Sasi Math (Revised for 1024)

Scroll:Measurement >> Area of Triangle >> ps (1315)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

The figure below is made up of 6 squares of side 11cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 12cm each.

Find on the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 4 squares of side 2cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 12cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 7cm each.

Find on the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 4 squares of side 8cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 6cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 2cm each.

Find on the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 4 squares of side 10cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

10)

The figure below is made up of 6 squares of side 5cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 11cm each.

Find the area of the shaded parts.

Answer: 242cm²

SOLUTION 1 :

11cm

11cm

Step 1: Length of AB → 11cm + 11cm = 22cm

Step 2: Height of BC → 11cm + 11cm + 11cm = 33cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 22cm x 33cm = 363cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 22cm x 11cm = 121cm²

Step 5: Area of shaded parts → 363cm² - 121cm² = 242cm²

The figure below is made up of 6 squares of side 12cm each.

Find on the area of the shaded parts.

Answer: 144cm²

SOLUTION 1 :

12cm

12cm

Step 1: Length of AB → 12cm + 12cm = 24cm

Step 2: Height of BC → 12cm + 12cm + 12cm = 36cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 24cm x 36cm = 432cm²

Height of FG = Length of AB

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 24cm x 24cm = 288cm²

Step 5: Area of shaded parts → 432cm² - 288cm² = 144cm²

The figure below is made up of 4 squares of side 2cm each.

Find the area of the shaded parts.

Answer: 4cm²

SOLUTION 1 :

2cm

2cm

Step 1: Length of AB → 2cm + 2cm = 4cm

Step 2: Height of DC → 2cm + 2cm = 4cm

Step 3: Area of triangle ADE → $\frac{1}{2}$ x 4cm x 2cm = 4cm²

Height of FG = Length of AD

Step 4: Area of triangle ADF → $\frac{1}{2}$ x 4cm x 4cm = 8cm²

Step 5: Area of shaded parts → 8cm² - 4cm² = 4cm²

The figure below is made up of 6 squares of side 12cm each.

Find the area of the shaded parts.

Answer: 288cm²

SOLUTION 1 :

12cm

12cm

Step 1: Length of AB → 12cm + 12cm = 24cm

Step 2: Height of BC → 12cm + 12cm + 12cm = 36cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 24cm x 36cm = 432cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 24cm x 12cm = 144cm²

Step 5: Area of shaded parts → 432cm² - 144cm² = 288cm²

The figure below is made up of 6 squares of side 7cm each.

Find on the area of the shaded parts.

Answer: 49cm²

SOLUTION 1 :

7cm

7cm

Step 1: Length of AB → 7cm + 7cm = 14cm

Step 2: Height of BC → 7cm + 7cm + 7cm = 21cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 14cm x 21cm = 147cm²

Height of FG = Length of AB

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 14cm x 14cm = 98cm²

Step 5: Area of shaded parts → 147cm² - 98cm² = 49cm²

The figure below is made up of 4 squares of side 8cm each.

Find the area of the shaded parts.

Answer: 64cm²

SOLUTION 1 :

8cm

8cm

Step 1: Length of AB → 8cm + 8cm = 16cm

Step 2: Height of DC → 8cm + 8cm = 16cm

Step 3: Area of triangle ADE → $\frac{1}{2}$ x 16cm x 8cm = 64cm²

Height of FG = Length of AD

Step 4: Area of triangle ADF → $\frac{1}{2}$ x 16cm x 16cm = 128cm²

Step 5: Area of shaded parts → 128cm² - 64cm² = 64cm²

The figure below is made up of 6 squares of side 6cm each.

Find the area of the shaded parts.

Answer: 72cm²

SOLUTION 1 :

6cm

6cm

Step 1: Length of AB → 6cm + 6cm = 12cm

Step 2: Height of BC → 6cm + 6cm + 6cm = 18cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 12cm x 18cm = 108cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 12cm x 6cm = 36cm²

Step 5: Area of shaded parts → 108cm² - 36cm² = 72cm²

The figure below is made up of 6 squares of side 2cm each.

Find on the area of the shaded parts.

Answer: 4cm²

SOLUTION 1 :

2cm

2cm

Step 1: Length of AB → 2cm + 2cm = 4cm

Step 2: Height of BC → 2cm + 2cm + 2cm = 6cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 4cm x 6cm = 12cm²

Height of FG = Length of AB

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 4cm x 4cm = 8cm²

Step 5: Area of shaded parts → 12cm² - 8cm² = 4cm²

The figure below is made up of 4 squares of side 10cm each.

Find the area of the shaded parts.

Answer: 100cm²

SOLUTION 1 :

10cm

10cm

Step 1: Length of AB → 10cm + 10cm = 20cm

Step 2: Height of DC → 10cm + 10cm = 20cm

Step 3: Area of triangle ADE → $\frac{1}{2}$ x 20cm x 10cm = 100cm²

Height of FG = Length of AD

Step 4: Area of triangle ADF → $\frac{1}{2}$ x 20cm x 20cm = 200cm²

Step 5: Area of shaded parts → 200cm² - 100cm² = 100cm²

10)

The figure below is made up of 6 squares of side 5cm each.

Find the area of the shaded parts.

Answer: 50cm²

SOLUTION 1 :

5cm

5cm

Step 1: Length of AB → 5cm + 5cm = 10cm

Step 2: Height of BC → 5cm + 5cm + 5cm = 15cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 10cm x 15cm = 75cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 10cm x 5cm = 25cm²

Step 5: Area of shaded parts → 75cm² - 25cm² = 50cm²