Sasi Math (Revised for 1024)

Scroll:Probability >> probability >> saq (4232)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A box contains 5 Green, 3 Blue and 8 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour

Not Green in colour

Answer:_______________

A box contains 5 Green, 9 Blue and 8 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour

Not Green in colour

Answer:_______________

A box contains 7 Green, 3 Blue and 2 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour

Not Green in colour

Answer:_______________

A box contains 9 Green, 8 Blue and 2 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour

Not Green in colour

Answer:_______________

A box contains 6 Green, 4 Blue and 3 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour

Not Green in colour

Answer:_______________

A box contains 6 Green, 5 Blue and 2 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour

Not Green in colour

Answer:_______________

A box contains 3 Green, 5 Blue and 5 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour

Not Green in colour

Answer:_______________

A box contains 3 Green, 5 Blue and 4 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour

Not Green in colour

Answer:_______________

A box contains 8 Green, 3 Blue and 7 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour

Not Green in colour

Answer:_______________

10)

A box contains 9 Green, 4 Blue and 3 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour

Not Green in colour

Answer:_______________

A box contains 5 Green, 3 Blue and 8 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour Answer: $\frac{1}{2}$

Not Green in colour Answer: $\frac{11}{16}$

SOLUTION 1 :

A box contains 5 Green, 3 Blue and 8 red balls.

n(S) = 16

(i) Let A be the event of drawing a red balls.

n(A) = 8

P(A) =	n(A)	=	8	=	$\frac{1}{2}$
	n(S)		16

(ii) Not Green in colour

Let B be the event of drawing a ball, which is not Green in colour

A ball is not green in colour.

⇒ a ball is either Red or Blue.

n(B) = 11 [ 3 blue and 8 red balls ]

P(A) =	n(B)	=	11	=	$\frac{11}{16}$
	n(S)		16

A box contains 5 Green, 9 Blue and 8 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour Answer: $\frac{4}{11}$

Not Green in colour Answer: $\frac{17}{22}$

SOLUTION 1 :

A box contains 5 Green, 9 Blue and 8 red balls.

n(S) = 22

(i) Let A be the event of drawing a red balls.

n(A) = 8

P(A) =	n(A)	=	8	=	$\frac{4}{11}$
	n(S)		22

(ii) Not Green in colour

Let B be the event of drawing a ball, which is not Green in colour

A ball is not green in colour.

⇒ a ball is either Red or Blue.

n(B) = 17 [ 9 blue and 8 red balls ]

P(A) =	n(B)	=	17	=	$\frac{17}{22}$
	n(S)		22

A box contains 7 Green, 3 Blue and 2 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour Answer: $\frac{1}{6}$

Not Green in colour Answer: $\frac{5}{12}$

SOLUTION 1 :

A box contains 7 Green, 3 Blue and 2 red balls.

n(S) = 12

(i) Let A be the event of drawing a red balls.

n(A) = 2

P(A) =	n(A)	=	2	=	$\frac{1}{6}$
	n(S)		12

(ii) Not Green in colour

Let B be the event of drawing a ball, which is not Green in colour

A ball is not green in colour.

⇒ a ball is either Red or Blue.

n(B) = 5 [ 3 blue and 2 red balls ]

P(A) =	n(B)	=	5	=	$\frac{5}{12}$
	n(S)		12

A box contains 9 Green, 8 Blue and 2 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour Answer: $\frac{2}{19}$

Not Green in colour Answer: $\frac{10}{19}$

SOLUTION 1 :

A box contains 9 Green, 8 Blue and 2 red balls.

n(S) = 19

(i) Let A be the event of drawing a red balls.

n(A) = 2

P(A) =	n(A)	=	2	=	$\frac{2}{19}$
	n(S)		19

(ii) Not Green in colour

Let B be the event of drawing a ball, which is not Green in colour

A ball is not green in colour.

⇒ a ball is either Red or Blue.

n(B) = 10 [ 8 blue and 2 red balls ]

P(A) =	n(B)	=	10	=	$\frac{10}{19}$
	n(S)		19

A box contains 6 Green, 4 Blue and 3 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour Answer: $\frac{3}{13}$

Not Green in colour Answer: $\frac{7}{13}$

SOLUTION 1 :

A box contains 6 Green, 4 Blue and 3 red balls.

n(S) = 13

(i) Let A be the event of drawing a red balls.

n(A) = 3

P(A) =	n(A)	=	3	=	$\frac{3}{13}$
	n(S)		13

(ii) Not Green in colour

Let B be the event of drawing a ball, which is not Green in colour

A ball is not green in colour.

⇒ a ball is either Red or Blue.

n(B) = 7 [ 4 blue and 3 red balls ]

P(A) =	n(B)	=	7	=	$\frac{7}{13}$
	n(S)		13

A box contains 6 Green, 5 Blue and 2 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour Answer: $\frac{2}{13}$

Not Green in colour Answer: $\frac{7}{13}$

SOLUTION 1 :

A box contains 6 Green, 5 Blue and 2 red balls.

n(S) = 13

(i) Let A be the event of drawing a red balls.

n(A) = 2

P(A) =	n(A)	=	2	=	$\frac{2}{13}$
	n(S)		13

(ii) Not Green in colour

Let B be the event of drawing a ball, which is not Green in colour

A ball is not green in colour.

⇒ a ball is either Red or Blue.

n(B) = 7 [ 5 blue and 2 red balls ]

P(A) =	n(B)	=	7	=	$\frac{7}{13}$
	n(S)		13

A box contains 3 Green, 5 Blue and 5 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour Answer: $\frac{5}{13}$

Not Green in colour Answer: $\frac{10}{13}$

SOLUTION 1 :

A box contains 3 Green, 5 Blue and 5 red balls.

n(S) = 13

(i) Let A be the event of drawing a red balls.

n(A) = 5

P(A) =	n(A)	=	5	=	$\frac{5}{13}$
	n(S)		13

(ii) Not Green in colour

Let B be the event of drawing a ball, which is not Green in colour

A ball is not green in colour.

⇒ a ball is either Red or Blue.

n(B) = 10 [ 5 blue and 5 red balls ]

P(A) =	n(B)	=	10	=	$\frac{10}{13}$
	n(S)		13

A box contains 3 Green, 5 Blue and 4 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour Answer: $\frac{1}{3}$

Not Green in colour Answer: $\frac{3}{4}$

SOLUTION 1 :

A box contains 3 Green, 5 Blue and 4 red balls.

n(S) = 12

(i) Let A be the event of drawing a red balls.

n(A) = 4

P(A) =	n(A)	=	4	=	$\frac{1}{3}$
	n(S)		12

(ii) Not Green in colour

Let B be the event of drawing a ball, which is not Green in colour

A ball is not green in colour.

⇒ a ball is either Red or Blue.

n(B) = 9 [ 5 blue and 4 red balls ]

P(A) =	n(B)	=	9	=	$\frac{3}{4}$
	n(S)		12

A box contains 8 Green, 3 Blue and 7 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour Answer: $\frac{7}{18}$

Not Green in colour Answer: $\frac{5}{9}$

SOLUTION 1 :

A box contains 8 Green, 3 Blue and 7 red balls.

n(S) = 18

(i) Let A be the event of drawing a red balls.

n(A) = 7

P(A) =	n(A)	=	7	=	$\frac{7}{18}$
	n(S)		18

(ii) Not Green in colour

Let B be the event of drawing a ball, which is not Green in colour

A ball is not green in colour.

⇒ a ball is either Red or Blue.

n(B) = 10 [ 3 blue and 7 red balls ]

P(A) =	n(B)	=	10	=	$\frac{5}{9}$
	n(S)		18

10)

A box contains 9 Green, 4 Blue and 3 Red balls. A ball is drawn at random . Find the probality that the selected ball is

(I) Red in colour (ii) not Green in colour

Red in colour Answer: $\frac{3}{16}$

Not Green in colour Answer: $\frac{7}{16}$

SOLUTION 1 :

A box contains 9 Green, 4 Blue and 3 red balls.

n(S) = 16

(i) Let A be the event of drawing a red balls.

n(A) = 3

P(A) =	n(A)	=	3	=	$\frac{3}{16}$
	n(S)		16

(ii) Not Green in colour

Let B be the event of drawing a ball, which is not Green in colour

A ball is not green in colour.

⇒ a ball is either Red or Blue.

n(B) = 7 [ 4 blue and 3 red balls ]

P(A) =	n(B)	=	7	=	$\frac{7}{16}$
	n(S)		16