Sasi Math (Revised for 1024)

Scroll:Sequences and series >> Arithmetric Progressions >> saq (4223)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

How many terms are there in the following Arrithmetic Progression

7, 11, 15.....127

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

17, 21, 25.....141

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

13, 18, 23.....128

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

20, 22, 24.....72

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

19, 21, 23.....79

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

14, 17, 20.....122

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

18, 22, 26.....186

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

16, 21, 26.....131

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

17, 21, 25.....109

Difference =

n =

Answer:_______________

10)

How many terms are there in the following Arrithmetic Progression

8, 10, 12.....60

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

7, 11, 15.....127

Difference = Answer: 4

n = Answer: 31

SOLUTION 1 :

Given A.P. is 7,11,15.....127

Here a = 7

d = 11 - 7

d = 4

t_n = a + (n-1)d

t_n = 127

a + (n-1)d = 127

t₃₁ = 7 + (n-1)4 = 127

= 7 + (4n- 4) = 127

= 4n + 3 = 127

= 4n = 127-3

4n = 124

n = $\frac{124}{4}$ = 31

How many terms are there in the following Arrithmetic Progression

17, 21, 25.....141

Difference = Answer: 4

n = Answer: 32

SOLUTION 1 :

Given A.P. is 17,21,25.....141

Here a = 17

d = 21 - 17

d = 4

t_n = a + (n-1)d

t_n = 141

a + (n-1)d = 141

t₃₂ = 17 + (n-1)4 = 141

= 17 + (4n- 4) = 141

= 4n + 13 = 141

= 4n = 141-13

4n = 128

n = $\frac{128}{4}$ = 32

How many terms are there in the following Arrithmetic Progression

13, 18, 23.....128

Difference = Answer: 5

n = Answer: 24

SOLUTION 1 :

Given A.P. is 13,18,23.....128

Here a = 13

d = 18 - 13

d = 5

t_n = a + (n-1)d

t_n = 128

a + (n-1)d = 128

t₂₄ = 13 + (n-1)5 = 128

= 13 + (5n- 5) = 128

= 5n + 8 = 128

= 5n = 128-8

5n = 120

n = $\frac{120}{5}$ = 24

How many terms are there in the following Arrithmetic Progression

20, 22, 24.....72

Difference = Answer: 2

n = Answer: 27

SOLUTION 1 :

Given A.P. is 20,22,24.....72

Here a = 20

d = 22 - 20

d = 2

t_n = a + (n-1)d

t_n = 72

a + (n-1)d = 72

t₂₇ = 20 + (n-1)2 = 72

= 20 + (2n- 2) = 72

= 2n + 18 = 72

= 2n = 72-18

2n = 54

n = $\frac{54}{2}$ = 27

How many terms are there in the following Arrithmetic Progression

19, 21, 23.....79

Difference = Answer: 2

n = Answer: 31

SOLUTION 1 :

Given A.P. is 19,21,23.....79

Here a = 19

d = 21 - 19

d = 2

t_n = a + (n-1)d

t_n = 79

a + (n-1)d = 79

t₃₁ = 19 + (n-1)2 = 79

= 19 + (2n- 2) = 79

= 2n + 17 = 79

= 2n = 79-17

2n = 62

n = $\frac{62}{2}$ = 31

How many terms are there in the following Arrithmetic Progression

14, 17, 20.....122

Difference = Answer: 3

n = Answer: 37

SOLUTION 1 :

Given A.P. is 14,17,20.....122

Here a = 14

d = 17 - 14

d = 3

t_n = a + (n-1)d

t_n = 122

a + (n-1)d = 122

t₃₇ = 14 + (n-1)3 = 122

= 14 + (3n- 3) = 122

= 3n + 11 = 122

= 3n = 122-11

3n = 111

n = $\frac{111}{3}$ = 37

How many terms are there in the following Arrithmetic Progression

18, 22, 26.....186

Difference = Answer: 4

n = Answer: 43

SOLUTION 1 :

Given A.P. is 18,22,26.....186

Here a = 18

d = 22 - 18

d = 4

t_n = a + (n-1)d

t_n = 186

a + (n-1)d = 186

t₄₃ = 18 + (n-1)4 = 186

= 18 + (4n- 4) = 186

= 4n + 14 = 186

= 4n = 186-14

4n = 172

n = $\frac{172}{4}$ = 43

How many terms are there in the following Arrithmetic Progression

16, 21, 26.....131

Difference = Answer: 5

n = Answer: 24

SOLUTION 1 :

Given A.P. is 16,21,26.....131

Here a = 16

d = 21 - 16

d = 5

t_n = a + (n-1)d

t_n = 131

a + (n-1)d = 131

t₂₄ = 16 + (n-1)5 = 131

= 16 + (5n- 5) = 131

= 5n + 11 = 131

= 5n = 131-11

5n = 120

n = $\frac{120}{5}$ = 24

How many terms are there in the following Arrithmetic Progression

17, 21, 25.....109

Difference = Answer: 4

n = Answer: 24

SOLUTION 1 :

Given A.P. is 17,21,25.....109

Here a = 17

d = 21 - 17

d = 4

t_n = a + (n-1)d

t_n = 109

a + (n-1)d = 109

t₂₄ = 17 + (n-1)4 = 109

= 17 + (4n- 4) = 109

= 4n + 13 = 109

= 4n = 109-13

4n = 96

n = $\frac{96}{4}$ = 24

10)

How many terms are there in the following Arrithmetic Progression

8, 10, 12.....60

Difference = Answer: 2

n = Answer: 27

SOLUTION 1 :

Given A.P. is 8,10,12.....60

Here a = 8

d = 10 - 8

d = 2

t_n = a + (n-1)d

t_n = 60

a + (n-1)d = 60

t₂₇ = 8 + (n-1)2 = 60

= 8 + (2n- 2) = 60

= 2n + 6 = 60

= 2n = 60-6

2n = 54

n = $\frac{54}{2}$ = 27