Sasi Math (Revised for 1024)

Scroll:Measurement >> Area of Triangle >> ps (1315)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

The figure below is made up of 6 squares of side 7cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 4 squares of side 5cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 10cm each.

Find on the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 10cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 4 squares of side 3cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 6cm each.

Find on the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 11cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 4 squares of side 7cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 3cm each.

Find on the area of the shaded parts.

___cm²

Answer:_______________

10)

The figure below is made up of 6 squares of side 2cm each.

Find the area of the shaded parts.

___cm²

Answer:_______________

The figure below is made up of 6 squares of side 7cm each.

Find the area of the shaded parts.

Answer: 98cm²

SOLUTION 1 :

7cm

7cm

Step 1: Length of AB → 7cm + 7cm = 14cm

Step 2: Height of BC → 7cm + 7cm + 7cm = 21cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 14cm x 21cm = 147cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 14cm x 7cm = 49cm²

Step 5: Area of shaded parts → 147cm² - 49cm² = 98cm²

The figure below is made up of 4 squares of side 5cm each.

Find the area of the shaded parts.

Answer: 25cm²

SOLUTION 1 :

5cm

5cm

Step 1: Length of AB → 5cm + 5cm = 10cm

Step 2: Height of DC → 5cm + 5cm = 10cm

Step 3: Area of triangle ADE → $\frac{1}{2}$ x 10cm x 5cm = 25cm²

Height of FG = Length of AD

Step 4: Area of triangle ADF → $\frac{1}{2}$ x 10cm x 10cm = 50cm²

Step 5: Area of shaded parts → 50cm² - 25cm² = 25cm²

The figure below is made up of 6 squares of side 10cm each.

Find on the area of the shaded parts.

Answer: 100cm²

SOLUTION 1 :

10cm

10cm

Step 1: Length of AB → 10cm + 10cm = 20cm

Step 2: Height of BC → 10cm + 10cm + 10cm = 30cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 20cm x 30cm = 300cm²

Height of FG = Length of AB

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 20cm x 20cm = 200cm²

Step 5: Area of shaded parts → 300cm² - 200cm² = 100cm²

The figure below is made up of 6 squares of side 10cm each.

Find the area of the shaded parts.

Answer: 200cm²

SOLUTION 1 :

10cm

10cm

Step 1: Length of AB → 10cm + 10cm = 20cm

Step 2: Height of BC → 10cm + 10cm + 10cm = 30cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 20cm x 30cm = 300cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 20cm x 10cm = 100cm²

Step 5: Area of shaded parts → 300cm² - 100cm² = 200cm²

The figure below is made up of 4 squares of side 3cm each.

Find the area of the shaded parts.

Answer: 9cm²

SOLUTION 1 :

3cm

3cm

Step 1: Length of AB → 3cm + 3cm = 6cm

Step 2: Height of DC → 3cm + 3cm = 6cm

Step 3: Area of triangle ADE → $\frac{1}{2}$ x 6cm x 3cm = 9cm²

Height of FG = Length of AD

Step 4: Area of triangle ADF → $\frac{1}{2}$ x 6cm x 6cm = 18cm²

Step 5: Area of shaded parts → 18cm² - 9cm² = 9cm²

The figure below is made up of 6 squares of side 6cm each.

Find on the area of the shaded parts.

Answer: 36cm²

SOLUTION 1 :

6cm

6cm

Step 1: Length of AB → 6cm + 6cm = 12cm

Step 2: Height of BC → 6cm + 6cm + 6cm = 18cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 12cm x 18cm = 108cm²

Height of FG = Length of AB

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 12cm x 12cm = 72cm²

Step 5: Area of shaded parts → 108cm² - 72cm² = 36cm²

The figure below is made up of 6 squares of side 11cm each.

Find the area of the shaded parts.

Answer: 242cm²

SOLUTION 1 :

11cm

11cm

Step 1: Length of AB → 11cm + 11cm = 22cm

Step 2: Height of BC → 11cm + 11cm + 11cm = 33cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 22cm x 33cm = 363cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 22cm x 11cm = 121cm²

Step 5: Area of shaded parts → 363cm² - 121cm² = 242cm²

The figure below is made up of 4 squares of side 7cm each.

Find the area of the shaded parts.

Answer: 49cm²

SOLUTION 1 :

7cm

7cm

Step 1: Length of AB → 7cm + 7cm = 14cm

Step 2: Height of DC → 7cm + 7cm = 14cm

Step 3: Area of triangle ADE → $\frac{1}{2}$ x 14cm x 7cm = 49cm²

Height of FG = Length of AD

Step 4: Area of triangle ADF → $\frac{1}{2}$ x 14cm x 14cm = 98cm²

Step 5: Area of shaded parts → 98cm² - 49cm² = 49cm²

The figure below is made up of 6 squares of side 3cm each.

Find on the area of the shaded parts.

Answer: 9cm²

SOLUTION 1 :

3cm

3cm

Step 1: Length of AB → 3cm + 3cm = 6cm

Step 2: Height of BC → 3cm + 3cm + 3cm = 9cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 6cm x 9cm = 27cm²

Height of FG = Length of AB

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 6cm x 6cm = 18cm²

Step 5: Area of shaded parts → 27cm² - 18cm² = 9cm²

10)

The figure below is made up of 6 squares of side 2cm each.

Find the area of the shaded parts.

Answer: 8cm²

SOLUTION 1 :

2cm

2cm

Step 1: Length of AB → 2cm + 2cm = 4cm

Step 2: Height of BC → 2cm + 2cm + 2cm = 6cm

Step 3: Area of triangle ABE → $\frac{1}{2}$ x 4cm x 6cm = 12cm²

Step 4: Area of triangle ABF → $\frac{1}{2}$ x 4cm x 2cm = 4cm²

Step 5: Area of shaded parts → 12cm² - 4cm² = 8cm²