Sasi Math (Revised for 1024)

Scroll:Percentage >> Percentage >> saq (2896)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A bag consists of a number of 20-cent and 50-cent coins. There are 75% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 100 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 60% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 200 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 85% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 285 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 70% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 390 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 55% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 630 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 75% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 50 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 60% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 720 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 85% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 375 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

A bag consists of a number of 20-cent and 50-cent coins. There are 70% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 300 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

10)

A bag consists of a number of 20-cent and 50-cent coins. There are 55% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 315 more 50-cent coins than 20-cent coins

$ ___

Answer:_______________

Answer: $260

SOLUTION 1 :

Step 1:	20-cent coins	→ 75%
	50-cent coins	→ 100%
	Difference	→ 100% - 75%
		= 25%
Step 2:	25%	→ 100	(difference)
	1%	→ $\frac{100}{25%}$
	75%	→ $\frac{100}{25%}$ x $\frac{75%}{1}$	(number of 20-cent coins)
		= 300
	100%	→ $\frac{100}{25%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 400
Step 3:	Amount of money in the bag	→ (300 x $0.20) + (400 x $0.50)
		= $260

Answer: $310

SOLUTION 1 :

Step 1:	20-cent coins	→ 60%
	50-cent coins	→ 100%
	Difference	→ 100% - 60%
		= 40%
Step 2:	40%	→ 200	(difference)
	1%	→ $\frac{200}{40%}$
	60%	→ $\frac{200}{40%}$ x $\frac{60%}{1}$	(number of 20-cent coins)
		= 300
	100%	→ $\frac{200}{40%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 500
Step 3:	Amount of money in the bag	→ (300 x $0.20) + (500 x $0.50)
		= $310

Answer: $1273

SOLUTION 1 :

Step 1:	20-cent coins	→ 85%
	50-cent coins	→ 100%
	Difference	→ 100% - 85%
		= 15%
Step 2:	15%	→ 285	(difference)
	1%	→ $\frac{285}{15%}$
	85%	→ $\frac{285}{15%}$ x $\frac{85%}{1}$	(number of 20-cent coins)
		= 1615
	100%	→ $\frac{285}{15%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1900
Step 3:	Amount of money in the bag	→ (1615 x $0.20) + (1900 x $0.50)
		= $1273

Answer: $832

SOLUTION 1 :

Step 1:	20-cent coins	→ 70%
	50-cent coins	→ 100%
	Difference	→ 100% - 70%
		= 30%
Step 2:	30%	→ 390	(difference)
	1%	→ $\frac{390}{30%}$
	70%	→ $\frac{390}{30%}$ x $\frac{70%}{1}$	(number of 20-cent coins)
		= 910
	100%	→ $\frac{390}{30%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1300
Step 3:	Amount of money in the bag	→ (910 x $0.20) + (1300 x $0.50)
		= $832

Answer: $854

SOLUTION 1 :

Step 1:	20-cent coins	→ 55%
	50-cent coins	→ 100%
	Difference	→ 100% - 55%
		= 45%
Step 2:	45%	→ 630	(difference)
	1%	→ $\frac{630}{45%}$
	55%	→ $\frac{630}{45%}$ x $\frac{55%}{1}$	(number of 20-cent coins)
		= 770
	100%	→ $\frac{630}{45%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1400
Step 3:	Amount of money in the bag	→ (770 x $0.20) + (1400 x $0.50)
		= $854

A bag consists of a number of 20-cent and 50-cent coins. There are 75% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 50 more 50-cent coins than 20-cent coins

Answer: $130

SOLUTION 1 :

Step 1:	20-cent coins	→ 75%
	50-cent coins	→ 100%
	Difference	→ 100% - 75%
		= 25%
Step 2:	25%	→ 50	(difference)
	1%	→ $\frac{50}{25%}$
	75%	→ $\frac{50}{25%}$ x $\frac{75%}{1}$	(number of 20-cent coins)
		= 150
	100%	→ $\frac{50}{25%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 200
Step 3:	Amount of money in the bag	→ (150 x $0.20) + (200 x $0.50)
		= $130

Answer: $1116

SOLUTION 1 :

Step 1:	20-cent coins	→ 60%
	50-cent coins	→ 100%
	Difference	→ 100% - 60%
		= 40%
Step 2:	40%	→ 720	(difference)
	1%	→ $\frac{720}{40%}$
	60%	→ $\frac{720}{40%}$ x $\frac{60%}{1}$	(number of 20-cent coins)
		= 1080
	100%	→ $\frac{720}{40%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1800
Step 3:	Amount of money in the bag	→ (1080 x $0.20) + (1800 x $0.50)
		= $1116

Answer: $1675

SOLUTION 1 :

Step 1:	20-cent coins	→ 85%
	50-cent coins	→ 100%
	Difference	→ 100% - 85%
		= 15%
Step 2:	15%	→ 375	(difference)
	1%	→ $\frac{375}{15%}$
	85%	→ $\frac{375}{15%}$ x $\frac{85%}{1}$	(number of 20-cent coins)
		= 2125
	100%	→ $\frac{375}{15%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 2500
Step 3:	Amount of money in the bag	→ (2125 x $0.20) + (2500 x $0.50)
		= $1675

Answer: $640

SOLUTION 1 :

Step 1:	20-cent coins	→ 70%
	50-cent coins	→ 100%
	Difference	→ 100% - 70%
		= 30%
Step 2:	30%	→ 300	(difference)
	1%	→ $\frac{300}{30%}$
	70%	→ $\frac{300}{30%}$ x $\frac{70%}{1}$	(number of 20-cent coins)
		= 700
	100%	→ $\frac{300}{30%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 1000
Step 3:	Amount of money in the bag	→ (700 x $0.20) + (1000 x $0.50)
		= $640

10)

Answer: $427

SOLUTION 1 :

Step 1:	20-cent coins	→ 55%
	50-cent coins	→ 100%
	Difference	→ 100% - 55%
		= 45%
Step 2:	45%	→ 315	(difference)
	1%	→ $\frac{315}{45%}$
	55%	→ $\frac{315}{45%}$ x $\frac{55%}{1}$	(number of 20-cent coins)
		= 385
	100%	→ $\frac{315}{45%}$ x $\frac{100%}{1}$	(number of 50-cent coins)
		= 700
Step 3:	Amount of money in the bag	→ (385 x $0.20) + (700 x $0.50)
		= $427