Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (645)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Mr Goh drove at 71 $\frac{km}{h}$ for 3h and then slowed down to 44 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Poongodi drove the first 3h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 85 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 67 $\frac{km}{h}$ for 1h and then slowed down to 52 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Parveen drove the first 3h of her journey at 45 $\frac{km}{h.}$
Driving at an average speed of 70 $\frac{km}{h}$ , it took her another 5h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 73 $\frac{km}{h}$ for 4h and then slowed down to 48 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Poongodi drove the first 4h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 75 $\frac{km}{h}$ , it took her another 6h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 78 $\frac{km}{h}$ for 4h and then slowed down to 52 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

Haritha drove the first 4h of her journey at 55 $\frac{km}{h.}$
Driving at an average speed of 80 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Mr Goh drove at 73 $\frac{km}{h}$ for 2h and then slowed down to 56 $\frac{km}{h}$ for the next 15 min. What was his average speed for the journey Express your answer corrected to the nearest 2 decimal places.

$\frac{km}{h}$

Answer:_______________

10)

Pavi drove the first 3h of her journey at 50 $\frac{km}{h.}$
Driving at an average speed of 85 $\frac{km}{h}$ , it took her another 7h to complete the remaining journey.
Find the average speed. Express your answer corrected to the nearest 2 decimal places.
$\frac{km}{h}$

Answer:_______________

Answer: 68.92 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 71 $\frac{km}{h}$	→	71 $\frac{km}{h}$ x 3 h
		=	213 km

Step 2:	Distance covered at a speed of 44 $\frac{km}{h}$	→	44 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	44 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	11 km

Step 3:	Total distance	→	213 km + 11 km
		=	224 km

Step 4:	Total time	→	3 h + $\frac{1}{4}$ h
		=	3 $\frac{1}{4}$ h

Step 5:	Average speed	→	224 km ÷ 3 $\frac{1}{4}$ h
		=	68.92308 $\frac{km}{h}$
		≈	68.92 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 3 h
		=	135 km

Step 2:	Distance covered at a speed of 85 $\frac{km}{h}$	→	85 $\frac{km}{h}$ x 5 h
		=	425 km

Step 3:	Total distance	→	135 km + 425 km
		=	560 km

Step 4:	Total time	→	3 h + 5 h
		=	8 h

Step 5:	Average speed	→	560 km ÷ 8 h
		=	70 $\frac{km}{h}$
		≈	70.00 $\frac{km}{h}$

Answer: 64.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 67 $\frac{km}{h}$	→	67 $\frac{km}{h}$ x 1 h
		=	67 km

Step 2:	Distance covered at a speed of 52 $\frac{km}{h}$	→	52 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	52 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	13 km

Step 3:	Total distance	→	67 km + 13 km
		=	80 km

Step 4:	Total time	→	1 h + $\frac{1}{4}$ h
		=	1 $\frac{1}{4}$ h

Step 5:	Average speed	→	80 km ÷ 1 $\frac{1}{4}$ h
		=	64 $\frac{km}{h}$
		≈	64.00 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 45 $\frac{km}{h}$	→	45 $\frac{km}{h}$ x 3 h
		=	135 km

Step 2:	Distance covered at a speed of 70 $\frac{km}{h}$	→	70 $\frac{km}{h}$ x 5 h
		=	350 km

Step 3:	Total distance	→	135 km + 350 km
		=	485 km

Step 4:	Total time	→	3 h + 5 h
		=	8 h

Step 5:	Average speed	→	485 km ÷ 8 h
		=	60.625 $\frac{km}{h}$
		≈	60.63 $\frac{km}{h}$

Answer: 71.53 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 73 $\frac{km}{h}$	→	73 $\frac{km}{h}$ x 4 h
		=	292 km

Step 2:	Distance covered at a speed of 48 $\frac{km}{h}$	→	48 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	48 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	12 km

Step 3:	Total distance	→	292 km + 12 km
		=	304 km

Step 4:	Total time	→	4 h + $\frac{1}{4}$ h
		=	4 $\frac{1}{4}$ h

Step 5:	Average speed	→	304 km ÷ 4 $\frac{1}{4}$ h
		=	71.52941 $\frac{km}{h}$
		≈	71.53 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 4 h
		=	220 km

Step 2:	Distance covered at a speed of 75 $\frac{km}{h}$	→	75 $\frac{km}{h}$ x 6 h
		=	450 km

Step 3:	Total distance	→	220 km + 450 km
		=	670 km

Step 4:	Total time	→	4 h + 6 h
		=	10 h

Step 5:	Average speed	→	670 km ÷ 10 h
		=	67 $\frac{km}{h}$
		≈	67.00 $\frac{km}{h}$

Answer: 76.47 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 78 $\frac{km}{h}$	→	78 $\frac{km}{h}$ x 4 h
		=	312 km

Step 2:	Distance covered at a speed of 52 $\frac{km}{h}$	→	52 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	52 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	13 km

Step 3:	Total distance	→	312 km + 13 km
		=	325 km

Step 4:	Total time	→	4 h + $\frac{1}{4}$ h
		=	4 $\frac{1}{4}$ h

Step 5:	Average speed	→	325 km ÷ 4 $\frac{1}{4}$ h
		=	76.47059 $\frac{km}{h}$
		≈	76.47 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 55 $\frac{km}{h}$	→	55 $\frac{km}{h}$ x 4 h
		=	220 km

Step 2:	Distance covered at a speed of 80 $\frac{km}{h}$	→	80 $\frac{km}{h}$ x 7 h
		=	560 km

Step 3:	Total distance	→	220 km + 560 km
		=	780 km

Step 4:	Total time	→	4 h + 7 h
		=	11 h

Step 5:	Average speed	→	780 km ÷ 11 h
		=	70.90909 $\frac{km}{h}$
		≈	70.91 $\frac{km}{h}$

Answer: 71.11 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Distance covered at a speed of 73 $\frac{km}{h}$	→	73 $\frac{km}{h}$ x 2 h
		=	146 km

Step 2:	Distance covered at a speed of 56 $\frac{km}{h}$	→	56 $\frac{km}{h}$ x $\frac{15}{60}$ h
		=	56 $\frac{km}{h}$ x $\frac{1}{4}$ h
		=	14 km

Step 3:	Total distance	→	146 km + 14 km
		=	160 km

Step 4:	Total time	→	2 h + $\frac{1}{4}$ h
		=	2 $\frac{1}{4}$ h

Step 5:	Average speed	→	160 km ÷ 2 $\frac{1}{4}$ h
		=	71.11111 $\frac{km}{h}$
		≈	71.11 $\frac{km}{h}$

10)

SOLUTION 1 :

Step 1:	Distance covered at a speed of 50 $\frac{km}{h}$	→	50 $\frac{km}{h}$ x 3 h
		=	150 km

Step 2:	Distance covered at a speed of 85 $\frac{km}{h}$	→	85 $\frac{km}{h}$ x 7 h
		=	595 km

Step 3:	Total distance	→	150 km + 595 km
		=	745 km

Step 4:	Total time	→	3 h + 7 h
		=	10 h

Step 5:	Average speed	→	745 km ÷ 10 h
		=	74.5 $\frac{km}{h}$
		≈	74.50 $\frac{km}{h}$