Scroll:Measurement >> Area & Circumference of Circle >> ps (1791)

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1)  

The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 28 cm, CD = 8 cm

cm

cm2



Answer:_______________




2)  

The figure is made up of a big circle and 2 small circles with radii of 50 cm and 25 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 50 cm.

cm

cm2



Answer:_______________




3)  

The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 22 cm, CD = 8 cm

cm

cm2



Answer:_______________




4)  

The figure is made up of a big circle and 2 small circles with radii of 28 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 28 cm.

cm

cm2



Answer:_______________




5)  

The figure is made up of a big circle and 2 small circles with diameter of 20 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 20 cm, CD = 10 cm

cm

cm2



Answer:_______________




6)  

The figure is made up of a big circle and 2 small circles with radii of 32 cm and 16 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 32 cm.

cm

cm2



Answer:_______________




7)  

The figure is made up of a big circle and 2 small circles with diameter of 16 cm and 12 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 16 cm, CD = 12 cm

cm

cm2



Answer:_______________




8)  

The figure is made up of a big circle and 2 small circles with radii of 40 cm and 20 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 40 cm.

cm

cm2



Answer:_______________




9)  

The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 12 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 28 cm, CD = 12 cm

cm

cm2



Answer:_______________




10)  

The figure is made up of a big circle and 2 small circles with radii of 46 cm and 23 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 46 cm.

cm

cm2



Answer:_______________




 

1)  

The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 28 cm, CD = 8 cm

Answer: 226 cm

Answer: 352 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 36 cm

                                                         = 113.112 cm

Step 2: Circumference of medium circle → π x 28 cm

                                                                 = 87.976 cm

Step 3: Circumference of small circle → π x 8 cm

                                                            = 25.136 cm

Step 4: Perimeter of shaded part → 113.112 cm + 87.976 cm + 25.136 cm

                                                      = 226.224 cm

                                                      ≈ 226 cm

Step 5: Area of big circle → π x 18 cm  x 18 cm

                                          = 1018.008 cm2

Step 6: Area of medium circle → π x 14 cm x 14 cm

                                                 = 615.832 cm2

Step 7: Area of small circle → π x 4 cm x 4 cm

                                            = 50.272 cm2

Step 8: Area of shaded part → 1018.008 cm2 - 615.832 cm2  - 50.272 cm2

                                             = 351.904 cm2 

                                             ≈ 352 cm2



2)  

The figure is made up of a big circle and 2 small circles with radii of 50 cm and 25 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 50 cm.

Answer: 628 cm

Answer: 3928 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 100 cm

                                                        = 314.200 cm

Step 2: Circumference of 2 small circles → 2 x π x 50 cm

                                                                 = 314.200 cm

Step 3: Perimeter of shaded part → 314.200 cm + 314.200 cm

                                                     = 628.400 cm

                                                     ≈ 628 cm

Step 4: Area of big circle → π x 50 cm  x 50 cm

                                         = 7855 cm2

Step 5: Area of 2 small circles →2 x π x 25 cm x 25 cm

                                                 = 3927.5 cm2

Step 6: Area of shaded part → 7855 cm2 - 3927.5 cm2

                                             = 3927.500 cm2 

                                             ≈ 3928 cm2



3)  

The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 8 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 22 cm, CD = 8 cm

Answer: 189 cm

Answer: 276 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 30 cm

                                                         = 94.26 cm

Step 2: Circumference of medium circle → π x 22 cm

                                                                 = 69.124 cm

Step 3: Circumference of small circle → π x 8 cm

                                                            = 25.136 cm

Step 4: Perimeter of shaded part → 94.26 cm + 69.124 cm + 25.136 cm

                                                      = 188.520 cm

                                                      ≈ 189 cm

Step 5: Area of big circle → π x 15 cm  x 15 cm

                                          = 706.95 cm2

Step 6: Area of medium circle → π x 11 cm x 11 cm

                                                 = 380.182 cm2

Step 7: Area of small circle → π x 4 cm x 4 cm

                                            = 50.272 cm2

Step 8: Area of shaded part → 706.95 cm2 - 380.182 cm2  - 50.272 cm2

                                             = 276.496 cm2 

                                             ≈ 276 cm2



4)  

The figure is made up of a big circle and 2 small circles with radii of 28 cm and 14 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 28 cm.

Answer: 352 cm

Answer: 1232 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 56 cm

                                                        = 175.952 cm

Step 2: Circumference of 2 small circles → 2 x π x 28 cm

                                                                 = 175.952 cm

Step 3: Perimeter of shaded part → 175.952 cm + 175.952 cm

                                                     = 351.904 cm

                                                     ≈ 352 cm

Step 4: Area of big circle → π x 28 cm  x 28 cm

                                         = 2463.328 cm2

Step 5: Area of 2 small circles →2 x π x 14 cm x 14 cm

                                                 = 1231.664 cm2

Step 6: Area of shaded part → 2463.328 cm2 - 1231.664 cm2

                                             = 1231.664 cm2 

                                             ≈ 1232 cm2



5)  

The figure is made up of a big circle and 2 small circles with diameter of 20 cm and 10 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 20 cm, CD = 10 cm

Answer: 189 cm

Answer: 314 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 30 cm

                                                         = 94.26 cm

Step 2: Circumference of medium circle → π x 20 cm

                                                                 = 62.84 cm

Step 3: Circumference of small circle → π x 10 cm

                                                            = 31.42 cm

Step 4: Perimeter of shaded part → 94.26 cm + 62.84 cm + 31.42 cm

                                                      = 188.520 cm

                                                      ≈ 189 cm

Step 5: Area of big circle → π x 15 cm  x 15 cm

                                          = 706.95 cm2

Step 6: Area of medium circle → π x 10 cm x 10 cm

                                                 = 314.2 cm2

Step 7: Area of small circle → π x 5 cm x 5 cm

                                            = 78.55 cm2

Step 8: Area of shaded part → 706.95 cm2 - 314.2 cm2  - 78.55 cm2

                                             = 314.200 cm2 

                                             ≈ 314 cm2



6)  

The figure is made up of a big circle and 2 small circles with radii of 32 cm and 16 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 32 cm.

Answer: 402 cm

Answer: 1609 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 64 cm

                                                        = 201.088 cm

Step 2: Circumference of 2 small circles → 2 x π x 32 cm

                                                                 = 201.088 cm

Step 3: Perimeter of shaded part → 201.088 cm + 201.088 cm

                                                     = 402.176 cm

                                                     ≈ 402 cm

Step 4: Area of big circle → π x 32 cm  x 32 cm

                                         = 3217.408 cm2

Step 5: Area of 2 small circles →2 x π x 16 cm x 16 cm

                                                 = 1608.704 cm2

Step 6: Area of shaded part → 3217.408 cm2 - 1608.704 cm2

                                             = 1608.704 cm2 

                                             ≈ 1609 cm2



7)  

The figure is made up of a big circle and 2 small circles with diameter of 16 cm and 12 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 16 cm, CD = 12 cm

Answer: 176 cm

Answer: 302 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 28 cm

                                                         = 87.976 cm

Step 2: Circumference of medium circle → π x 16 cm

                                                                 = 50.272 cm

Step 3: Circumference of small circle → π x 12 cm

                                                            = 37.704 cm

Step 4: Perimeter of shaded part → 87.976 cm + 50.272 cm + 37.704 cm

                                                      = 175.952 cm

                                                      ≈ 176 cm

Step 5: Area of big circle → π x 14 cm  x 14 cm

                                          = 615.832 cm2

Step 6: Area of medium circle → π x 8 cm x 8 cm

                                                 = 201.088 cm2

Step 7: Area of small circle → π x 6 cm x 6 cm

                                            = 113.112 cm2

Step 8: Area of shaded part → 615.832 cm2 - 201.088 cm2  - 113.112 cm2

                                             = 301.632 cm2 

                                             ≈ 302 cm2



8)  

The figure is made up of a big circle and 2 small circles with radii of 40 cm and 20 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 40 cm.

Answer: 503 cm

Answer: 2514 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 80 cm

                                                        = 251.360 cm

Step 2: Circumference of 2 small circles → 2 x π x 40 cm

                                                                 = 251.360 cm

Step 3: Perimeter of shaded part → 251.360 cm + 251.360 cm

                                                     = 502.720 cm

                                                     ≈ 503 cm

Step 4: Area of big circle → π x 40 cm  x 40 cm

                                         = 5027.2 cm2

Step 5: Area of 2 small circles →2 x π x 20 cm x 20 cm

                                                 = 2513.6 cm2

Step 6: Area of shaded part → 5027.2 cm2 - 2513.6 cm2

                                             = 2513.600 cm2 

                                             ≈ 2514 cm2



9)  

The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 12 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = 28 cm, CD = 12 cm

Answer: 251 cm

Answer: 528 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 40 cm

                                                         = 125.68 cm

Step 2: Circumference of medium circle → π x 28 cm

                                                                 = 87.976 cm

Step 3: Circumference of small circle → π x 12 cm

                                                            = 37.704 cm

Step 4: Perimeter of shaded part → 125.68 cm + 87.976 cm + 37.704 cm

                                                      = 251.360 cm

                                                      ≈ 251 cm

Step 5: Area of big circle → π x 20 cm  x 20 cm

                                          = 1256.8 cm2

Step 6: Area of medium circle → π x 14 cm x 14 cm

                                                 = 615.832 cm2

Step 7: Area of small circle → π x 6 cm x 6 cm

                                            = 113.112 cm2

Step 8: Area of shaded part → 1256.8 cm2 - 615.832 cm2  - 113.112 cm2

                                             = 527.856 cm2 

                                             ≈ 528 cm2



10)  

The figure is made up of a big circle and 2 small circles with radii of 46 cm and 23 cm respectively. 

Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. 

π = 3.142

AB = CD, therefore AB = 46 cm.

Answer: 578 cm

Answer: 3324 cm2



SOLUTION 1 :

Step 1: Circumference of big circle → π x 92 cm

                                                        = 289.064 cm

Step 2: Circumference of 2 small circles → 2 x π x 46 cm

                                                                 = 289.064 cm

Step 3: Perimeter of shaded part → 289.064 cm + 289.064 cm

                                                     = 578.128 cm

                                                     ≈ 578 cm

Step 4: Area of big circle → π x 46 cm  x 46 cm

                                         = 6648.472 cm2

Step 5: Area of 2 small circles →2 x π x 23 cm x 23 cm

                                                 = 3324.236 cm2

Step 6: Area of shaded part → 6648.472 cm2 - 3324.236 cm2

                                             = 3324.236 cm2 

                                             ≈ 3324 cm2