Sasi Math (Revised for 1024)

Scroll:Fractions >> Subtraction >> mcq (2505)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Subtract $\frac{1}{3}$ from the sum of $\frac{5}{9}$ and $\frac{1}{3}$ .

1) 59' title="

\frac{5}{9}

"/>

\frac{5}{9}

2) 13' title="

\frac{1}{3}

"/>

\frac{1}{3}

3) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

4) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

( )

Subtract $\frac{1}{4}$ from the sum of $\frac{1}{3}$ and $\frac{1}{12}$ .

1) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

2) 16' title="

\frac{1}{6}

"/>

\frac{1}{6}

3) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

4) 812' title="

\frac{8}{12}

"/>

\frac{8}{12}

( )

Subtract $\frac{1}{4}$ from the sum of $\frac{5}{8}$ and $\frac{1}{2}$ .

1) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

2) 78' title="

\frac{7}{8}

"/>

\frac{7}{8}

3) 36' title="

\frac{3}{6}

"/>

\frac{3}{6}

4) 13' title="

\frac{1}{3}

"/>

\frac{1}{3}

( )

Subtract $\frac{1}{4}$ from the sum of $\frac{3}{8}$ and $\frac{1}{2}$ .

1) 38' title="

\frac{3}{8}

"/>

\frac{3}{8}

2) 58' title="

\frac{5}{8}

"/>

\frac{5}{8}

3) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

4) 48' title="

\frac{4}{8}

"/>

\frac{4}{8}

( )

Subtract $\frac{1}{8}$ from the sum of $\frac{1}{8}$ and $\frac{3}{4}$ .

1) 34' title="

\frac{3}{4}

"/>

\frac{3}{4}

2) 15' title="

\frac{1}{5}

"/>

\frac{1}{5}

3) 310' title="

\frac{3}{10}

"/>

\frac{3}{10}

4) 510' title="

\frac{5}{10}

"/>

\frac{5}{10}

( )

Subtract $\frac{1}{4}$ from the sum of $\frac{3}{4}$ and $\frac{1}{8}$ .

1) 38' title="

\frac{3}{8}

"/>

\frac{3}{8}

2) 18' title="

\frac{1}{8}

"/>

\frac{1}{8}

3) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

4) 58' title="

\frac{5}{8}

"/>

\frac{5}{8}

( )

Subtract $\frac{2}{5}$ from the sum of $\frac{3}{5}$ and $\frac{3}{10}$ .

1) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

2) 25' title="

\frac{2}{5}

"/>

\frac{2}{5}

3) 910' title="

\frac{9}{10}

"/>

\frac{9}{10}

4) 35' title="

\frac{3}{5}

"/>

\frac{3}{5}

( )

Subtract $\frac{1}{3}$ from the sum of $\frac{1}{6}$ and $\frac{1}{2}$ .

1) 26' title="

\frac{2}{6}

"/>

\frac{2}{6}

2) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

3) 13' title="

\frac{1}{3}

"/>

\frac{1}{3}

4) 56' title="

\frac{5}{6}

"/>

\frac{5}{6}

( )

Subtract $\frac{1}{3}$ from the sum of $\frac{7}{12}$ and $\frac{1}{4}$ .

1) 512' title="

\frac{5}{12}

"/>

\frac{5}{12}

2) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

3) 16' title="

\frac{1}{6}

"/>

\frac{1}{6}

4) 56' title="

\frac{5}{6}

"/>

\frac{5}{6}

( )

10)

Subtract $\frac{1}{4}$ from the sum of $\frac{5}{12}$ and $\frac{1}{3}$ .

1) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

2) 512' title="

\frac{5}{12}

"/>

\frac{5}{12}

3) 34' title="

\frac{3}{4}

"/>

\frac{3}{4}

4) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

( )

Subtract $\frac{1}{3}$ from the sum of $\frac{5}{9}$ and $\frac{1}{3}$ .

1) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

2) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

3) 59' title="

\frac{5}{9}

"/>

\frac{5}{9}

4) 13' title="

\frac{1}{3}

"/>

\frac{1}{3}

Answer: 3

SOLUTION 1 :

Step 1:	$\frac{5}{9}$ + $\frac{1 x 3}{3 x 3}$	= $\frac{5}{9}$ + $\frac{3}{9}$
		= $\frac{8}{9}$
Step 2:	$\frac{8}{9}$ - $\frac{1 x 3}{3 x 3}$	= $\frac{8}{9}$ - $\frac{3}{9}$
		= $\frac{5}{9}$

Subtract $\frac{1}{4}$ from the sum of $\frac{1}{3}$ and $\frac{1}{12}$ .

1) 16' title="

\frac{1}{6}

"/>

\frac{1}{6}

2) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

3) 812' title="

\frac{8}{12}

"/>

\frac{8}{12}

4) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

Answer: 1

SOLUTION 1 :

Step 1:	$\frac{1 x 4}{3 x 4}$ + $\frac{1}{12}$	= $\frac{4}{12}$ + $\frac{1}{12}$
		= $\frac{5}{12}$
Step 2:	$\frac{5}{12}$ - $\frac{1 x 3}{4 x 3}$	= $\frac{5}{12}$ - $\frac{3}{12}$
		= $\frac{2}{12}$

Subtract $\frac{1}{4}$ from the sum of $\frac{5}{8}$ and $\frac{1}{2}$ .

1) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

2) 78' title="

\frac{7}{8}

"/>

\frac{7}{8}

3) 13' title="

\frac{1}{3}

"/>

\frac{1}{3}

4) 36' title="

\frac{3}{6}

"/>

\frac{3}{6}

Answer: 2

SOLUTION 1 :

Step 1:	$\frac{5}{8}$ + $\frac{1 x 4}{2 x 4}$	= $\frac{5}{8}$ + $\frac{4}{8}$
		= $\frac{9}{8}$ $\frac{}{}$
Step 2:	$\frac{9}{8}$ - $\frac{1 x 2}{4 x 2}$	= $\frac{9}{8}$ - $\frac{2}{8}$
		= $\frac{7}{8}$

Subtract $\frac{1}{4}$ from the sum of $\frac{3}{8}$ and $\frac{1}{2}$ .

1) 58' title="

\frac{5}{8}

"/>

\frac{5}{8}

2) 48' title="

\frac{4}{8}

"/>

\frac{4}{8}

3) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

4) 38' title="

\frac{3}{8}

"/>

\frac{3}{8}

Answer: 1

SOLUTION 1 :

Step 1:	$\frac{3}{8}$ + $\frac{1 x 4}{2 x 4}$	= $\frac{3}{8}$ + $\frac{4}{8}$
		= $\frac{7}{8}$
Step 2:	$\frac{7}{8}$ - $\frac{1 x 2}{4 x 2}$	= $\frac{7}{8}$ - $\frac{2}{8}$
		= $\frac{5}{8}$

Subtract $\frac{1}{8}$ from the sum of $\frac{1}{8}$ and $\frac{3}{4}$ .

1) 510' title="

\frac{5}{10}

"/>

\frac{5}{10}

2) 310' title="

\frac{3}{10}

"/>

\frac{3}{10}

3) 15' title="

\frac{1}{5}

"/>

\frac{1}{5}

4) 34' title="

\frac{3}{4}

"/>

\frac{3}{4}

Answer: 4

SOLUTION 1 :

Step 1:	$\frac{1}{8}$ + $\frac{3 x 2}{4 x 2}$	= $\frac{1}{8}$ + $\frac{6}{8}$
		= $\frac{7}{8}$
Step 2:	$\frac{7}{8}$ - $\frac{1}{8}$	= $\frac{7}{8}$ - $\frac{1}{8}$
		= $\frac{6}{8}$
		= $\frac{3}{4}$

Subtract $\frac{1}{4}$ from the sum of $\frac{3}{4}$ and $\frac{1}{8}$ .

1) 18' title="

\frac{1}{8}

"/>

\frac{1}{8}

2) 38' title="

\frac{3}{8}

"/>

\frac{3}{8}

3) 58' title="

\frac{5}{8}

"/>

\frac{5}{8}

4) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

Answer: 3

SOLUTION 1 :

Step 1:	$\frac{3 x 2}{4 x 2}$ + $\frac{1}{8}$	= $\frac{6}{8}$ + $\frac{1}{8}$
		= $\frac{7}{8}$
Step 2:	$\frac{7}{8}$ - $\frac{1 x 2}{4 x 2}$	= $\frac{7}{8}$ - $\frac{2}{8}$
		= $\frac{5}{8}$

Subtract $\frac{2}{5}$ from the sum of $\frac{3}{5}$ and $\frac{3}{10}$ .

1) 35' title="

\frac{3}{5}

"/>

\frac{3}{5}

2) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

3) 25' title="

\frac{2}{5}

"/>

\frac{2}{5}

4) 910' title="

\frac{9}{10}

"/>

\frac{9}{10}

Answer: 2

SOLUTION 1 :

Step 1:	$\frac{3 x 2}{5 x 2}$ + $\frac{3}{10}$	= $\frac{6}{10}$ + $\frac{3}{10}$
		= $\frac{9}{10}$
Step 2:	$\frac{9}{10}$ - $\frac{2 x 2}{5 x 2}$	= $\frac{9}{10}$ - $\frac{4}{10}$
		= $\frac{5}{10}$
		= $\frac{1}{2}$

Subtract $\frac{1}{3}$ from the sum of $\frac{1}{6}$ and $\frac{1}{2}$ .

1) 13' title="

\frac{1}{3}

"/>

\frac{1}{3}

2) 23' title="

\frac{2}{3}

"/>

\frac{2}{3}

3) 26' title="

\frac{2}{6}

"/>

\frac{2}{6}

4) 56' title="

\frac{5}{6}

"/>

\frac{5}{6}

Answer: 1

SOLUTION 1 :

Step 1:	$\frac{1}{6}$ + $\frac{1 x 3}{2 x 3}$	= $\frac{1}{6}$ + $\frac{3}{6}$
		= $\frac{4}{6}$
		= $\frac{2}{3}$
Step 2:	$\frac{2}{3}$ - $\frac{1}{3}$	= $\frac{1}{3}$

Subtract $\frac{1}{3}$ from the sum of $\frac{7}{12}$ and $\frac{1}{4}$ .

1) 512' title="

\frac{5}{12}

"/>

\frac{5}{12}

2) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

3) 56' title="

\frac{5}{6}

"/>

\frac{5}{6}

4) 16' title="

\frac{1}{6}

"/>

\frac{1}{6}

Answer: 2

SOLUTION 1 :

Step 1:	$\frac{7}{12}$ + $\frac{1 x 3}{4 x 3}$	= $\frac{7}{12}$ + $\frac{3}{12}$
		= $\frac{10}{12}$
		= $\frac{5}{6}$
Step 2:	$\frac{5}{6}$ - $\frac{1 x 2}{3 x 2}$	= $\frac{5}{6}$ - $\frac{2}{6}$
		= $\frac{3}{6}$
		= $\frac{1}{2}$

10)

Subtract $\frac{1}{4}$ from the sum of $\frac{5}{12}$ and $\frac{1}{3}$ .

1) 12' title="

\frac{1}{2}

"/>

\frac{1}{2}

2) 14' title="

\frac{1}{4}

"/>

\frac{1}{4}

3) 512' title="

\frac{5}{12}

"/>

\frac{5}{12}

4) 34' title="

\frac{3}{4}

"/>

\frac{3}{4}

Answer: 1

SOLUTION 1 :

Step 1:	$\frac{5}{12}$ + $\frac{1 x 4}{3 x 4}$	= $\frac{5}{12}$ + $\frac{4}{12}$
		= $\frac{9}{12}$
		= $\frac{3}{4}$
Step 2:	$\frac{3}{4}$ - $\frac{1}{4}$	= $\frac{2}{4}$
		= $\frac{1}{2}$