Scroll:Measurement >> Area & Circumference of Circle >> ps (1791)

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1)  

The figure is made up of a big circle and 2 small circles with diameter of 16 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 16 cm, CD = 14 cm

cm

cm2



Answer:_______________




2)  

The figure is made up of a big circle and 2 small circles with radii of 18 cm and 9 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 18 cm.

cm

cm2



Answer:_______________




3)  

The figure is made up of a big circle and 2 small circles with diameter of 24 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 24 cm, CD = 8 cm

cm

cm2



Answer:_______________




4)  

The figure is made up of a big circle and 2 small circles with radii of 30 cm and 15 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 30 cm.

cm

cm2



Answer:_______________




5)  

The figure is made up of a big circle and 2 small circles with diameter of 16 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 16 cm, CD = 6 cm

cm

cm2



Answer:_______________




6)  

The figure is made up of a big circle and 2 small circles with radii of 32 cm and 16 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 32 cm.

cm

cm2



Answer:_______________




7)  

The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 18 cm, CD = 10 cm

cm

cm2



Answer:_______________




8)  

The figure is made up of a big circle and 2 small circles with radii of 10 cm and 5 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 10 cm.

cm

cm2



Answer:_______________




9)  

The figure is made up of a big circle and 2 small circles with diameter of 24 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 24 cm, CD = 10 cm

cm

cm2



Answer:_______________




10)  

The figure is made up of a big circle and 2 small circles with radii of 46 cm and 23 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 46 cm.

cm

cm2



Answer:_______________




 

1)  

The figure is made up of a big circle and 2 small circles with diameter of 16 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 16 cm, CD = 14 cm

Answer: 189 cm

Answer: 352 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 30 cm

                                                         = 94.26 cm

Step 2: Circumference of medium circle → π x 16 cm

                                                                 = 50.272 cm

Step 3: Circumference of small circle → π x 14 cm

                                                            = 43.988 cm

Step 4: Perimeter of shaded part → 94.26 cm + 50.272 cm + 43.988 cm

                                                      = 188.520 cm

                                                      ≈ 189 cm

Step 5: Area of big circle → π x 15 cm  x 15 cm

                                          = 706.95 cm2

Step 6: Area of medium circle → π x 8 cm x 8 cm

                                                 = 201.088 cm2

Step 7: Area of small circle → π x 7 cm x 7 cm

                                            = 153.958 cm2

Step 8: Area of shaded part → 706.95 cm2 - 201.088 cm2  - 153.958 cm2

                                             = 351.904 cm2 

                                             ≈ 352 cm2



2)  

The figure is made up of a big circle and 2 small circles with radii of 18 cm and 9 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 18 cm.

Answer: 226 cm

Answer: 509 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 36 cm

                                                        = 113.112 cm

Step 2: Circumference of 2 small circles → 2 x π x 18 cm

                                                                 = 113.112 cm

Step 3: Perimeter of shaded part → 113.112 cm + 113.112 cm

                                                     = 226.224 cm

                                                     ≈ 226 cm

Step 4: Area of big circle → π x 18 cm  x 18 cm

                                         = 1018.008 cm2

Step 5: Area of 2 small circles →2 x π x 9 cm x 9 cm

                                                 = 509.004 cm2

Step 6: Area of shaded part → 1018.008 cm2 - 509.004 cm2

                                             = 509.004 cm2 

                                             ≈ 509 cm2



3)  

The figure is made up of a big circle and 2 small circles with diameter of 24 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 24 cm, CD = 8 cm

Answer: 201 cm

Answer: 302 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 32 cm

                                                         = 100.544 cm

Step 2: Circumference of medium circle → π x 24 cm

                                                                 = 75.408 cm

Step 3: Circumference of small circle → π x 8 cm

                                                            = 25.136 cm

Step 4: Perimeter of shaded part → 100.544 cm + 75.408 cm + 25.136 cm

                                                      = 201.088 cm

                                                      ≈ 201 cm

Step 5: Area of big circle → π x 16 cm  x 16 cm

                                          = 804.352 cm2

Step 6: Area of medium circle → π x 12 cm x 12 cm

                                                 = 452.448 cm2

Step 7: Area of small circle → π x 4 cm x 4 cm

                                            = 50.272 cm2

Step 8: Area of shaded part → 804.352 cm2 - 452.448 cm2  - 50.272 cm2

                                             = 301.632 cm2 

                                             ≈ 302 cm2



4)  

The figure is made up of a big circle and 2 small circles with radii of 30 cm and 15 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 30 cm.

Answer: 377 cm

Answer: 1414 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 60 cm

                                                        = 188.520 cm

Step 2: Circumference of 2 small circles → 2 x π x 30 cm

                                                                 = 188.520 cm

Step 3: Perimeter of shaded part → 188.520 cm + 188.520 cm

                                                     = 377.040 cm

                                                     ≈ 377 cm

Step 4: Area of big circle → π x 30 cm  x 30 cm

                                         = 2827.8 cm2

Step 5: Area of 2 small circles →2 x π x 15 cm x 15 cm

                                                 = 1413.9 cm2

Step 6: Area of shaded part → 2827.8 cm2 - 1413.9 cm2

                                             = 1413.900 cm2 

                                             ≈ 1414 cm2



5)  

The figure is made up of a big circle and 2 small circles with diameter of 16 cm and 6 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 16 cm, CD = 6 cm

Answer: 138 cm

Answer: 151 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 22 cm

                                                         = 69.124 cm

Step 2: Circumference of medium circle → π x 16 cm

                                                                 = 50.272 cm

Step 3: Circumference of small circle → π x 6 cm

                                                            = 18.852 cm

Step 4: Perimeter of shaded part → 69.124 cm + 50.272 cm + 18.852 cm

                                                      = 138.248 cm

                                                      ≈ 138 cm

Step 5: Area of big circle → π x 11 cm  x 11 cm

                                          = 380.182 cm2

Step 6: Area of medium circle → π x 8 cm x 8 cm

                                                 = 201.088 cm2

Step 7: Area of small circle → π x 3 cm x 3 cm

                                            = 28.278 cm2

Step 8: Area of shaded part → 380.182 cm2 - 201.088 cm2  - 28.278 cm2

                                             = 150.816 cm2 

                                             ≈ 151 cm2



6)  

The figure is made up of a big circle and 2 small circles with radii of 32 cm and 16 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 32 cm.

Answer: 402 cm

Answer: 1609 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 64 cm

                                                        = 201.088 cm

Step 2: Circumference of 2 small circles → 2 x π x 32 cm

                                                                 = 201.088 cm

Step 3: Perimeter of shaded part → 201.088 cm + 201.088 cm

                                                     = 402.176 cm

                                                     ≈ 402 cm

Step 4: Area of big circle → π x 32 cm  x 32 cm

                                         = 3217.408 cm2

Step 5: Area of 2 small circles →2 x π x 16 cm x 16 cm

                                                 = 1608.704 cm2

Step 6: Area of shaded part → 3217.408 cm2 - 1608.704 cm2

                                             = 1608.704 cm2 

                                             ≈ 1609 cm2



7)  

The figure is made up of a big circle and 2 small circles with diameter of 18 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 18 cm, CD = 10 cm

Answer: 176 cm

Answer: 283 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 28 cm

                                                         = 87.976 cm

Step 2: Circumference of medium circle → π x 18 cm

                                                                 = 56.556 cm

Step 3: Circumference of small circle → π x 10 cm

                                                            = 31.42 cm

Step 4: Perimeter of shaded part → 87.976 cm + 56.556 cm + 31.42 cm

                                                      = 175.952 cm

                                                      ≈ 176 cm

Step 5: Area of big circle → π x 14 cm  x 14 cm

                                          = 615.832 cm2

Step 6: Area of medium circle → π x 9 cm x 9 cm

                                                 = 254.502 cm2

Step 7: Area of small circle → π x 5 cm x 5 cm

                                            = 78.55 cm2

Step 8: Area of shaded part → 615.832 cm2 - 254.502 cm2  - 78.55 cm2

                                             = 282.780 cm2 

                                             ≈ 283 cm2



8)  

The figure is made up of a big circle and 2 small circles with radii of 10 cm and 5 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 10 cm.

Answer: 126 cm

Answer: 157 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 20 cm

                                                        = 62.840 cm

Step 2: Circumference of 2 small circles → 2 x π x 10 cm

                                                                 = 62.840 cm

Step 3: Perimeter of shaded part → 62.840 cm + 62.840 cm

                                                     = 125.680 cm

                                                     ≈ 126 cm

Step 4: Area of big circle → π x 10 cm  x 10 cm

                                         = 314.2 cm2

Step 5: Area of 2 small circles →2 x π x 5 cm x 5 cm

                                                 = 157.1 cm2

Step 6: Area of shaded part → 314.2 cm2 - 157.1 cm2

                                             = 157.100 cm2 

                                             ≈ 157 cm2



9)  

The figure is made up of a big circle and 2 small circles with diameter of 24 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 24 cm, CD = 10 cm

Answer: 214 cm

Answer: 377 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 34 cm

                                                         = 106.828 cm

Step 2: Circumference of medium circle → π x 24 cm

                                                                 = 75.408 cm

Step 3: Circumference of small circle → π x 10 cm

                                                            = 31.42 cm

Step 4: Perimeter of shaded part → 106.828 cm + 75.408 cm + 31.42 cm

                                                      = 213.656 cm

                                                      ≈ 214 cm

Step 5: Area of big circle → π x 17 cm  x 17 cm

                                          = 908.038 cm2

Step 6: Area of medium circle → π x 12 cm x 12 cm

                                                 = 452.448 cm2

Step 7: Area of small circle → π x 5 cm x 5 cm

                                            = 78.55 cm2

Step 8: Area of shaded part → 908.038 cm2 - 452.448 cm2  - 78.55 cm2

                                             = 377.040 cm2 

                                             ≈ 377 cm2



10)  

The figure is made up of a big circle and 2 small circles with radii of 46 cm and 23 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 46 cm.

Answer: 578 cm

Answer: 3324 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 92 cm

                                                        = 289.064 cm

Step 2: Circumference of 2 small circles → 2 x π x 46 cm

                                                                 = 289.064 cm

Step 3: Perimeter of shaded part → 289.064 cm + 289.064 cm

                                                     = 578.128 cm

                                                     ≈ 578 cm

Step 4: Area of big circle → π x 46 cm  x 46 cm

                                         = 6648.472 cm2

Step 5: Area of 2 small circles →2 x π x 23 cm x 23 cm

                                                 = 3324.236 cm2

Step 6: Area of shaded part → 6648.472 cm2 - 3324.236 cm2

                                             = 3324.236 cm2 

                                             ≈ 3324 cm2