Scroll:Life mathematics >> profit and loss >> saq (4270)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.


 

1)  

 At what rate per annum will 368 amount to 613 in 2 years , when interest is being compounted annually

%


Answer:_______________




2)  

 At what rate per annum will 266 amount to 722 in 2 years , when interest is being compounted annually

%


Answer:_______________




3)  

 At what rate per annum will 296 amount to 777 in 2 years , when interest is being compounted annually

%


Answer:_______________




4)  

 At what rate per annum will 386 amount to 652 in 2 years , when interest is being compounted annually

%


Answer:_______________




5)  

 At what rate per annum will 297 amount to 785 in 2 years , when interest is being compounted annually

%


Answer:_______________




6)  

 At what rate per annum will 336 amount to 720 in 2 years , when interest is being compounted annually

%


Answer:_______________




7)  

 At what rate per annum will 381 amount to 724 in 2 years , when interest is being compounted annually

%


Answer:_______________




8)  

 At what rate per annum will 287 amount to 775 in 2 years , when interest is being compounted annually

%


Answer:_______________




9)  

 At what rate per annum will 345 amount to 789 in 2 years , when interest is being compounted annually

%


Answer:_______________




10)  

 At what rate per annum will 413 amount to 650 in 2 years , when interest is being compounted annually

%


Answer:_______________




 

1)  

 At what rate per annum will 368 amount to 613 in 2 years , when interest is being compounted annually

Answer: 67 %


SOLUTION 1 :

Given :

  Given  

        P   =   368

        A   =   613

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   613   =   368[1+(r÷100)]2    

613÷ 368 =  [1+(r÷100)]2  

1.6657608695652                = [1+(r÷100)]2

(1.6657608695652)½ = 1+(r÷100)

1.6657608695652            =   1+(r÷100)

(1.6657608695652)-1        =    r÷100

0.66576086956522 x 100  = r

67 %     =  r

 



2)  

 At what rate per annum will 266 amount to 722 in 2 years , when interest is being compounted annually

Answer: 171 %


SOLUTION 1 :

Given :

  Given  

        P   =   266

        A   =   722

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   722   =   266[1+(r÷100)]2    

722÷ 266 =  [1+(r÷100)]2  

2.7142857142857                = [1+(r÷100)]2

(2.7142857142857)½ = 1+(r÷100)

2.7142857142857            =   1+(r÷100)

(2.7142857142857)-1        =    r÷100

1.7142857142857 x 100  = r

171 %     =  r

 



3)  

 At what rate per annum will 296 amount to 777 in 2 years , when interest is being compounted annually

Answer: 163 %


SOLUTION 1 :

Given :

  Given  

        P   =   296

        A   =   777

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   777   =   296[1+(r÷100)]2    

777÷ 296 =  [1+(r÷100)]2  

2.625                = [1+(r÷100)]2

(2.625)½ = 1+(r÷100)

2.625            =   1+(r÷100)

(2.625)-1        =    r÷100

1.625 x 100  = r

163 %     =  r

 



4)  

 At what rate per annum will 386 amount to 652 in 2 years , when interest is being compounted annually

Answer: 69 %


SOLUTION 1 :

Given :

  Given  

        P   =   386

        A   =   652

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   652   =   386[1+(r÷100)]2    

652÷ 386 =  [1+(r÷100)]2  

1.6891191709845                = [1+(r÷100)]2

(1.6891191709845)½ = 1+(r÷100)

1.6891191709845            =   1+(r÷100)

(1.6891191709845)-1        =    r÷100

0.68911917098446 x 100  = r

69 %     =  r

 



5)  

 At what rate per annum will 297 amount to 785 in 2 years , when interest is being compounted annually

Answer: 164 %


SOLUTION 1 :

Given :

  Given  

        P   =   297

        A   =   785

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   785   =   297[1+(r÷100)]2    

785÷ 297 =  [1+(r÷100)]2  

2.6430976430976                = [1+(r÷100)]2

(2.6430976430976)½ = 1+(r÷100)

2.6430976430976            =   1+(r÷100)

(2.6430976430976)-1        =    r÷100

1.6430976430976 x 100  = r

164 %     =  r

 



6)  

 At what rate per annum will 336 amount to 720 in 2 years , when interest is being compounted annually

Answer: 114 %


SOLUTION 1 :

Given :

  Given  

        P   =   336

        A   =   720

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   720   =   336[1+(r÷100)]2    

720÷ 336 =  [1+(r÷100)]2  

2.1428571428571                = [1+(r÷100)]2

(2.1428571428571)½ = 1+(r÷100)

2.1428571428571            =   1+(r÷100)

(2.1428571428571)-1        =    r÷100

1.1428571428571 x 100  = r

114 %     =  r

 



7)  

 At what rate per annum will 381 amount to 724 in 2 years , when interest is being compounted annually

Answer: 90 %


SOLUTION 1 :

Given :

  Given  

        P   =   381

        A   =   724

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   724   =   381[1+(r÷100)]2    

724÷ 381 =  [1+(r÷100)]2  

1.9002624671916                = [1+(r÷100)]2

(1.9002624671916)½ = 1+(r÷100)

1.9002624671916            =   1+(r÷100)

(1.9002624671916)-1        =    r÷100

0.9002624671916 x 100  = r

90 %     =  r

 



8)  

 At what rate per annum will 287 amount to 775 in 2 years , when interest is being compounted annually

Answer: 170 %


SOLUTION 1 :

Given :

  Given  

        P   =   287

        A   =   775

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   775   =   287[1+(r÷100)]2    

775÷ 287 =  [1+(r÷100)]2  

2.7003484320557                = [1+(r÷100)]2

(2.7003484320557)½ = 1+(r÷100)

2.7003484320557            =   1+(r÷100)

(2.7003484320557)-1        =    r÷100

1.7003484320557 x 100  = r

170 %     =  r

 



9)  

 At what rate per annum will 345 amount to 789 in 2 years , when interest is being compounted annually

Answer: 129 %


SOLUTION 1 :

Given :

  Given  

        P   =   345

        A   =   789

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   789   =   345[1+(r÷100)]2    

789÷ 345 =  [1+(r÷100)]2  

2.2869565217391                = [1+(r÷100)]2

(2.2869565217391)½ = 1+(r÷100)

2.2869565217391            =   1+(r÷100)

(2.2869565217391)-1        =    r÷100

1.2869565217391 x 100  = r

129 %     =  r

 



10)  

 At what rate per annum will 413 amount to 650 in 2 years , when interest is being compounted annually

Answer: 57 %


SOLUTION 1 :

Given :

  Given  

        P   =   413

        A   =   650

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   650   =   413[1+(r÷100)]2    

650÷ 413 =  [1+(r÷100)]2  

1.5738498789346                = [1+(r÷100)]2

(1.5738498789346)½ = 1+(r÷100)

1.5738498789346            =   1+(r÷100)

(1.5738498789346)-1        =    r÷100

0.57384987893462 x 100  = r

57 %     =  r