Written Instructions:
For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..
For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.
Leave your answers in the simplest form or correct to two decimal places.
| 1) The figure is made up of a big circle and 2 small circles with radii of 16 cm and 8 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 16 cm.
cm cm2 Answer:_______________ |
| 2) The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 12 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 28 cm, CD = 12 cm
cm cm2 Answer:_______________ |
| 3) The figure is made up of a big circle and 2 small circles with radii of 8 cm and 4 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 8 cm.
cm cm2 Answer:_______________ |
| 4) The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 10 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 22 cm, CD = 10 cm
cm cm2 Answer:_______________ |
| 5) The figure is made up of a big circle and 2 small circles with radii of 54 cm and 27 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 54 cm.
cm cm2 Answer:_______________ |
| 6) The figure is made up of a big circle and 2 small circles with diameter of 30 cm and 6 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 30 cm, CD = 6 cm
cm cm2 Answer:_______________ |
| 7) The figure is made up of a big circle and 2 small circles with radii of 26 cm and 13 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 26 cm.
cm cm2 Answer:_______________ |
| 8) The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 14 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 22 cm, CD = 14 cm
cm cm2 Answer:_______________ |
| 9) The figure is made up of a big circle and 2 small circles with radii of 36 cm and 18 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 36 cm.
cm cm2 Answer:_______________ |
| 10) The figure is made up of a big circle and 2 small circles with diameter of 30 cm and 10 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 30 cm, CD = 10 cm
cm cm2 Answer:_______________ |
| 1) The figure is made up of a big circle and 2 small circles with radii of 16 cm and 8 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 16 cm.
Answer: 201 cm Answer: 402 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 32 cm = 100.544 cm Step 2: Circumference of 2 small circles → 2 x π x 16 cm = 100.544 cm Step 3: Perimeter of shaded part → 100.544 cm + 100.544 cm = 201.088 cm ≈ 201 cm Step 4: Area of big circle → π x 16 cm x 16 cm = 804.352 cm2 Step 5: Area of 2 small circles →2 x π x 8 cm x 8 cm = 402.176 cm2 Step 6: Area of shaded part → 804.352 cm2 - 402.176 cm2 = 402.176 cm2 ≈ 402 cm2 |
| 2) The figure is made up of a big circle and 2 small circles with diameter of 28 cm and 12 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 28 cm, CD = 12 cm
Answer: 251 cm Answer: 528 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 40 cm = 125.68 cm Step 2: Circumference of medium circle → π x 28 cm = 87.976 cm Step 3: Circumference of small circle → π x 12 cm = 37.704 cm Step 4: Perimeter of shaded part → 125.68 cm + 87.976 cm + 37.704 cm = 251.360 cm ≈ 251 cm Step 5: Area of big circle → π x 20 cm x 20 cm = 1256.8 cm2 Step 6: Area of medium circle → π x 14 cm x 14 cm = 615.832 cm2 Step 7: Area of small circle → π x 6 cm x 6 cm = 113.112 cm2 Step 8: Area of shaded part → 1256.8 cm2 - 615.832 cm2 - 113.112 cm2 = 527.856 cm2 ≈ 528 cm2 |
| 3) The figure is made up of a big circle and 2 small circles with radii of 8 cm and 4 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 8 cm.
Answer: 101 cm Answer: 101 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 16 cm = 50.272 cm Step 2: Circumference of 2 small circles → 2 x π x 8 cm = 50.272 cm Step 3: Perimeter of shaded part → 50.272 cm + 50.272 cm = 100.544 cm ≈ 101 cm Step 4: Area of big circle → π x 8 cm x 8 cm = 201.088 cm2 Step 5: Area of 2 small circles →2 x π x 4 cm x 4 cm = 100.544 cm2 Step 6: Area of shaded part → 201.088 cm2 - 100.544 cm2 = 100.544 cm2 ≈ 101 cm2 |
| 4) The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 10 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 22 cm, CD = 10 cm
Answer: 201 cm Answer: 346 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 32 cm = 100.544 cm Step 2: Circumference of medium circle → π x 22 cm = 69.124 cm Step 3: Circumference of small circle → π x 10 cm = 31.42 cm Step 4: Perimeter of shaded part → 100.544 cm + 69.124 cm + 31.42 cm = 201.088 cm ≈ 201 cm Step 5: Area of big circle → π x 16 cm x 16 cm = 804.352 cm2 Step 6: Area of medium circle → π x 11 cm x 11 cm = 380.182 cm2 Step 7: Area of small circle → π x 5 cm x 5 cm = 78.55 cm2 Step 8: Area of shaded part → 804.352 cm2 - 380.182 cm2 - 78.55 cm2 = 345.620 cm2 ≈ 346 cm2 |
| 5) The figure is made up of a big circle and 2 small circles with radii of 54 cm and 27 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 54 cm.
Answer: 679 cm Answer: 4581 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 108 cm = 339.336 cm Step 2: Circumference of 2 small circles → 2 x π x 54 cm = 339.336 cm Step 3: Perimeter of shaded part → 339.336 cm + 339.336 cm = 678.672 cm ≈ 679 cm Step 4: Area of big circle → π x 54 cm x 54 cm = 9162.072 cm2 Step 5: Area of 2 small circles →2 x π x 27 cm x 27 cm = 4581.036 cm2 Step 6: Area of shaded part → 9162.072 cm2 - 4581.036 cm2 = 4581.036 cm2 ≈ 4581 cm2 |
| 6) The figure is made up of a big circle and 2 small circles with diameter of 30 cm and 6 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 30 cm, CD = 6 cm
Answer: 226 cm Answer: 283 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 36 cm = 113.112 cm Step 2: Circumference of medium circle → π x 30 cm = 94.26 cm Step 3: Circumference of small circle → π x 6 cm = 18.852 cm Step 4: Perimeter of shaded part → 113.112 cm + 94.26 cm + 18.852 cm = 226.224 cm ≈ 226 cm Step 5: Area of big circle → π x 18 cm x 18 cm = 1018.008 cm2 Step 6: Area of medium circle → π x 15 cm x 15 cm = 706.95 cm2 Step 7: Area of small circle → π x 3 cm x 3 cm = 28.278 cm2 Step 8: Area of shaded part → 1018.008 cm2 - 706.95 cm2 - 28.278 cm2 = 282.780 cm2 ≈ 283 cm2 |
| 7) The figure is made up of a big circle and 2 small circles with radii of 26 cm and 13 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 26 cm.
Answer: 327 cm Answer: 1062 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 52 cm = 163.384 cm Step 2: Circumference of 2 small circles → 2 x π x 26 cm = 163.384 cm Step 3: Perimeter of shaded part → 163.384 cm + 163.384 cm = 326.768 cm ≈ 327 cm Step 4: Area of big circle → π x 26 cm x 26 cm = 2123.992 cm2 Step 5: Area of 2 small circles →2 x π x 13 cm x 13 cm = 1061.996 cm2 Step 6: Area of shaded part → 2123.992 cm2 - 1061.996 cm2 = 1061.996 cm2 ≈ 1062 cm2 |
| 8) The figure is made up of a big circle and 2 small circles with diameter of 22 cm and 14 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 22 cm, CD = 14 cm
Answer: 226 cm Answer: 484 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 36 cm = 113.112 cm Step 2: Circumference of medium circle → π x 22 cm = 69.124 cm Step 3: Circumference of small circle → π x 14 cm = 43.988 cm Step 4: Perimeter of shaded part → 113.112 cm + 69.124 cm + 43.988 cm = 226.224 cm ≈ 226 cm Step 5: Area of big circle → π x 18 cm x 18 cm = 1018.008 cm2 Step 6: Area of medium circle → π x 11 cm x 11 cm = 380.182 cm2 Step 7: Area of small circle → π x 7 cm x 7 cm = 153.958 cm2 Step 8: Area of shaded part → 1018.008 cm2 - 380.182 cm2 - 153.958 cm2 = 483.868 cm2 ≈ 484 cm2 |
| 9) The figure is made up of a big circle and 2 small circles with radii of 36 cm and 18 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = CD, therefore AB = 36 cm.
Answer: 452 cm Answer: 2036 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 72 cm = 226.224 cm Step 2: Circumference of 2 small circles → 2 x π x 36 cm = 226.224 cm Step 3: Perimeter of shaded part → 226.224 cm + 226.224 cm = 452.448 cm ≈ 452 cm Step 4: Area of big circle → π x 36 cm x 36 cm = 4072.032 cm2 Step 5: Area of 2 small circles →2 x π x 18 cm x 18 cm = 2036.016 cm2 Step 6: Area of shaded part → 4072.032 cm2 - 2036.016 cm2 = 2036.016 cm2 ≈ 2036 cm2 |
| 10) The figure is made up of a big circle and 2 small circles with diameter of 30 cm and 10 cm respectively. Find the perimeter and area of the shaded part, rounding off your answers to the nearest whole number. π = 3.142 AB = 30 cm, CD = 10 cm
Answer: 251 cm Answer: 471 cm2 SOLUTION 1 : Step 1: Circumference of big circle → π x 40 cm = 125.68 cm Step 2: Circumference of medium circle → π x 30 cm = 94.26 cm Step 3: Circumference of small circle → π x 10 cm = 31.42 cm Step 4: Perimeter of shaded part → 125.68 cm + 94.26 cm + 31.42 cm = 251.360 cm ≈ 251 cm Step 5: Area of big circle → π x 20 cm x 20 cm = 1256.8 cm2 Step 6: Area of medium circle → π x 15 cm x 15 cm = 706.95 cm2 Step 7: Area of small circle → π x 5 cm x 5 cm = 78.55 cm2 Step 8: Area of shaded part → 1256.8 cm2 - 706.95 cm2 - 78.55 cm2 = 471.300 cm2 ≈ 471 cm2 |