Sasi Math (Revised for 1024)

Scroll:Mensuration >> circumference of cylinder and cone >> ps (4133)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A circus tent is to be erected in the form in the from of a cone surmounted on a cylinder. The total height of the tent is 64m. Diameter of the base is 40m . and height of the cylinder is 18m. Find the cost of canvas needed to make the tent, if the cost of canvas is 11.50/ m2. (take π = $\frac{22}{7}$ ) (write answer the nearest round number)

18m

64m

40m

Answer:_______________

A circus tent is to be erected in the form in the from of a cone surmounted on a cylinder. The total height of the tent is 36m. Diameter of the base is 46m . and height of the cylinder is 24m. Find the cost of canvas needed to make the tent, if the cost of canvas is 10.50/ m2. (take π = $\frac{22}{7}$ ) (write answer the nearest round number)

24m

36m

46m

Answer:_______________

A circus tent is to be erected in the form in the from of a cone surmounted on a cylinder. The total height of the tent is 64m. Diameter of the base is 50m . and height of the cylinder is 30m. Find the cost of canvas needed to make the tent, if the cost of canvas is 14.50/ m2. (take π = $\frac{22}{7}$ ) (write answer the nearest round number)

30m

64m

50m

Answer:_______________

A circus tent is to be erected in the form in the from of a cone surmounted on a cylinder. The total height of the tent is 64m. Diameter of the base is 36m . and height of the cylinder is 21m. Find the cost of canvas needed to make the tent, if the cost of canvas is 13.50/ m2. (take π = $\frac{22}{7}$ ) (write answer the nearest round number)

21m

64m

36m

Answer:_______________

A circus tent is to be erected in the form in the from of a cone surmounted on a cylinder. The total height of the tent is 64m. Diameter of the base is 40m . and height of the cylinder is 21m. Find the cost of canvas needed to make the tent, if the cost of canvas is 13.50/ m2. (take π = $\frac{22}{7}$ ) (write answer the nearest round number)

21m

64m

40m

Answer:_______________

A circus tent is to be erected in the form in the from of a cone surmounted on a cylinder. The total height of the tent is 81m. Diameter of the base is 40m . and height of the cylinder is 15m. Find the cost of canvas needed to make the tent, if the cost of canvas is 10.50/ m2. (take π = $\frac{22}{7}$ ) (write answer the nearest round number)

15m

81m

40m

Answer:_______________

A circus tent is to be erected in the form in the from of a cone surmounted on a cylinder. The total height of the tent is 64m. Diameter of the base is 44m . and height of the cylinder is 27m. Find the cost of canvas needed to make the tent, if the cost of canvas is 13.50/ m2. (take π = $\frac{22}{7}$ ) (write answer the nearest round number)

27m

64m

44m

Answer:_______________

A circus tent is to be erected in the form in the from of a cone surmounted on a cylinder. The total height of the tent is 36m. Diameter of the base is 40m . and height of the cylinder is 18m. Find the cost of canvas needed to make the tent, if the cost of canvas is 10.50/ m2. (take π = $\frac{22}{7}$ ) (write answer the nearest round number)

18m

36m

40m

Answer:_______________

A circus tent is to be erected in the form in the from of a cone surmounted on a cylinder. The total height of the tent is 64m. Diameter of the base is 48m . and height of the cylinder is 27m. Find the cost of canvas needed to make the tent, if the cost of canvas is 15.50/ m2. (take π = $\frac{22}{7}$ ) (write answer the nearest round number)

27m

64m

48m

Answer:_______________

10)

A circus tent is to be erected in the form in the from of a cone surmounted on a cylinder. The total height of the tent is 81m. Diameter of the base is 50m . and height of the cylinder is 15m. Find the cost of canvas needed to make the tent, if the cost of canvas is 15.50/ m2. (take π = $\frac{22}{7}$ ) (write answer the nearest round number)

15m

81m

50m

Answer:_______________

18m

64m

40m

Answer: 51323

SOLUTION 1 :

Cylindrical part

Diameter, 2r = 40m

Radius, r = 20m

Height, (h) = 18m

Conical Part :

Radius, r = 20m

Height, h₁ = 64 - 20 = 44m

Slant height, l = √ h₁²+ r²

√ 44² + 20²

=√ 784 + 441

= √ 1225 = 35m.

Total area or the canvas needed

= CSA of the cylindrical part + CSA of the conical part

= 2πrh + πrl = πr(2h + l)

= $\frac{22}{7}$ x 20 x ( 2 x 18 + 35)

= $\frac{22}{7}$ x 20 x 71

= $\frac{31240}{7}$

Area of the canvas= 4462.86m²

Now, the cost of canvas per Sq.m = 11.50

Thus, the total cost of the canvas = 4462.86 x 11.50 = 51323.

24m

36m

46m

Answer: 62997

SOLUTION 1 :

Cylindrical part

Diameter, 2r = 46m

Radius, r = 23m

Height, (h) = 24m

Conical Part :

Radius, r = 23m

Height, h₁ = 36 - 23 = 13m

Slant height, l = √ h₁²+ r²

√ 13² + 23²

=√ 784 + 441

= √ 1225 = 35m.

Total area or the canvas needed

= CSA of the cylindrical part + CSA of the conical part

= 2πrh + πrl = πr(2h + l)

= $\frac{22}{7}$ x 23 x ( 2 x 24 + 35)

= $\frac{22}{7}$ x 23 x 83

= $\frac{41998}{7}$

Area of the canvas= 5999.71m²

Now, the cost of canvas per Sq.m = 10.50

Thus, the total cost of the canvas = 5999.71 x 10.50 = 62997.

30m

64m

50m

Answer: 108232

SOLUTION 1 :

Cylindrical part

Diameter, 2r = 50m

Radius, r = 25m

Height, (h) = 30m

Conical Part :

Radius, r = 25m

Height, h₁ = 64 - 25 = 39m

Slant height, l = √ h₁²+ r²

√ 39² + 25²

=√ 784 + 441

= √ 1225 = 35m.

Total area or the canvas needed

= CSA of the cylindrical part + CSA of the conical part

= 2πrh + πrl = πr(2h + l)

= $\frac{22}{7}$ x 25 x ( 2 x 30 + 35)

= $\frac{22}{7}$ x 25 x 95

= $\frac{52250}{7}$

Area of the canvas= 7464.29m²

Now, the cost of canvas per Sq.m = 14.50

Thus, the total cost of the canvas = 7464.29 x 14.50 = 108232.

21m

64m

36m

Answer: 58806

SOLUTION 1 :

Cylindrical part

Diameter, 2r = 36m

Radius, r = 18m

Height, (h) = 21m

Conical Part :

Radius, r = 18m

Height, h₁ = 64 - 18 = 46m

Slant height, l = √ h₁²+ r²

√ 46² + 18²

=√ 784 + 441

= √ 1225 = 35m.

Total area or the canvas needed

= CSA of the cylindrical part + CSA of the conical part

= 2πrh + πrl = πr(2h + l)

= $\frac{22}{7}$ x 18 x ( 2 x 21 + 35)

= $\frac{22}{7}$ x 18 x 77

= $\frac{30492}{7}$

Area of the canvas= 4356.00m²

Now, the cost of canvas per Sq.m = 13.50

Thus, the total cost of the canvas = 4356.00 x 13.50 = 58806.

21m

64m

40m

Answer: 65340

SOLUTION 1 :

Cylindrical part

Diameter, 2r = 40m

Radius, r = 20m

Height, (h) = 21m

Conical Part :

Radius, r = 20m

Height, h₁ = 64 - 20 = 44m

Slant height, l = √ h₁²+ r²

√ 44² + 20²

=√ 784 + 441

= √ 1225 = 35m.

Total area or the canvas needed

= CSA of the cylindrical part + CSA of the conical part

= 2πrh + πrl = πr(2h + l)

= $\frac{22}{7}$ x 20 x ( 2 x 21 + 35)

= $\frac{22}{7}$ x 20 x 77

= $\frac{33880}{7}$

Area of the canvas= 4840.00m²

Now, the cost of canvas per Sq.m = 13.50

Thus, the total cost of the canvas = 4840.00 x 13.50 = 65340.

15m

81m

40m

Answer: 42900

SOLUTION 1 :

Cylindrical part

Diameter, 2r = 40m

Radius, r = 20m

Height, (h) = 15m

Conical Part :

Radius, r = 20m

Height, h₁ = 81 - 20 = 61m

Slant height, l = √ h₁²+ r²

√ 61² + 20²

=√ 784 + 441

= √ 1225 = 35m.

Total area or the canvas needed

= CSA of the cylindrical part + CSA of the conical part

= 2πrh + πrl = πr(2h + l)

= $\frac{22}{7}$ x 20 x ( 2 x 15 + 35)

= $\frac{22}{7}$ x 20 x 65

= $\frac{28600}{7}$

Area of the canvas= 4085.71m²

Now, the cost of canvas per Sq.m = 10.50

Thus, the total cost of the canvas = 4085.71 x 10.50 = 42900.

27m

64m

44m

Answer: 83075

SOLUTION 1 :

Cylindrical part

Diameter, 2r = 44m

Radius, r = 22m

Height, (h) = 27m

Conical Part :

Radius, r = 22m

Height, h₁ = 64 - 22 = 42m

Slant height, l = √ h₁²+ r²

√ 42² + 22²

=√ 784 + 441

= √ 1225 = 35m.

Total area or the canvas needed

= CSA of the cylindrical part + CSA of the conical part

= 2πrh + πrl = πr(2h + l)

= $\frac{22}{7}$ x 22 x ( 2 x 27 + 35)

= $\frac{22}{7}$ x 22 x 89

= $\frac{43076}{7}$

Area of the canvas= 6153.71m²

Now, the cost of canvas per Sq.m = 13.50

Thus, the total cost of the canvas = 6153.71 x 13.50 = 83075.

18m

36m

40m

Answer: 46860

SOLUTION 1 :

Cylindrical part

Diameter, 2r = 40m

Radius, r = 20m

Height, (h) = 18m

Conical Part :

Radius, r = 20m

Height, h₁ = 36 - 20 = 16m

Slant height, l = √ h₁²+ r²

√ 16² + 20²

=√ 784 + 441

= √ 1225 = 35m.

Total area or the canvas needed

= CSA of the cylindrical part + CSA of the conical part

= 2πrh + πrl = πr(2h + l)

= $\frac{22}{7}$ x 20 x ( 2 x 18 + 35)

= $\frac{22}{7}$ x 20 x 71

= $\frac{31240}{7}$

Area of the canvas= 4462.86m²

Now, the cost of canvas per Sq.m = 10.50

Thus, the total cost of the canvas = 4462.86 x 10.50 = 46860.

27m

64m

48m

Answer: 104054

SOLUTION 1 :

Cylindrical part

Diameter, 2r = 48m

Radius, r = 24m

Height, (h) = 27m

Conical Part :

Radius, r = 24m

Height, h₁ = 64 - 24 = 40m

Slant height, l = √ h₁²+ r²

√ 40² + 24²

=√ 784 + 441

= √ 1225 = 35m.

Total area or the canvas needed

= CSA of the cylindrical part + CSA of the conical part

= 2πrh + πrl = πr(2h + l)

= $\frac{22}{7}$ x 24 x ( 2 x 27 + 35)

= $\frac{22}{7}$ x 24 x 89

= $\frac{46992}{7}$

Area of the canvas= 6713.14m²

Now, the cost of canvas per Sq.m = 15.50

Thus, the total cost of the canvas = 6713.14 x 15.50 = 104054.

10)

15m

81m

50m

Answer: 79161

SOLUTION 1 :

Cylindrical part

Diameter, 2r = 50m

Radius, r = 25m

Height, (h) = 15m

Conical Part :

Radius, r = 25m

Height, h₁ = 81 - 25 = 56m

Slant height, l = √ h₁²+ r²

√ 56² + 25²

=√ 784 + 441

= √ 1225 = 35m.

Total area or the canvas needed

= CSA of the cylindrical part + CSA of the conical part

= 2πrh + πrl = πr(2h + l)

= $\frac{22}{7}$ x 25 x ( 2 x 15 + 35)

= $\frac{22}{7}$ x 25 x 65

= $\frac{35750}{7}$

Area of the canvas= 5107.14m²

Now, the cost of canvas per Sq.m = 15.50

Thus, the total cost of the canvas = 5107.14 x 15.50 = 79161.