Sasi Math (Revised for 1024)

Scroll:Distance, Time and Speed >> Distance, Time & Speed >> ps (1770)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Town A and Town B were 950 km apart. At 1045 h Kumutha drove from Town A to Town B. At the same time, Kalai drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Kumutha and Kalai passed each other at 1530 h. If Kumutha was travelling 12 $\frac{km}{h}$ slower than Kalai, find Kalai's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 680 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 14 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 836 km apart. At 1045 h Jeevini drove from Town A to Town B. At the same time, Anand drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Jeevini and Anand passed each other at 1530 h. If Jeevini was travelling 16 $\frac{km}{h}$ slower than Anand, find Anand's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 720 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 30 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 912 km apart. At 1045 h Tamilselvi drove from Town A to Town B. At the same time, Pugal drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Tamilselvi and Pugal passed each other at 1530 h. If Tamilselvi was travelling 16 $\frac{km}{h}$ slower than Pugal, find Pugal's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 680 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 30 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 646 km apart. At 1045 h Poongodi drove from Town A to Town B. At the same time, Anand drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Poongodi and Anand passed each other at 1530 h. If Poongodi was travelling 18 $\frac{km}{h}$ slower than Anand, find Anand's speed.

$\frac{km}{h}$

Answer:_______________

Town Lala and Town Yaya are 670 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 26 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Town A and Town B were 836 km apart. At 1045 h Selvanayaki drove from Town A to Town B. At the same time, Narayanan drove from Town B to Town A on the same road. Both of them did not change their speeds throughout their journeys. Selvanayaki and Narayanan passed each other at 1530 h. If Selvanayaki was travelling 10 $\frac{km}{h}$ slower than Narayanan, find Narayanan's speed.

$\frac{km}{h}$

Answer:_______________

10)

Town Lala and Town Yaya are 740 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 28 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

$\frac{km}{h}$

Answer:_______________

Answer: 106 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Kumutha travelled 57 km less than Kalai.

Kumutha

Kalai

57km

Total = 950 km

Step 3: 950 km - 57 km = 893 km

Step 4:	Distance travelled by Kumutha	→	893 km ÷ 2
		=	446.5 km

Step 5:	Kumutha's speed	→	446.5 km ÷ 4 $\frac{3}{4}$ h
		=	94 $\frac{km}{h}$

Step 6:	Kalai's speed	→	94 $\frac{km}{h}$ + 12 $\frac{km}{h}$
		=	106 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	12 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 12 km
		=	57 km

Kumutha travelled 57 km less than Kalai.

Kumutha

Kalai

57km

Total = 950 km

Step 3: 950 km - 57 km = 893 km

Step 4:	Distance travelled by Kumutha	→	893 km ÷ 2
		=	446.5 km

Step 5:	Distance travelled by Kalai	→	446.5 km + 57 km
		=	503.5 km

Step 6:	Kalai's speed	→	503.5 km ÷ 4 $\frac{3}{4}$ h
		=	106 $\frac{km}{h}$

Answer: 75 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	14 km
	5h	→	5 x 14 km
		=	70 km

The lorry travelled 70 km less than the car.

Lorry

Car

70km

Total = 680 km

Step 3: 680 km - 70 km = 610 km

Step 4:	Distance travelled by the lorry	→	610 km ÷ 2
		=	305 km

Step 5:	Distance travelled by the car	→	305 km + 70 km
		=	375 km

Step 6:	Car's speed	→	375 km ÷ 5h
		=	75 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	14 km
	5h	→	5 x 14 km
		=	70 km

The lorry travelled 70 km less than the car.

Lorry

Car

70km

Total = 680 km

Step 3: 680 km - 70 km = 610 km

Step 4:	Distance travelled by the lorry	→	610 km ÷ 2
		=	305 km

Step 5:	Lorry's speed	→	305 km ÷ 5h
		=	61 $\frac{km}{h}$

Step 6:	Car's speed	→	61 $\frac{km}{h}$ + 14 $\frac{km}{h}$
		=	75 $\frac{km}{h}$

Answer: 96 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	16 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 16 km
		=	76 km

Jeevini travelled 76 km less than Anand.

Jeevini

Anand

76km

Total = 836 km

Step 3: 836 km - 76 km = 760 km

Step 4:	Distance travelled by Jeevini	→	760 km ÷ 2
		=	380 km

Step 5:	Jeevini's speed	→	380 km ÷ 4 $\frac{3}{4}$ h
		=	80 $\frac{km}{h}$

Step 6:	Anand's speed	→	80 $\frac{km}{h}$ + 16 $\frac{km}{h}$
		=	96 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	16 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 16 km
		=	76 km

Jeevini travelled 76 km less than Anand.

Jeevini

Anand

76km

Total = 836 km

Step 3: 836 km - 76 km = 760 km

Step 4:	Distance travelled by Jeevini	→	760 km ÷ 2
		=	380 km

Step 5:	Distance travelled by Anand	→	380 km + 76 km
		=	456 km

Step 6:	Anand's speed	→	456 km ÷ 4 $\frac{3}{4}$ h
		=	96 $\frac{km}{h}$

Answer: 87 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	30 km
	5h	→	5 x 30 km
		=	150 km

The lorry travelled 150 km less than the car.

Lorry

Car

150km

Total = 720 km

Step 3: 720 km - 150 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Distance travelled by the car	→	285 km + 150 km
		=	435 km

Step 6:	Car's speed	→	435 km ÷ 5h
		=	87 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	30 km
	5h	→	5 x 30 km
		=	150 km

The lorry travelled 150 km less than the car.

Lorry

Car

150km

Total = 720 km

Step 3: 720 km - 150 km = 570 km

Step 4:	Distance travelled by the lorry	→	570 km ÷ 2
		=	285 km

Step 5:	Lorry's speed	→	285 km ÷ 5h
		=	57 $\frac{km}{h}$

Step 6:	Car's speed	→	57 $\frac{km}{h}$ + 30 $\frac{km}{h}$
		=	87 $\frac{km}{h}$

Answer: 104 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	16 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 16 km
		=	76 km

Tamilselvi travelled 76 km less than Pugal.

Tamilselvi

Pugal

76km

Total = 912 km

Step 3: 912 km - 76 km = 836 km

Step 4:	Distance travelled by Tamilselvi	→	836 km ÷ 2
		=	418 km

Step 5:	Tamilselvi's speed	→	418 km ÷ 4 $\frac{3}{4}$ h
		=	88 $\frac{km}{h}$

Step 6:	Pugal's speed	→	88 $\frac{km}{h}$ + 16 $\frac{km}{h}$
		=	104 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	16 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 16 km
		=	76 km

Tamilselvi travelled 76 km less than Pugal.

Tamilselvi

Pugal

76km

Total = 912 km

Step 3: 912 km - 76 km = 836 km

Step 4:	Distance travelled by Tamilselvi	→	836 km ÷ 2
		=	418 km

Step 5:	Distance travelled by Pugal	→	418 km + 76 km
		=	494 km

Step 6:	Pugal's speed	→	494 km ÷ 4 $\frac{3}{4}$ h
		=	104 $\frac{km}{h}$

Town Lala and Town Yaya are 680 km apart. At 8.30 a.m., a car left Town Lala for Town Yaya, travelling at a constant speed. At the same time, a lorry set off from Town Yaya for Town Lala at a constant speed too. At 1.30 p.m.,the two vehicles passed each other. If the speed of the car was 30 $\frac{km}{h}$ faster than the lorry, find the speed of the car.

Answer: 83 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	30 km
	5h	→	5 x 30 km
		=	150 km

The lorry travelled 150 km less than the car.

Lorry

Car

150km

Total = 680 km

Step 3: 680 km - 150 km = 530 km

Step 4:	Distance travelled by the lorry	→	530 km ÷ 2
		=	265 km

Step 5:	Distance travelled by the car	→	265 km + 150 km
		=	415 km

Step 6:	Car's speed	→	415 km ÷ 5h
		=	83 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	30 km
	5h	→	5 x 30 km
		=	150 km

The lorry travelled 150 km less than the car.

Lorry

Car

150km

Total = 680 km

Step 3: 680 km - 150 km = 530 km

Step 4:	Distance travelled by the lorry	→	530 km ÷ 2
		=	265 km

Step 5:	Lorry's speed	→	265 km ÷ 5h
		=	53 $\frac{km}{h}$

Step 6:	Car's speed	→	53 $\frac{km}{h}$ + 30 $\frac{km}{h}$
		=	83 $\frac{km}{h}$

Answer: 77 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	18 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 18 km
		=	85.5 km

Poongodi travelled 85.5 km less than Anand.

Poongodi

Anand

85.5km

Total = 646 km

Step 3: 646 km - 85.5 km = 560.5 km

Step 4:	Distance travelled by Poongodi	→	560.5 km ÷ 2
		=	280.25 km

Step 5:	Poongodi's speed	→	280.25 km ÷ 4 $\frac{3}{4}$ h
		=	59 $\frac{km}{h}$

Step 6:	Anand's speed	→	59 $\frac{km}{h}$ + 18 $\frac{km}{h}$
		=	77 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	18 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 18 km
		=	85.5 km

Poongodi travelled 85.5 km less than Anand.

Poongodi

Anand

85.5km

Total = 646 km

Step 3: 646 km - 85.5 km = 560.5 km

Step 4:	Distance travelled by Poongodi	→	560.5 km ÷ 2
		=	280.25 km

Step 5:	Distance travelled by Anand	→	280.25 km + 85.5 km
		=	365.75 km

Step 6:	Anand's speed	→	365.75 km ÷ 4 $\frac{3}{4}$ h
		=	77 $\frac{km}{h}$

Answer: 80 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	26 km
	5h	→	5 x 26 km
		=	130 km

The lorry travelled 130 km less than the car.

Lorry

Car

130km

Total = 670 km

Step 3: 670 km - 130 km = 540 km

Step 4:	Distance travelled by the lorry	→	540 km ÷ 2
		=	270 km

Step 5:	Distance travelled by the car	→	270 km + 130 km
		=	400 km

Step 6:	Car's speed	→	400 km ÷ 5h
		=	80 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	26 km
	5h	→	5 x 26 km
		=	130 km

The lorry travelled 130 km less than the car.

Lorry

Car

130km

Total = 670 km

Step 3: 670 km - 130 km = 540 km

Step 4:	Distance travelled by the lorry	→	540 km ÷ 2
		=	270 km

Step 5:	Lorry's speed	→	270 km ÷ 5h
		=	54 $\frac{km}{h}$

Step 6:	Car's speed	→	54 $\frac{km}{h}$ + 26 $\frac{km}{h}$
		=	80 $\frac{km}{h}$

Answer: 93 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	10 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 10 km
		=	47.5 km

Selvanayaki travelled 47.5 km less than Narayanan.

Selvanayaki

Narayanan

47.5km

Total = 836 km

Step 3: 836 km - 47.5 km = 788.5 km

Step 4:	Distance travelled by Selvanayaki	→	788.5 km ÷ 2
		=	394.25 km

Step 5:	Selvanayaki's speed	→	394.25 km ÷ 4 $\frac{3}{4}$ h
		=	83 $\frac{km}{h}$

Step 6:	Narayanan's speed	→	83 $\frac{km}{h}$ + 10 $\frac{km}{h}$
		=	93 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1530 h - 1045 h
		=	4 $\frac{3}{4}$ h

Step 2:	1h	→	10 km
	4 $\frac{3}{4}$ h	→	4 $\frac{3}{4}$ x 10 km
		=	47.5 km

Selvanayaki travelled 47.5 km less than Narayanan.

Selvanayaki

Narayanan

47.5km

Total = 836 km

Step 3: 836 km - 47.5 km = 788.5 km

Step 4:	Distance travelled by Selvanayaki	→	788.5 km ÷ 2
		=	394.25 km

Step 5:	Distance travelled by Narayanan	→	394.25 km + 47.5 km
		=	441.75 km

Step 6:	Narayanan's speed	→	441.75 km ÷ 4 $\frac{3}{4}$ h
		=	93 $\frac{km}{h}$

10)

Answer: 88 $\frac{km}{h}$

SOLUTION 1 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	28 km
	5h	→	5 x 28 km
		=	140 km

The lorry travelled 140 km less than the car.

Lorry

Car

140km

Total = 740 km

Step 3: 740 km - 140 km = 600 km

Step 4:	Distance travelled by the lorry	→	600 km ÷ 2
		=	300 km

Step 5:	Distance travelled by the car	→	300 km + 140 km
		=	440 km

Step 6:	Car's speed	→	440 km ÷ 5h
		=	88 $\frac{km}{h}$

SOLUTION 2 :

Step 1:	Travelling time	→	1.30 p.m. - 8.30 a.m.
		=	5h

Step 2:	1h	→	28 km
	5h	→	5 x 28 km
		=	140 km

The lorry travelled 140 km less than the car.

Lorry

Car

140km

Total = 740 km

Step 3: 740 km - 140 km = 600 km

Step 4:	Distance travelled by the lorry	→	600 km ÷ 2
		=	300 km

Step 5:	Lorry's speed	→	300 km ÷ 5h
		=	60 $\frac{km}{h}$

Step 6:	Car's speed	→	60 $\frac{km}{h}$ + 28 $\frac{km}{h}$
		=	88 $\frac{km}{h}$