Sasi Math (Revised for 1024)

Scroll:Sequences and series >> Arithmetric Progressions >> saq (4223)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

How many terms are there in the following Arrithmetic Progression

16, 19, 22.....160

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

11, 13, 15.....109

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

9, 14, 19.....169

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

9, 14, 19.....239

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

18, 22, 26.....130

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

16, 20, 24.....208

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

7, 12, 17.....232

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

13, 18, 23.....148

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

13, 17, 21.....205

Difference =

n =

Answer:_______________

10)

How many terms are there in the following Arrithmetic Progression

19, 22, 25.....112

Difference =

n =

Answer:_______________

How many terms are there in the following Arrithmetic Progression

16, 19, 22.....160

Difference = Answer: 3

n = Answer: 49

SOLUTION 1 :

Given A.P. is 16,19,22.....160

Here a = 16

d = 19 - 16

d = 3

t_n = a + (n-1)d

t_n = 160

a + (n-1)d = 160

t₄₉ = 16 + (n-1)3 = 160

= 16 + (3n- 3) = 160

= 3n + 13 = 160

= 3n = 160-13

3n = 147

n = $\frac{147}{3}$ = 49

How many terms are there in the following Arrithmetic Progression

11, 13, 15.....109

Difference = Answer: 2

n = Answer: 50

SOLUTION 1 :

Given A.P. is 11,13,15.....109

Here a = 11

d = 13 - 11

d = 2

t_n = a + (n-1)d

t_n = 109

a + (n-1)d = 109

t₅₀ = 11 + (n-1)2 = 109

= 11 + (2n- 2) = 109

= 2n + 9 = 109

= 2n = 109-9

2n = 100

n = $\frac{100}{2}$ = 50

How many terms are there in the following Arrithmetic Progression

9, 14, 19.....169

Difference = Answer: 5

n = Answer: 33

SOLUTION 1 :

Given A.P. is 9,14,19.....169

Here a = 9

d = 14 - 9

d = 5

t_n = a + (n-1)d

t_n = 169

a + (n-1)d = 169

t₃₃ = 9 + (n-1)5 = 169

= 9 + (5n- 5) = 169

= 5n + 4 = 169

= 5n = 169-4

5n = 165

n = $\frac{165}{5}$ = 33

How many terms are there in the following Arrithmetic Progression

9, 14, 19.....239

Difference = Answer: 5

n = Answer: 47

SOLUTION 1 :

Given A.P. is 9,14,19.....239

Here a = 9

d = 14 - 9

d = 5

t_n = a + (n-1)d

t_n = 239

a + (n-1)d = 239

t₄₇ = 9 + (n-1)5 = 239

= 9 + (5n- 5) = 239

= 5n + 4 = 239

= 5n = 239-4

5n = 235

n = $\frac{235}{5}$ = 47

How many terms are there in the following Arrithmetic Progression

18, 22, 26.....130

Difference = Answer: 4

n = Answer: 29

SOLUTION 1 :

Given A.P. is 18,22,26.....130

Here a = 18

d = 22 - 18

d = 4

t_n = a + (n-1)d

t_n = 130

a + (n-1)d = 130

t₂₉ = 18 + (n-1)4 = 130

= 18 + (4n- 4) = 130

= 4n + 14 = 130

= 4n = 130-14

4n = 116

n = $\frac{116}{4}$ = 29

How many terms are there in the following Arrithmetic Progression

16, 20, 24.....208

Difference = Answer: 4

n = Answer: 49

SOLUTION 1 :

Given A.P. is 16,20,24.....208

Here a = 16

d = 20 - 16

d = 4

t_n = a + (n-1)d

t_n = 208

a + (n-1)d = 208

t₄₉ = 16 + (n-1)4 = 208

= 16 + (4n- 4) = 208

= 4n + 12 = 208

= 4n = 208-12

4n = 196

n = $\frac{196}{4}$ = 49

How many terms are there in the following Arrithmetic Progression

7, 12, 17.....232

Difference = Answer: 5

n = Answer: 46

SOLUTION 1 :

Given A.P. is 7,12,17.....232

Here a = 7

d = 12 - 7

d = 5

t_n = a + (n-1)d

t_n = 232

a + (n-1)d = 232

t₄₆ = 7 + (n-1)5 = 232

= 7 + (5n- 5) = 232

= 5n + 2 = 232

= 5n = 232-2

5n = 230

n = $\frac{230}{5}$ = 46

How many terms are there in the following Arrithmetic Progression

13, 18, 23.....148

Difference = Answer: 5

n = Answer: 28

SOLUTION 1 :

Given A.P. is 13,18,23.....148

Here a = 13

d = 18 - 13

d = 5

t_n = a + (n-1)d

t_n = 148

a + (n-1)d = 148

t₂₈ = 13 + (n-1)5 = 148

= 13 + (5n- 5) = 148

= 5n + 8 = 148

= 5n = 148-8

5n = 140

n = $\frac{140}{5}$ = 28

How many terms are there in the following Arrithmetic Progression

13, 17, 21.....205

Difference = Answer: 4

n = Answer: 49

SOLUTION 1 :

Given A.P. is 13,17,21.....205

Here a = 13

d = 17 - 13

d = 4

t_n = a + (n-1)d

t_n = 205

a + (n-1)d = 205

t₄₉ = 13 + (n-1)4 = 205

= 13 + (4n- 4) = 205

= 4n + 9 = 205

= 4n = 205-9

4n = 196

n = $\frac{196}{4}$ = 49

10)

How many terms are there in the following Arrithmetic Progression

19, 22, 25.....112

Difference = Answer: 3

n = Answer: 32

SOLUTION 1 :

Given A.P. is 19,22,25.....112

Here a = 19

d = 22 - 19

d = 3

t_n = a + (n-1)d

t_n = 112

a + (n-1)d = 112

t₃₂ = 19 + (n-1)3 = 112

= 19 + (3n- 3) = 112

= 3n + 16 = 112

= 3n = 112-16

3n = 96

n = $\frac{96}{3}$ = 32