Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (1770)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Town Lala and Town Yaya are 680 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 22 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 950 km apart. At 1045 h Haritha drove from Town A to Town B. At the same time, Prem drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Haritha and Prem passed each other at 1530 h. If Haritha was travelling 20 $\frac{km}{h}$ slower than Prem, find Prem's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 720 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 20 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 798 km apart. At 1045 h Tamilselvi drove from Town A to Town B. At the same time, Moorthi drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Tamilselvi and Moorthi passed each other at 1530 h. If Tamilselvi was travelling 30 $\frac{km}{h}$ slower than Moorthi, find Moorthi's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 730 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 12 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 950 km apart. At 1045 h Pavi drove from Town A to Town B. At the same time, Kumar drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Pavi and Kumar passed each other at 1530 h. If Pavi was travelling 20 $\frac{km}{h}$ slower than Kumar, find Kumar's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 700 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 22 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 798 km apart. At 1045 h Indra drove from Town A to Town B. At the same time, Raj drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Indra and Raj passed each other at 1530 h. If Indra was travelling 12 $\frac{km}{h}$ slower than Raj, find Raj's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 710 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 18 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

10)

Town A and Town B were 608 km apart. At 1045 h Poongodi drove from Town A to Town B. At the same time, Anand drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Poongodi and Anand passed each other at 1530 h. If Poongodi was travelling 28 $\frac{km}{h}$ slower than Anand, find Anand's speed.

$\frac{km}{h}$

Answer:_______________

Answer: 79 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	22 km
	5h	→	5 x 22 km
		=	110 km

The lorry travelled 110 km less than the car.

Lorry

Car

110km

Total = 680 km

Step 3: 680 km - 110 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Distance travelled by the car	→	285 km + 110 km
		=	395 km

Step 6:	Car's speed	→	395 km ÷ 5h
		=	79 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	22 km
	5h	→	5 x 22 km
		=	110 km

The lorry travelled 110 km less than the car.

Lorry

Car

110km

Total = 680 km

Step 3: 680 km - 110 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Lorry's speed	→	285 km ÷ 5h
		=	57 $\frac{km}{h}$

Step 6:	Car's speed	→	57 $\frac{km}{h}$ + 22 $\frac{km}{h}$
		=	79 $\frac{km}{h}$

Answer: 110 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	20 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 20 km
		=	95 km

Haritha travelled 95 km less than Prem.

Haritha

Prem

95km

Total = 950 km

Step 3: 950 km - 95 km = 855 km

Step 4:	Distance travelled by Haritha	→	855 km ÷ 2
		=	427.5 km

Step 5:	Haritha's speed	→	427.5 km ÷ 4 $\frac{3}{4}$ h
		=	90 $\frac{km}{h}$

Step 6:	Prem's speed	→	90 $\frac{km}{h}$ + 20 $\frac{km}{h}$
		=	110 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	20 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 20 km
		=	95 km

Haritha travelled 95 km less than Prem.

Haritha

Prem

95km

Total = 950 km

Step 3: 950 km - 95 km = 855 km

Step 4:	Distance travelled by Haritha	→	855 km ÷ 2
		=	427.5 km

Step 5:	Distance travelled by Prem	→	427.5 km + 95 km
		=	522.5 km

Step 6:	Prem's speed	→	522.5 km ÷ 4 $\frac{3}{4}$ h
		=	110 $\frac{km}{h}$

Answer: 82 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	20 km
	5h	→	5 x 20 km
		=	100 km

The lorry travelled 100 km less than the car.

Lorry

Car

100km

Total = 720 km

Step 3: 720 km - 100 km = 620 km

Step 4:	Distance travelled by the lorry	→	620 km ÷ 2
		=	310 km

Step 5:	Distance travelled by the car	→	310 km + 100 km
		=	410 km

Step 6:	Car's speed	→	410 km ÷ 5h
		=	82 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	20 km
	5h	→	5 x 20 km
		=	100 km

The lorry travelled 100 km less than the car.

Lorry

Car

100km

Total = 720 km

Step 3: 720 km - 100 km = 620 km

Step 4:	Distance travelled by the lorry	→	620 km ÷ 2
		=	310 km

Step 5:	Lorry's speed	→	310 km ÷ 5h
		=	62 $\frac{km}{h}$

Step 6:	Car's speed	→	62 $\frac{km}{h}$ + 20 $\frac{km}{h}$
		=	82 $\frac{km}{h}$

Answer: 99 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	30 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 30 km
		=	142.5 km

Tamilselvi travelled 142.5 km less than Moorthi.

Tamilselvi

Moorthi

142.5km

Total = 798 km

Step 3: 798 km - 142.5 km = 655.5 km

Step 4:	Distance travelled by Tamilselvi	→	655.5 km ÷ 2
		=	327.75 km

Step 5:	Tamilselvi's speed	→	327.75 km ÷ 4 $\frac{3}{4}$ h
		=	69 $\frac{km}{h}$

Step 6:	Moorthi's speed	→	69 $\frac{km}{h}$ + 30 $\frac{km}{h}$
		=	99 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	30 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 30 km
		=	142.5 km

Tamilselvi travelled 142.5 km less than Moorthi.

Tamilselvi

Moorthi

142.5km

Total = 798 km

Step 3: 798 km - 142.5 km = 655.5 km

Step 4:	Distance travelled by Tamilselvi	→	655.5 km ÷ 2
		=	327.75 km

Step 5:	Distance travelled by Moorthi	→	327.75 km + 142.5 km
		=	470.25 km

Step 6:	Moorthi's speed	→	470.25 km ÷ 4 $\frac{3}{4}$ h
		=	99 $\frac{km}{h}$

Answer: 79 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	12 km
	5h	→	5 x 12 km
		=	60 km

The lorry travelled 60 km less than the car.

Lorry

Car

60km

Total = 730 km

Step 3: 730 km - 60 km = 670 km

Step 4:	Distance travelled by the lorry	→	670 km ÷ 2
		=	335 km

Step 5:	Distance travelled by the car	→	335 km + 60 km
		=	395 km

Step 6:	Car's speed	→	395 km ÷ 5h
		=	79 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	12 km
	5h	→	5 x 12 km
		=	60 km

The lorry travelled 60 km less than the car.

Lorry

Car

60km

Total = 730 km

Step 3: 730 km - 60 km = 670 km

Step 4:	Distance travelled by the lorry	→	670 km ÷ 2
		=	335 km

Step 5:	Lorry's speed	→	335 km ÷ 5h
		=	67 $\frac{km}{h}$

Step 6:	Car's speed	→	67 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	79 $\frac{km}{h}$

Answer: 110 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	20 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 20 km
		=	95 km

Pavi travelled 95 km less than Kumar.

Pavi

Kumar

95km

Total = 950 km

Step 3: 950 km - 95 km = 855 km

Step 4:	Distance travelled by Pavi	→	855 km ÷ 2
		=	427.5 km

Step 5:	Pavi's speed	→	427.5 km ÷ 4 $\frac{3}{4}$ h
		=	90 $\frac{km}{h}$

Step 6:	Kumar's speed	→	90 $\frac{km}{h}$ + 20 $\frac{km}{h}$
		=	110 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	20 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 20 km
		=	95 km

Pavi travelled 95 km less than Kumar.

Pavi

Kumar

95km

Total = 950 km

Step 3: 950 km - 95 km = 855 km

Step 4:	Distance travelled by Pavi	→	855 km ÷ 2
		=	427.5 km

Step 5:	Distance travelled by Kumar	→	427.5 km + 95 km
		=	522.5 km

Step 6:	Kumar's speed	→	522.5 km ÷ 4 $\frac{3}{4}$ h
		=	110 $\frac{km}{h}$

Answer: 81 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	22 km
	5h	→	5 x 22 km
		=	110 km

The lorry travelled 110 km less than the car.

Lorry

Car

110km

Total = 700 km

Step 3: 700 km - 110 km = 590 km

Step 4:	Distance travelled by the lorry	→	590 km ÷ 2
		=	295 km

Step 5:	Distance travelled by the car	→	295 km + 110 km
		=	405 km

Step 6:	Car's speed	→	405 km ÷ 5h
		=	81 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	22 km
	5h	→	5 x 22 km
		=	110 km

The lorry travelled 110 km less than the car.

Lorry

Car

110km

Total = 700 km

Step 3: 700 km - 110 km = 590 km

Step 4:	Distance travelled by the lorry	→	590 km ÷ 2
		=	295 km

Step 5:	Lorry's speed	→	295 km ÷ 5h
		=	59 $\frac{km}{h}$

Step 6:	Car's speed	→	59 $\frac{km}{h}$ + 22 $\frac{km}{h}$
		=	81 $\frac{km}{h}$

Answer: 90 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Indra travelled 57 km less than Raj.

Indra

Raj

57km

Total = 798 km

Step 3: 798 km - 57 km = 741 km

Step 4:	Distance travelled by Indra	→	741 km ÷ 2
		=	370.5 km

Step 5:	Indra's speed	→	370.5 km ÷ 4 $\frac{3}{4}$ h
		=	78 $\frac{km}{h}$

Step 6:	Raj's speed	→	78 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	90 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Indra travelled 57 km less than Raj.

Indra

Raj

57km

Total = 798 km

Step 3: 798 km - 57 km = 741 km

Step 4:	Distance travelled by Indra	→	741 km ÷ 2
		=	370.5 km

Step 5:	Distance travelled by Raj	→	370.5 km + 57 km
		=	427.5 km

Step 6:	Raj's speed	→	427.5 km ÷ 4 $\frac{3}{4}$ h
		=	90 $\frac{km}{h}$

Answer: 80 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	18 km
	5h	→	5 x 18 km
		=	90 km

The lorry travelled 90 km less than the car.

Lorry

Car

90km

Total = 710 km

Step 3: 710 km - 90 km = 620 km

Step 4:	Distance travelled by the lorry	→	620 km ÷ 2
		=	310 km

Step 5:	Distance travelled by the car	→	310 km + 90 km
		=	400 km

Step 6:	Car's speed	→	400 km ÷ 5h
		=	80 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	18 km
	5h	→	5 x 18 km
		=	90 km

The lorry travelled 90 km less than the car.

Lorry

Car

90km

Total = 710 km

Step 3: 710 km - 90 km = 620 km

Step 4:	Distance travelled by the lorry	→	620 km ÷ 2
		=	310 km

Step 5:	Lorry's speed	→	310 km ÷ 5h
		=	62 $\frac{km}{h}$

Step 6:	Car's speed	→	62 $\frac{km}{h}$ + 18 $\frac{km}{h}$
		=	80 $\frac{km}{h}$

10)

Answer: 78 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	28 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 28 km
		=	133 km

Poongodi travelled 133 km less than Anand.

Poongodi

Anand

133km

Total = 608 km

Step 3: 608 km - 133 km = 475 km

Step 4:	Distance travelled by Poongodi	→	475 km ÷ 2
		=	237.5 km

Step 5:	Poongodi's speed	→	237.5 km ÷ 4 $\frac{3}{4}$ h
		=	50 $\frac{km}{h}$

Step 6:	Anand's speed	→	50 $\frac{km}{h}$ + 28 $\frac{km}{h}$
		=	78 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	28 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 28 km
		=	133 km

Poongodi travelled 133 km less than Anand.

Poongodi

Anand

133km

Total = 608 km

Step 3: 608 km - 133 km = 475 km

Step 4:	Distance travelled by Poongodi	→	475 km ÷ 2
		=	237.5 km

Step 5:	Distance travelled by Anand	→	237.5 km + 133 km
		=	370.5 km

Step 6:	Anand's speed	→	370.5 km ÷ 4 $\frac{3}{4}$ h
		=	78 $\frac{km}{h}$