Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (1770)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Town A and Town B were 646 km apart. At 1045 h Savithri drove from Town A to Town B. At the same time, Sriram drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Savithri and Sriram passed each other at 1530 h. If Savithri was travelling 22 $\frac{km}{h}$ slower than Sriram, find Sriram's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 670 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 26 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 836 km apart. At 1045 h Chithra drove from Town A to Town B. At the same time, Balaji drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Chithra and Balaji passed each other at 1530 h. If Chithra was travelling 12 $\frac{km}{h}$ slower than Balaji, find Balaji's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 740 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 14 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 950 km apart. At 1045 h Thamarai drove from Town A to Town B. At the same time, Kalai drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Thamarai and Kalai passed each other at 1530 h. If Thamarai was travelling 24 $\frac{km}{h}$ slower than Kalai, find Kalai's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 650 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 28 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 646 km apart. At 1045 h Jeevini drove from Town A to Town B. At the same time, Karna drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Jeevini and Karna passed each other at 1530 h. If Jeevini was travelling 18 $\frac{km}{h}$ slower than Karna, find Karna's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 650 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 14 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 684 km apart. At 1045 h Mithra drove from Town A to Town B. At the same time, Narayanan drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Mithra and Narayanan passed each other at 1530 h. If Mithra was travelling 22 $\frac{km}{h}$ slower than Narayanan, find Narayanan's speed.

$\frac{km}{h}$

Answer:_______________

10)

Town Lala and Town Yaya are 690 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 14 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Answer: 79 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	22 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 22 km
		=	104.5 km

Savithri travelled 104.5 km less than Sriram.

Savithri

Sriram

104.5km

Total = 646 km

Step 3: 646 km - 104.5 km = 541.5 km

Step 4:	Distance travelled by Savithri	→	541.5 km ÷ 2
		=	270.75 km

Step 5:	Savithri's speed	→	270.75 km ÷ 4 $\frac{3}{4}$ h
		=	57 $\frac{km}{h}$

Step 6:	Sriram's speed	→	57 $\frac{km}{h}$ + 22 $\frac{km}{h}$
		=	79 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	22 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 22 km
		=	104.5 km

Savithri travelled 104.5 km less than Sriram.

Savithri

Sriram

104.5km

Total = 646 km

Step 3: 646 km - 104.5 km = 541.5 km

Step 4:	Distance travelled by Savithri	→	541.5 km ÷ 2
		=	270.75 km

Step 5:	Distance travelled by Sriram	→	270.75 km + 104.5 km
		=	375.25 km

Step 6:	Sriram's speed	→	375.25 km ÷ 4 $\frac{3}{4}$ h
		=	79 $\frac{km}{h}$

Answer: 80 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	26 km
	5h	→	5 x 26 km
		=	130 km

The lorry travelled 130 km less than the car.

Lorry

Car

130km

Total = 670 km

Step 3: 670 km - 130 km = 540 km

Step 4:	Distance travelled by the lorry	→	540 km ÷ 2
		=	270 km

Step 5:	Distance travelled by the car	→	270 km + 130 km
		=	400 km

Step 6:	Car's speed	→	400 km ÷ 5h
		=	80 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	26 km
	5h	→	5 x 26 km
		=	130 km

The lorry travelled 130 km less than the car.

Lorry

Car

130km

Total = 670 km

Step 3: 670 km - 130 km = 540 km

Step 4:	Distance travelled by the lorry	→	540 km ÷ 2
		=	270 km

Step 5:	Lorry's speed	→	270 km ÷ 5h
		=	54 $\frac{km}{h}$

Step 6:	Car's speed	→	54 $\frac{km}{h}$ + 26 $\frac{km}{h}$
		=	80 $\frac{km}{h}$

Answer: 94 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Chithra travelled 57 km less than Balaji.

Chithra

Balaji

57km

Total = 836 km

Step 3: 836 km - 57 km = 779 km

Step 4:	Distance travelled by Chithra	→	779 km ÷ 2
		=	389.5 km

Step 5:	Chithra's speed	→	389.5 km ÷ 4 $\frac{3}{4}$ h
		=	82 $\frac{km}{h}$

Step 6:	Balaji's speed	→	82 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	94 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Chithra travelled 57 km less than Balaji.

Chithra

Balaji

57km

Total = 836 km

Step 3: 836 km - 57 km = 779 km

Step 4:	Distance travelled by Chithra	→	779 km ÷ 2
		=	389.5 km

Step 5:	Distance travelled by Balaji	→	389.5 km + 57 km
		=	446.5 km

Step 6:	Balaji's speed	→	446.5 km ÷ 4 $\frac{3}{4}$ h
		=	94 $\frac{km}{h}$

Answer: 81 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	14 km
	5h	→	5 x 14 km
		=	70 km

The lorry travelled 70 km less than the car.

Lorry

Car

70km

Total = 740 km

Step 3: 740 km - 70 km = 670 km

Step 4:	Distance travelled by the lorry	→	670 km ÷ 2
		=	335 km

Step 5:	Distance travelled by the car	→	335 km + 70 km
		=	405 km

Step 6:	Car's speed	→	405 km ÷ 5h
		=	81 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	14 km
	5h	→	5 x 14 km
		=	70 km

The lorry travelled 70 km less than the car.

Lorry

Car

70km

Total = 740 km

Step 3: 740 km - 70 km = 670 km

Step 4:	Distance travelled by the lorry	→	670 km ÷ 2
		=	335 km

Step 5:	Lorry's speed	→	335 km ÷ 5h
		=	67 $\frac{km}{h}$

Step 6:	Car's speed	→	67 $\frac{km}{h}$ + 14 $\frac{km}{h}$
		=	81 $\frac{km}{h}$

Answer: 112 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	24 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 24 km
		=	114 km

Thamarai travelled 114 km less than Kalai.

Thamarai

Kalai

114km

Total = 950 km

Step 3: 950 km - 114 km = 836 km

Step 4:	Distance travelled by Thamarai	→	836 km ÷ 2
		=	418 km

Step 5:	Thamarai's speed	→	418 km ÷ 4 $\frac{3}{4}$ h
		=	88 $\frac{km}{h}$

Step 6:	Kalai's speed	→	88 $\frac{km}{h}$ + 24 $\frac{km}{h}$
		=	112 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	24 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 24 km
		=	114 km

Thamarai travelled 114 km less than Kalai.

Thamarai

Kalai

114km

Total = 950 km

Step 3: 950 km - 114 km = 836 km

Step 4:	Distance travelled by Thamarai	→	836 km ÷ 2
		=	418 km

Step 5:	Distance travelled by Kalai	→	418 km + 114 km
		=	532 km

Step 6:	Kalai's speed	→	532 km ÷ 4 $\frac{3}{4}$ h
		=	112 $\frac{km}{h}$

Answer: 79 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	28 km
	5h	→	5 x 28 km
		=	140 km

The lorry travelled 140 km less than the car.

Lorry

Car

140km

Total = 650 km

Step 3: 650 km - 140 km = 510 km

Step 4:	Distance travelled by the lorry	→	510 km ÷ 2
		=	255 km

Step 5:	Distance travelled by the car	→	255 km + 140 km
		=	395 km

Step 6:	Car's speed	→	395 km ÷ 5h
		=	79 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	28 km
	5h	→	5 x 28 km
		=	140 km

The lorry travelled 140 km less than the car.

Lorry

Car

140km

Total = 650 km

Step 3: 650 km - 140 km = 510 km

Step 4:	Distance travelled by the lorry	→	510 km ÷ 2
		=	255 km

Step 5:	Lorry's speed	→	255 km ÷ 5h
		=	51 $\frac{km}{h}$

Step 6:	Car's speed	→	51 $\frac{km}{h}$ + 28 $\frac{km}{h}$
		=	79 $\frac{km}{h}$

Answer: 77 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	18 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 18 km
		=	85.5 km

Jeevini travelled 85.5 km less than Karna.

Jeevini

Karna

85.5km

Total = 646 km

Step 3: 646 km - 85.5 km = 560.5 km

Step 4:	Distance travelled by Jeevini	→	560.5 km ÷ 2
		=	280.25 km

Step 5:	Jeevini's speed	→	280.25 km ÷ 4 $\frac{3}{4}$ h
		=	59 $\frac{km}{h}$

Step 6:	Karna's speed	→	59 $\frac{km}{h}$ + 18 $\frac{km}{h}$
		=	77 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	18 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 18 km
		=	85.5 km

Jeevini travelled 85.5 km less than Karna.

Jeevini

Karna

85.5km

Total = 646 km

Step 3: 646 km - 85.5 km = 560.5 km

Step 4:	Distance travelled by Jeevini	→	560.5 km ÷ 2
		=	280.25 km

Step 5:	Distance travelled by Karna	→	280.25 km + 85.5 km
		=	365.75 km

Step 6:	Karna's speed	→	365.75 km ÷ 4 $\frac{3}{4}$ h
		=	77 $\frac{km}{h}$

Town Lala and Town Yaya are 650 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 14 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

Answer: 72 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	14 km
	5h	→	5 x 14 km
		=	70 km

The lorry travelled 70 km less than the car.

Lorry

Car

70km

Total = 650 km

Step 3: 650 km - 70 km = 580 km

Step 4:	Distance travelled by the lorry	→	580 km ÷ 2
		=	290 km

Step 5:	Distance travelled by the car	→	290 km + 70 km
		=	360 km

Step 6:	Car's speed	→	360 km ÷ 5h
		=	72 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	14 km
	5h	→	5 x 14 km
		=	70 km

The lorry travelled 70 km less than the car.

Lorry

Car

70km

Total = 650 km

Step 3: 650 km - 70 km = 580 km

Step 4:	Distance travelled by the lorry	→	580 km ÷ 2
		=	290 km

Step 5:	Lorry's speed	→	290 km ÷ 5h
		=	58 $\frac{km}{h}$

Step 6:	Car's speed	→	58 $\frac{km}{h}$ + 14 $\frac{km}{h}$
		=	72 $\frac{km}{h}$

Answer: 83 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	22 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 22 km
		=	104.5 km

Mithra travelled 104.5 km less than Narayanan.

Mithra

Narayanan

104.5km

Total = 684 km

Step 3: 684 km - 104.5 km = 579.5 km

Step 4:	Distance travelled by Mithra	→	579.5 km ÷ 2
		=	289.75 km

Step 5:	Mithra's speed	→	289.75 km ÷ 4 $\frac{3}{4}$ h
		=	61 $\frac{km}{h}$

Step 6:	Narayanan's speed	→	61 $\frac{km}{h}$ + 22 $\frac{km}{h}$
		=	83 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	22 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 22 km
		=	104.5 km

Mithra travelled 104.5 km less than Narayanan.

Mithra

Narayanan

104.5km

Total = 684 km

Step 3: 684 km - 104.5 km = 579.5 km

Step 4:	Distance travelled by Mithra	→	579.5 km ÷ 2
		=	289.75 km

Step 5:	Distance travelled by Narayanan	→	289.75 km + 104.5 km
		=	394.25 km

Step 6:	Narayanan's speed	→	394.25 km ÷ 4 $\frac{3}{4}$ h
		=	83 $\frac{km}{h}$

10)

Answer: 76 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	14 km
	5h	→	5 x 14 km
		=	70 km

The lorry travelled 70 km less than the car.

Lorry

Car

70km

Total = 690 km

Step 3: 690 km - 70 km = 620 km

Step 4:	Distance travelled by the lorry	→	620 km ÷ 2
		=	310 km

Step 5:	Distance travelled by the car	→	310 km + 70 km
		=	380 km

Step 6:	Car's speed	→	380 km ÷ 5h
		=	76 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	14 km
	5h	→	5 x 14 km
		=	70 km

The lorry travelled 70 km less than the car.

Lorry

Car

70km

Total = 690 km

Step 3: 690 km - 70 km = 620 km

Step 4:	Distance travelled by the lorry	→	620 km ÷ 2
		=	310 km

Step 5:	Lorry's speed	→	310 km ÷ 5h
		=	62 $\frac{km}{h}$

Step 6:	Car's speed	→	62 $\frac{km}{h}$ + 14 $\frac{km}{h}$
		=	76 $\frac{km}{h}$