Sasi Math (Revised for 1024)

Scroll:Measurement >> Area of Triangle >> ps (1315)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

The figure below is made up of 6 squares of side 5cm each.

Find on the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 12cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 4 squares of side 3cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 9cm each.

Find on the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 2cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 4 squares of side 6cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 4cm each.

Find on the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 4cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 4 squares of side 7cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

10)

The figure below is made up of 6 squares of side 2cm each.

Find on the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 5cm each.

Find on the area of the shaded parts.

Answer: 25cm²

SOLUTION 1 :

5cm

5cm

Step 1: Length of AB → 5cm + 5cm = 10cm

Step 2: Height of BC → 5cm + 5cm + 5cm = 15cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 10cm x 15cm = 75cm²

Height of FG = Length of AB

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 10cm x 10cm = 50cm²

Step 5: Area of shaded parts → 75cm² - 50cm² = 25cm²

The figure below is made up of 6 squares of side 12cm each.

Find the area of the shaded parts.

Answer: 288cm²

SOLUTION 1 :

12cm

12cm

Step 1: Length of AB → 12cm + 12cm = 24cm

Step 2: Height of BC → 12cm + 12cm + 12cm = 36cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 24cm x 36cm = 432cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 24cm x 12cm = 144cm²

Step 5: Area of shaded parts → 432cm² - 144cm² = 288cm²

The figure below is made up of 4 squares of side 3cm each.

Find the area of the shaded parts.

Answer: 9cm²

SOLUTION 1 :

3cm

3cm

Step 1: Length of AB → 3cm + 3cm = 6cm

Step 2: Height of DC → 3cm + 3cm = 6cm

Step 3: Area of triangle ADE → $\frac{1}{2}$ x 6cm x 3cm = 9cm²

Height of FG = Length of AD

Step 4: Area of triangle ADF → $\frac{1}{2}$ x 6cm x 6cm = 18cm²

Step 5: Area of shaded parts → 18cm² - 9cm² = 9cm²

The figure below is made up of 6 squares of side 9cm each.

Find on the area of the shaded parts.

Answer: 81cm²

SOLUTION 1 :

9cm

9cm

Step 1: Length of AB → 9cm + 9cm = 18cm

Step 2: Height of BC → 9cm + 9cm + 9cm = 27cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 18cm x 27cm = 243cm²

Height of FG = Length of AB

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 18cm x 18cm = 162cm²

Step 5: Area of shaded parts → 243cm² - 162cm² = 81cm²

The figure below is made up of 6 squares of side 2cm each.

Find the area of the shaded parts.

Answer: 8cm²

SOLUTION 1 :

2cm

2cm

Step 1: Length of AB → 2cm + 2cm = 4cm

Step 2: Height of BC → 2cm + 2cm + 2cm = 6cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 4cm x 6cm = 12cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 4cm x 2cm = 4cm²

Step 5: Area of shaded parts → 12cm² - 4cm² = 8cm²

The figure below is made up of 4 squares of side 6cm each.

Find the area of the shaded parts.

Answer: 36cm²

SOLUTION 1 :

6cm

6cm

Step 1: Length of AB → 6cm + 6cm = 12cm

Step 2: Height of DC → 6cm + 6cm = 12cm

Step 3: Area of triangle ADE → $\frac{1}{2}$ x 12cm x 6cm = 36cm²

Height of FG = Length of AD

Step 4: Area of triangle ADF → $\frac{1}{2}$ x 12cm x 12cm = 72cm²

Step 5: Area of shaded parts → 72cm² - 36cm² = 36cm²

The figure below is made up of 6 squares of side 4cm each.

Find on the area of the shaded parts.

Answer: 16cm²

SOLUTION 1 :

4cm

4cm

Step 1: Length of AB → 4cm + 4cm = 8cm

Step 2: Height of BC → 4cm + 4cm + 4cm = 12cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 8cm x 12cm = 48cm²

Height of FG = Length of AB

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 8cm x 8cm = 32cm²

Step 5: Area of shaded parts → 48cm² - 32cm² = 16cm²

The figure below is made up of 6 squares of side 4cm each.

Find the area of the shaded parts.

Answer: 32cm²

SOLUTION 1 :

4cm

4cm

Step 1: Length of AB → 4cm + 4cm = 8cm

Step 2: Height of BC → 4cm + 4cm + 4cm = 12cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 8cm x 12cm = 48cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 8cm x 4cm = 16cm²

Step 5: Area of shaded parts → 48cm² - 16cm² = 32cm²

The figure below is made up of 4 squares of side 7cm each.

Find the area of the shaded parts.

Answer: 49cm²

SOLUTION 1 :

7cm

7cm

Step 1: Length of AB → 7cm + 7cm = 14cm

Step 2: Height of DC → 7cm + 7cm = 14cm

Step 3: Area of triangle ADE → $\frac{1}{2}$ x 14cm x 7cm = 49cm²

Height of FG = Length of AD

Step 4: Area of triangle ADF → $\frac{1}{2}$ x 14cm x 14cm = 98cm²

Step 5: Area of shaded parts → 98cm² - 49cm² = 49cm²

10)

The figure below is made up of 6 squares of side 2cm each.

Find on the area of the shaded parts.

Answer: 4cm²

SOLUTION 1 :

2cm

2cm

Step 1: Length of AB → 2cm + 2cm = 4cm

Step 2: Height of BC → 2cm + 2cm + 2cm = 6cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 4cm x 6cm = 12cm²

Height of FG = Length of AB

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 4cm x 4cm = 8cm²

Step 5: Area of shaded parts → 12cm² - 8cm² = 4cm²