Written Instructions:
For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..
For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.
Leave your answers in the simplest form or correct to two decimal places.
| 1) Find the first five terms of the sequence given by a1 = 2, a2 = 8+a1 and an = 2an-1 + 7 for n > 2
Answer:_______________ |
| 2) Find the first five terms of the sequence given by a1 = 2, a2 = 6+a1 and an = 2an-1 + 4 for n > 2
Answer:_______________ |
| 3) Find the first five terms of the sequence given by a1 = 2, a2 = 9+a1 and an = 2an-1 + 6 for n > 2
Answer:_______________ |
| 4) Find the first five terms of the sequence given by a1 = 2, a2 = 6+a1 and an = 2an-1 + 8 for n > 2
Answer:_______________ |
| 5) Find the first five terms of the sequence given by a1 = 2, a2 = 3+a1 and an = 2an-1 + 4 for n > 2
Answer:_______________ |
| 6) Find the first five terms of the sequence given by a1 = 2, a2 = 12+a1 and an = 2an-1 + 4 for n > 2
Answer:_______________ |
| 7) Find the first five terms of the sequence given by a1 = 2, a2 = 6+a1 and an = 2an-1 + 7 for n > 2
Answer:_______________ |
| 8) Find the first five terms of the sequence given by a1 = 2, a2 = 11+a1 and an = 2an-1 + 7 for n > 2
Answer:_______________ |
| 9) Find the first five terms of the sequence given by a1 = 2, a2 = 12+a1 and an = 2an-1 + 6 for n > 2
Answer:_______________ |
| 10) Find the first five terms of the sequence given by a1 = 2, a2 = 13+a1 and an = 2an-1 + 8 for n > 2
Answer:_______________ |
| 1) Find the first five terms of the sequence given by a1 = 2, a2 = 8+a1 and an = 2an-1 + 7 for n > 2 Answer: 2,10,27,61,129 SOLUTION 1 : Given a1 = 2, a2 = 8 + a1 and an = 2an-1+7 a1 = 2 . a2 = 8 + 2 = 10 For n = 3, a3 = 2a3-1 + 7 = 2a2 + 7 = 2(10) + 7 = 27 For 4 = a4 = 2a4-1 + 7 = 2a3 + 7 = 2(27) + 7 = 61 For 5 = a5 = 2a5-1 + 7 = 2a4 + 7 = 2(61) + 7 = 129 Hence the first five terms of the sequence are 2,10,27,61,129. |
| 2) Find the first five terms of the sequence given by a1 = 2, a2 = 6+a1 and an = 2an-1 + 4 for n > 2 Answer: 2,8,20,44,92 SOLUTION 1 : Given a1 = 2, a2 = 6 + a1 and an = 2an-1+4 a1 = 2 . a2 = 6 + 2 = 8 For n = 3, a3 = 2a3-1 + 4 = 2a2 + 4 = 2(8) + 4 = 20 For 4 = a4 = 2a4-1 + 4 = 2a3 + 4 = 2(20) + 4 = 44 For 5 = a5 = 2a5-1 + 4 = 2a4 + 4 = 2(44) + 4 = 92 Hence the first five terms of the sequence are 2,8,20,44,92. |
| 3) Find the first five terms of the sequence given by a1 = 2, a2 = 9+a1 and an = 2an-1 + 6 for n > 2 Answer: 2,11,28,62,130 SOLUTION 1 : Given a1 = 2, a2 = 9 + a1 and an = 2an-1+6 a1 = 2 . a2 = 9 + 2 = 11 For n = 3, a3 = 2a3-1 + 6 = 2a2 + 6 = 2(11) + 6 = 28 For 4 = a4 = 2a4-1 + 6 = 2a3 + 6 = 2(28) + 6 = 62 For 5 = a5 = 2a5-1 + 6 = 2a4 + 6 = 2(62) + 6 = 130 Hence the first five terms of the sequence are 2,11,28,62,130. |
| 4) Find the first five terms of the sequence given by a1 = 2, a2 = 6+a1 and an = 2an-1 + 8 for n > 2 Answer: 2,8,24,56,120 SOLUTION 1 : Given a1 = 2, a2 = 6 + a1 and an = 2an-1+8 a1 = 2 . a2 = 6 + 2 = 8 For n = 3, a3 = 2a3-1 + 8 = 2a2 + 8 = 2(8) + 8 = 24 For 4 = a4 = 2a4-1 + 8 = 2a3 + 8 = 2(24) + 8 = 56 For 5 = a5 = 2a5-1 + 8 = 2a4 + 8 = 2(56) + 8 = 120 Hence the first five terms of the sequence are 2,8,24,56,120. |
| 5) Find the first five terms of the sequence given by a1 = 2, a2 = 3+a1 and an = 2an-1 + 4 for n > 2 Answer: 2,5,14,32,68 SOLUTION 1 : Given a1 = 2, a2 = 3 + a1 and an = 2an-1+4 a1 = 2 . a2 = 3 + 2 = 5 For n = 3, a3 = 2a3-1 + 4 = 2a2 + 4 = 2(5) + 4 = 14 For 4 = a4 = 2a4-1 + 4 = 2a3 + 4 = 2(14) + 4 = 32 For 5 = a5 = 2a5-1 + 4 = 2a4 + 4 = 2(32) + 4 = 68 Hence the first five terms of the sequence are 2,5,14,32,68. |
| 6) Find the first five terms of the sequence given by a1 = 2, a2 = 12+a1 and an = 2an-1 + 4 for n > 2 Answer: 2,14,32,68,140 SOLUTION 1 : Given a1 = 2, a2 = 12 + a1 and an = 2an-1+4 a1 = 2 . a2 = 12 + 2 = 14 For n = 3, a3 = 2a3-1 + 4 = 2a2 + 4 = 2(14) + 4 = 32 For 4 = a4 = 2a4-1 + 4 = 2a3 + 4 = 2(32) + 4 = 68 For 5 = a5 = 2a5-1 + 4 = 2a4 + 4 = 2(68) + 4 = 140 Hence the first five terms of the sequence are 2,14,32,68,140. |
| 7) Find the first five terms of the sequence given by a1 = 2, a2 = 6+a1 and an = 2an-1 + 7 for n > 2 Answer: 2,8,23,53,113 SOLUTION 1 : Given a1 = 2, a2 = 6 + a1 and an = 2an-1+7 a1 = 2 . a2 = 6 + 2 = 8 For n = 3, a3 = 2a3-1 + 7 = 2a2 + 7 = 2(8) + 7 = 23 For 4 = a4 = 2a4-1 + 7 = 2a3 + 7 = 2(23) + 7 = 53 For 5 = a5 = 2a5-1 + 7 = 2a4 + 7 = 2(53) + 7 = 113 Hence the first five terms of the sequence are 2,8,23,53,113. |
| 8) Find the first five terms of the sequence given by a1 = 2, a2 = 11+a1 and an = 2an-1 + 7 for n > 2 Answer: 2,13,33,73,153 SOLUTION 1 : Given a1 = 2, a2 = 11 + a1 and an = 2an-1+7 a1 = 2 . a2 = 11 + 2 = 13 For n = 3, a3 = 2a3-1 + 7 = 2a2 + 7 = 2(13) + 7 = 33 For 4 = a4 = 2a4-1 + 7 = 2a3 + 7 = 2(33) + 7 = 73 For 5 = a5 = 2a5-1 + 7 = 2a4 + 7 = 2(73) + 7 = 153 Hence the first five terms of the sequence are 2,13,33,73,153. |
| 9) Find the first five terms of the sequence given by a1 = 2, a2 = 12+a1 and an = 2an-1 + 6 for n > 2 Answer: 2,14,34,74,154 SOLUTION 1 : Given a1 = 2, a2 = 12 + a1 and an = 2an-1+6 a1 = 2 . a2 = 12 + 2 = 14 For n = 3, a3 = 2a3-1 + 6 = 2a2 + 6 = 2(14) + 6 = 34 For 4 = a4 = 2a4-1 + 6 = 2a3 + 6 = 2(34) + 6 = 74 For 5 = a5 = 2a5-1 + 6 = 2a4 + 6 = 2(74) + 6 = 154 Hence the first five terms of the sequence are 2,14,34,74,154. |
| 10) Find the first five terms of the sequence given by a1 = 2, a2 = 13+a1 and an = 2an-1 + 8 for n > 2 Answer: 2,15,38,84,176 SOLUTION 1 : Given a1 = 2, a2 = 13 + a1 and an = 2an-1+8 a1 = 2 . a2 = 13 + 2 = 15 For n = 3, a3 = 2a3-1 + 8 = 2a2 + 8 = 2(15) + 8 = 38 For 4 = a4 = 2a4-1 + 8 = 2a3 + 8 = 2(38) + 8 = 84 For 5 = a5 = 2a5-1 + 8 = 2a4 + 8 = 2(84) + 8 = 176 Hence the first five terms of the sequence are 2,15,38,84,176. |