1}{4}$ h
		=	3 $\frac{1}{4}$ h

Step 5:	Average speed	→	231 km ÷ 3 $\frac{1}{4}$ h
		=	71.07692 $\frac{km}{h}$
		≈	71.08 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 3 h
		=	135 km

Step 2:	Distance covered at a speed of 70 $\frac{km}{h}$	→	70 $\frac{km}{h}$ x 7 h
		=	490 km

Step 3:	Total distance	→	135 km + 490 km
		=	625 km

Step 4:	Total time	→	3 h + 7 h
		=	10 h

Step 5:	Average speed	→	625 km ÷ 10 h
		=	62.5 $\frac{km}{h}$
		≈	62.50 $\frac{km}{h}$

Answer: 81.23 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 84 $\frac{km}{h}$	→	84 $\frac{km}{h}$ x 3 h
		=	252 km

Step 2:	Distance covered at a speed of 48 $\frac{km}{h}$	→	48 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	48 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	12 km

Step 3:	Total distance	→	252 km + 12 km
		=	264 km

Step 4:	Total time	→	3 h + $\frac{1}{4}$ h
		=	3 $\frac{1}{4}$ h

Step 5:	Average speed	→	264 km ÷ 3 $\frac{1}{4}$ h
		=	81.23077 $\frac{km}{h}$
		≈	81.23 $\frac{km}{h}$

10)

SOLUTION 1 :

Step 1:	Distance covered at a speed of 50 $\frac{km}{h}$	→	50 $\frac{km}{h}$ x 4 h
		=	200 km

Step 2:	Distance covered at a speed of 85 $\frac{km}{h}$	→	85 $\frac{km}{h}$ x 7 h
		=	595 km

Step 3:	Total distance	→	200 km + 595 km
		=	795 km

Step 4:	Total time	→	4 h + 7 h
		=	11 h

Step 5:	Average speed	→	795 km ÷ 11 h
		=	72.27273 $\frac{km}{h}$
		≈	72.27 $\frac{km}{h}$