Sasi Math (Revised for 1024)

Scroll:Percentage >> Percentage >> saq (2896)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A bag consists of a number of 20-cent and 50-cent coins. There are 70% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 60 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 55% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 135 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 60% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 760 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 85% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 135 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 75% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 325 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 70% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 390 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 55% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 315 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 60% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 240 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 85% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 315 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

10)

A bag consists of a number of 20-cent and 50-cent coins. There are 75% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 550 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 70% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 60 more 50-cent coins than 20-cent coins

Answer: $128

SOLUTION 1 :

Step 1:	20-cent coins	→ 70%
	50-cent coins	→ 100%
	Difference	→ 100% - 70%
		= 30%
Step 2:	30%	→ 60	(difference)
	1%	→ $\frac{60}{30%}$
	70%	→ $\frac{60}{30%}$ x $\frac{70%}{1}$	(number of 20-cent coins)
		= 140
	100%	→ $\frac{60}{30%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 200
Step 3:	Amount of money in the bag	→ (140 x $0.20) + (200 x $0.50)
		= $128

Answer: $183

SOLUTION 1 :

Step 1:	20-cent coins	→ 55%
	50-cent coins	→ 100%
	Difference	→ 100% - 55%
		= 45%
Step 2:	45%	→ 135	(difference)
	1%	→ $\frac{135}{45%}$
	55%	→ $\frac{135}{45%}$ x $\frac{55%}{1}$	(number of 20-cent coins)
		= 165
	100%	→ $\frac{135}{45%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 300
Step 3:	Amount of money in the bag	→ (165 x $0.20) + (300 x $0.50)
		= $183

Answer: $1178

SOLUTION 1 :

Step 1:	20-cent coins	→ 60%
	50-cent coins	→ 100%
	Difference	→ 100% - 60%
		= 40%
Step 2:	40%	→ 760	(difference)
	1%	→ $\frac{760}{40%}$
	60%	→ $\frac{760}{40%}$ x $\frac{60%}{1}$	(number of 20-cent coins)
		= 1140
	100%	→ $\frac{760}{40%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1900
Step 3:	Amount of money in the bag	→ (1140 x $0.20) + (1900 x $0.50)
		= $1178

Answer: $603

SOLUTION 1 :

Step 1:	20-cent coins	→ 85%
	50-cent coins	→ 100%
	Difference	→ 100% - 85%
		= 15%
Step 2:	15%	→ 135	(difference)
	1%	→ $\frac{135}{15%}$
	85%	→ $\frac{135}{15%}$ x $\frac{85%}{1}$	(number of 20-cent coins)
		= 765
	100%	→ $\frac{135}{15%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 900
Step 3:	Amount of money in the bag	→ (765 x $0.20) + (900 x $0.50)
		= $603

Answer: $845

SOLUTION 1 :

Step 1:	20-cent coins	→ 75%
	50-cent coins	→ 100%
	Difference	→ 100% - 75%
		= 25%
Step 2:	25%	→ 325	(difference)
	1%	→ $\frac{325}{25%}$
	75%	→ $\frac{325}{25%}$ x $\frac{75%}{1}$	(number of 20-cent coins)
		= 975
	100%	→ $\frac{325}{25%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1300
Step 3:	Amount of money in the bag	→ (975 x $0.20) + (1300 x $0.50)
		= $845

Answer: $832

SOLUTION 1 :

Step 1:	20-cent coins	→ 70%
	50-cent coins	→ 100%
	Difference	→ 100% - 70%
		= 30%
Step 2:	30%	→ 390	(difference)
	1%	→ $\frac{390}{30%}$
	70%	→ $\frac{390}{30%}$ x $\frac{70%}{1}$	(number of 20-cent coins)
		= 910
	100%	→ $\frac{390}{30%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1300
Step 3:	Amount of money in the bag	→ (910 x $0.20) + (1300 x $0.50)
		= $832

Answer: $427

SOLUTION 1 :

Step 1:	20-cent coins	→ 55%
	50-cent coins	→ 100%
	Difference	→ 100% - 55%
		= 45%
Step 2:	45%	→ 315	(difference)
	1%	→ $\frac{315}{45%}$
	55%	→ $\frac{315}{45%}$ x $\frac{55%}{1}$	(number of 20-cent coins)
		= 385
	100%	→ $\frac{315}{45%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 700
Step 3:	Amount of money in the bag	→ (385 x $0.20) + (700 x $0.50)
		= $427

Answer: $372

SOLUTION 1 :

Step 1:	20-cent coins	→ 60%
	50-cent coins	→ 100%
	Difference	→ 100% - 60%
		= 40%
Step 2:	40%	→ 240	(difference)
	1%	→ $\frac{240}{40%}$
	60%	→ $\frac{240}{40%}$ x $\frac{60%}{1}$	(number of 20-cent coins)
		= 360
	100%	→ $\frac{240}{40%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 600
Step 3:	Amount of money in the bag	→ (360 x $0.20) + (600 x $0.50)
		= $372

Answer: $1407

SOLUTION 1 :

Step 1:	20-cent coins	→ 85%
	50-cent coins	→ 100%
	Difference	→ 100% - 85%
		= 15%
Step 2:	15%	→ 315	(difference)
	1%	→ $\frac{315}{15%}$
	85%	→ $\frac{315}{15%}$ x $\frac{85%}{1}$	(number of 20-cent coins)
		= 1785
	100%	→ $\frac{315}{15%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 2100
Step 3:	Amount of money in the bag	→ (1785 x $0.20) + (2100 x $0.50)
		= $1407

10)

Answer: $1430

SOLUTION 1 :

Step 1:	20-cent coins	→ 75%
	50-cent coins	→ 100%
	Difference	→ 100% - 75%
		= 25%
Step 2:	25%	→ 550	(difference)
	1%	→ $\frac{550}{25%}$
	75%	→ $\frac{550}{25%}$ x $\frac{75%}{1}$	(number of 20-cent coins)
		= 1650
	100%	→ $\frac{550}{25%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 2200
Step 3:	Amount of money in the bag	→ (1650 x $0.20) + (2200 x $0.50)
		= $1430