Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (1770)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Town Lala and Town Yaya are 650 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 26 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 912 km apart. At 1045 h Selvanayaki drove from Town A to Town B. At the same time, Barathan drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Selvanayaki and Barathan passed each other at 1530 h. If Selvanayaki was travelling 12 $\frac{km}{h}$ slower than Barathan, find Barathan's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 720 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 18 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 608 km apart. At 1045 h Chithra drove from Town A to Town B. At the same time, Anand drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Chithra and Anand passed each other at 1530 h. If Chithra was travelling 14 $\frac{km}{h}$ slower than Anand, find Anand's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 700 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 20 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 874 km apart. At 1045 h Chellamal drove from Town A to Town B. At the same time, Kalai drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Chellamal and Kalai passed each other at 1530 h. If Chellamal was travelling 12 $\frac{km}{h}$ slower than Kalai, find Kalai's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 740 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 16 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 684 km apart. At 1045 h Panimalar drove from Town A to Town B. At the same time, Aravindh drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Panimalar and Aravindh passed each other at 1530 h. If Panimalar was travelling 20 $\frac{km}{h}$ slower than Aravindh, find Aravindh's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 700 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 12 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

10)

Town A and Town B were 722 km apart. At 1045 h Nandini drove from Town A to Town B. At the same time, Kumar drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Nandini and Kumar passed each other at 1530 h. If Nandini was travelling 12 $\frac{km}{h}$ slower than Kumar, find Kumar's speed.

$\frac{km}{h}$

Answer:_______________

Answer: 78 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	26 km
	5h	→	5 x 26 km
		=	130 km

The lorry travelled 130 km less than the car.

Lorry

Car

130km

Total = 650 km

Step 3: 650 km - 130 km = 520 km

Step 4:	Distance travelled by the lorry	→	520 km ÷ 2
		=	260 km

Step 5:	Distance travelled by the car	→	260 km + 130 km
		=	390 km

Step 6:	Car's speed	→	390 km ÷ 5h
		=	78 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	26 km
	5h	→	5 x 26 km
		=	130 km

The lorry travelled 130 km less than the car.

Lorry

Car

130km

Total = 650 km

Step 3: 650 km - 130 km = 520 km

Step 4:	Distance travelled by the lorry	→	520 km ÷ 2
		=	260 km

Step 5:	Lorry's speed	→	260 km ÷ 5h
		=	52 $\frac{km}{h}$

Step 6:	Car's speed	→	52 $\frac{km}{h}$ + 26 $\frac{km}{h}$
		=	78 $\frac{km}{h}$

Answer: 102 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Selvanayaki travelled 57 km less than Barathan.

Selvanayaki

Barathan

57km

Total = 912 km

Step 3: 912 km - 57 km = 855 km

Step 4:	Distance travelled by Selvanayaki	→	855 km ÷ 2
		=	427.5 km

Step 5:	Selvanayaki's speed	→	427.5 km ÷ 4 $\frac{3}{4}$ h
		=	90 $\frac{km}{h}$

Step 6:	Barathan's speed	→	90 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	102 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Selvanayaki travelled 57 km less than Barathan.

Selvanayaki

Barathan

57km

Total = 912 km

Step 3: 912 km - 57 km = 855 km

Step 4:	Distance travelled by Selvanayaki	→	855 km ÷ 2
		=	427.5 km

Step 5:	Distance travelled by Barathan	→	427.5 km + 57 km
		=	484.5 km

Step 6:	Barathan's speed	→	484.5 km ÷ 4 $\frac{3}{4}$ h
		=	102 $\frac{km}{h}$

Answer: 81 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	18 km
	5h	→	5 x 18 km
		=	90 km

The lorry travelled 90 km less than the car.

Lorry

Car

90km

Total = 720 km

Step 3: 720 km - 90 km = 630 km

Step 4:	Distance travelled by the lorry	→	630 km ÷ 2
		=	315 km

Step 5:	Distance travelled by the car	→	315 km + 90 km
		=	405 km

Step 6:	Car's speed	→	405 km ÷ 5h
		=	81 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	18 km
	5h	→	5 x 18 km
		=	90 km

The lorry travelled 90 km less than the car.

Lorry

Car

90km

Total = 720 km

Step 3: 720 km - 90 km = 630 km

Step 4:	Distance travelled by the lorry	→	630 km ÷ 2
		=	315 km

Step 5:	Lorry's speed	→	315 km ÷ 5h
		=	63 $\frac{km}{h}$

Step 6:	Car's speed	→	63 $\frac{km}{h}$ + 18 $\frac{km}{h}$
		=	81 $\frac{km}{h}$

Answer: 71 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	14 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 14 km
		=	66.5 km

Chithra travelled 66.5 km less than Anand.

Chithra

Anand

66.5km

Total = 608 km

Step 3: 608 km - 66.5 km = 541.5 km

Step 4:	Distance travelled by Chithra	→	541.5 km ÷ 2
		=	270.75 km

Step 5:	Chithra's speed	→	270.75 km ÷ 4 $\frac{3}{4}$ h
		=	57 $\frac{km}{h}$

Step 6:	Anand's speed	→	57 $\frac{km}{h}$ + 14 $\frac{km}{h}$
		=	71 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	14 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 14 km
		=	66.5 km

Chithra travelled 66.5 km less than Anand.

Chithra

Anand

66.5km

Total = 608 km

Step 3: 608 km - 66.5 km = 541.5 km

Step 4:	Distance travelled by Chithra	→	541.5 km ÷ 2
		=	270.75 km

Step 5:	Distance travelled by Anand	→	270.75 km + 66.5 km
		=	337.25 km

Step 6:	Anand's speed	→	337.25 km ÷ 4 $\frac{3}{4}$ h
		=	71 $\frac{km}{h}$

Answer: 80 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	20 km
	5h	→	5 x 20 km
		=	100 km

The lorry travelled 100 km less than the car.

Lorry

Car

100km

Total = 700 km

Step 3: 700 km - 100 km = 600 km

Step 4:	Distance travelled by the lorry	→	600 km ÷ 2
		=	300 km

Step 5:	Distance travelled by the car	→	300 km + 100 km
		=	400 km

Step 6:	Car's speed	→	400 km ÷ 5h
		=	80 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	20 km
	5h	→	5 x 20 km
		=	100 km

The lorry travelled 100 km less than the car.

Lorry

Car

100km

Total = 700 km

Step 3: 700 km - 100 km = 600 km

Step 4:	Distance travelled by the lorry	→	600 km ÷ 2
		=	300 km

Step 5:	Lorry's speed	→	300 km ÷ 5h
		=	60 $\frac{km}{h}$

Step 6:	Car's speed	→	60 $\frac{km}{h}$ + 20 $\frac{km}{h}$
		=	80 $\frac{km}{h}$

Answer: 98 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Chellamal travelled 57 km less than Kalai.

Chellamal

Kalai

57km

Total = 874 km

Step 3: 874 km - 57 km = 817 km

Step 4:	Distance travelled by Chellamal	→	817 km ÷ 2
		=	408.5 km

Step 5:	Chellamal's speed	→	408.5 km ÷ 4 $\frac{3}{4}$ h
		=	86 $\frac{km}{h}$

Step 6:	Kalai's speed	→	86 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	98 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Chellamal travelled 57 km less than Kalai.

Chellamal

Kalai

57km

Total = 874 km

Step 3: 874 km - 57 km = 817 km

Step 4:	Distance travelled by Chellamal	→	817 km ÷ 2
		=	408.5 km

Step 5:	Distance travelled by Kalai	→	408.5 km + 57 km
		=	465.5 km

Step 6:	Kalai's speed	→	465.5 km ÷ 4 $\frac{3}{4}$ h
		=	98 $\frac{km}{h}$

Answer: 82 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	16 km
	5h	→	5 x 16 km
		=	80 km

The lorry travelled 80 km less than the car.

Lorry

Car

80km

Total = 740 km

Step 3: 740 km - 80 km = 660 km

Step 4:	Distance travelled by the lorry	→	660 km ÷ 2
		=	330 km

Step 5:	Distance travelled by the car	→	330 km + 80 km
		=	410 km

Step 6:	Car's speed	→	410 km ÷ 5h
		=	82 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	16 km
	5h	→	5 x 16 km
		=	80 km

The lorry travelled 80 km less than the car.

Lorry

Car

80km

Total = 740 km

Step 3: 740 km - 80 km = 660 km

Step 4:	Distance travelled by the lorry	→	660 km ÷ 2
		=	330 km

Step 5:	Lorry's speed	→	330 km ÷ 5h
		=	66 $\frac{km}{h}$

Step 6:	Car's speed	→	66 $\frac{km}{h}$ + 16 $\frac{km}{h}$
		=	82 $\frac{km}{h}$

Answer: 82 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	20 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 20 km
		=	95 km

Panimalar travelled 95 km less than Aravindh.

Panimalar

Aravindh

95km

Total = 684 km

Step 3: 684 km - 95 km = 589 km

Step 4:	Distance travelled by Panimalar	→	589 km ÷ 2
		=	294.5 km

Step 5:	Panimalar's speed	→	294.5 km ÷ 4 $\frac{3}{4}$ h
		=	62 $\frac{km}{h}$

Step 6:	Aravindh's speed	→	62 $\frac{km}{h}$ + 20 $\frac{km}{h}$
		=	82 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	20 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 20 km
		=	95 km

Panimalar travelled 95 km less than Aravindh.

Panimalar

Aravindh

95km

Total = 684 km

Step 3: 684 km - 95 km = 589 km

Step 4:	Distance travelled by Panimalar	→	589 km ÷ 2
		=	294.5 km

Step 5:	Distance travelled by Aravindh	→	294.5 km + 95 km
		=	389.5 km

Step 6:	Aravindh's speed	→	389.5 km ÷ 4 $\frac{3}{4}$ h
		=	82 $\frac{km}{h}$

Town Lala and Town Yaya are 700 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 12 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

Answer: 76 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	12 km
	5h	→	5 x 12 km
		=	60 km

The lorry travelled 60 km less than the car.

Lorry

Car

60km

Total = 700 km

Step 3: 700 km - 60 km = 640 km

Step 4:	Distance travelled by the lorry	→	640 km ÷ 2
		=	320 km

Step 5:	Distance travelled by the car	→	320 km + 60 km
		=	380 km

Step 6:	Car's speed	→	380 km ÷ 5h
		=	76 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	12 km
	5h	→	5 x 12 km
		=	60 km

The lorry travelled 60 km less than the car.

Lorry

Car

60km

Total = 700 km

Step 3: 700 km - 60 km = 640 km

Step 4:	Distance travelled by the lorry	→	640 km ÷ 2
		=	320 km

Step 5:	Lorry's speed	→	320 km ÷ 5h
		=	64 $\frac{km}{h}$

Step 6:	Car's speed	→	64 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	76 $\frac{km}{h}$

10)

Answer: 82 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Nandini travelled 57 km less than Kumar.

Nandini

Kumar

57km

Total = 722 km

Step 3: 722 km - 57 km = 665 km

Step 4:	Distance travelled by Nandini	→	665 km ÷ 2
		=	332.5 km

Step 5:	Nandini's speed	→	332.5 km ÷ 4 $\frac{3}{4}$ h
		=	70 $\frac{km}{h}$

Step 6:	Kumar's speed	→	70 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	82 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Nandini travelled 57 km less than Kumar.

Nandini

Kumar

57km

Total = 722 km

Step 3: 722 km - 57 km = 665 km

Step 4:	Distance travelled by Nandini	→	665 km ÷ 2
		=	332.5 km

Step 5:	Distance travelled by Kumar	→	332.5 km + 57 km
		=	389.5 km

Step 6:	Kumar's speed	→	389.5 km ÷ 4 $\frac{3}{4}$ h
		=	82 $\frac{km}{h}$