Scroll:Life mathematics >> profit and loss >> saq (4270)


Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.



 

1)  

 At what rate per annum will 260 amount to 777 in 2 years , when interest is being compounted annually

%


Answer:_______________




2)  

 At what rate per annum will 241 amount to 645 in 2 years , when interest is being compounted annually

%


Answer:_______________




3)  

 At what rate per annum will 407 amount to 790 in 2 years , when interest is being compounted annually

%


Answer:_______________




4)  

 At what rate per annum will 275 amount to 796 in 2 years , when interest is being compounted annually

%


Answer:_______________




5)  

 At what rate per annum will 358 amount to 721 in 2 years , when interest is being compounted annually

%


Answer:_______________




6)  

 At what rate per annum will 329 amount to 691 in 2 years , when interest is being compounted annually

%


Answer:_______________




7)  

 At what rate per annum will 392 amount to 668 in 2 years , when interest is being compounted annually

%


Answer:_______________




8)  

 At what rate per annum will 461 amount to 774 in 2 years , when interest is being compounted annually

%


Answer:_______________




9)  

 At what rate per annum will 342 amount to 776 in 2 years , when interest is being compounted annually

%


Answer:_______________




10)  

 At what rate per annum will 489 amount to 652 in 2 years , when interest is being compounted annually

%


Answer:_______________




 

1)  

 At what rate per annum will 260 amount to 777 in 2 years , when interest is being compounted annually

Answer: 199 %


SOLUTION 1 :

Given :

  Given  

        P   =   260

        A   =   777

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   777   =   260[1+(r÷100)]2    

777÷ 260 =  [1+(r÷100)]2  

2.98846153846                = [1+(r÷100)]2

(2.98846153846)½ = 1+(r÷100)

2.98846153846            =   1+(r÷100)

(2.98846153846)-1        =    r÷100

1.98846153846 x 100  = r

199 %     =  r

 



2)  

 At what rate per annum will 241 amount to 645 in 2 years , when interest is being compounted annually

Answer: 168 %


SOLUTION 1 :

Given :

  Given  

        P   =   241

        A   =   645

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   645   =   241[1+(r÷100)]2    

645÷ 241 =  [1+(r÷100)]2  

2.67634854772                = [1+(r÷100)]2

(2.67634854772)½ = 1+(r÷100)

2.67634854772            =   1+(r÷100)

(2.67634854772)-1        =    r÷100

1.67634854772 x 100  = r

168 %     =  r

 



3)  

 At what rate per annum will 407 amount to 790 in 2 years , when interest is being compounted annually

Answer: 94 %


SOLUTION 1 :

Given :

  Given  

        P   =   407

        A   =   790

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   790   =   407[1+(r÷100)]2    

790÷ 407 =  [1+(r÷100)]2  

1.94103194103                = [1+(r÷100)]2

(1.94103194103)½ = 1+(r÷100)

1.94103194103            =   1+(r÷100)

(1.94103194103)-1        =    r÷100

0.941031941032 x 100  = r

94 %     =  r

 



4)  

 At what rate per annum will 275 amount to 796 in 2 years , when interest is being compounted annually

Answer: 189 %


SOLUTION 1 :

Given :

  Given  

        P   =   275

        A   =   796

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   796   =   275[1+(r÷100)]2    

796÷ 275 =  [1+(r÷100)]2  

2.89454545455                = [1+(r÷100)]2

(2.89454545455)½ = 1+(r÷100)

2.89454545455            =   1+(r÷100)

(2.89454545455)-1        =    r÷100

1.89454545455 x 100  = r

189 %     =  r

 



5)  

 At what rate per annum will 358 amount to 721 in 2 years , when interest is being compounted annually

Answer: 101 %


SOLUTION 1 :

Given :

  Given  

        P   =   358

        A   =   721

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   721   =   358[1+(r÷100)]2    

721÷ 358 =  [1+(r÷100)]2  

2.01396648045                = [1+(r÷100)]2

(2.01396648045)½ = 1+(r÷100)

2.01396648045            =   1+(r÷100)

(2.01396648045)-1        =    r÷100

1.01396648045 x 100  = r

101 %     =  r

 



6)  

 At what rate per annum will 329 amount to 691 in 2 years , when interest is being compounted annually

Answer: 110 %


SOLUTION 1 :

Given :

  Given  

        P   =   329

        A   =   691

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   691   =   329[1+(r÷100)]2    

691÷ 329 =  [1+(r÷100)]2  

2.10030395137                = [1+(r÷100)]2

(2.10030395137)½ = 1+(r÷100)

2.10030395137            =   1+(r÷100)

(2.10030395137)-1        =    r÷100

1.10030395137 x 100  = r

110 %     =  r

 



7)  

 At what rate per annum will 392 amount to 668 in 2 years , when interest is being compounted annually

Answer: 70 %


SOLUTION 1 :

Given :

  Given  

        P   =   392

        A   =   668

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   668   =   392[1+(r÷100)]2    

668÷ 392 =  [1+(r÷100)]2  

1.70408163265                = [1+(r÷100)]2

(1.70408163265)½ = 1+(r÷100)

1.70408163265            =   1+(r÷100)

(1.70408163265)-1        =    r÷100

0.704081632653 x 100  = r

70 %     =  r

 



8)  

 At what rate per annum will 461 amount to 774 in 2 years , when interest is being compounted annually

Answer: 68 %


SOLUTION 1 :

Given :

  Given  

        P   =   461

        A   =   774

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   774   =   461[1+(r÷100)]2    

774÷ 461 =  [1+(r÷100)]2  

1.67895878525                = [1+(r÷100)]2

(1.67895878525)½ = 1+(r÷100)

1.67895878525            =   1+(r÷100)

(1.67895878525)-1        =    r÷100

0.678958785249 x 100  = r

68 %     =  r

 



9)  

 At what rate per annum will 342 amount to 776 in 2 years , when interest is being compounted annually

Answer: 127 %


SOLUTION 1 :

Given :

  Given  

        P   =   342

        A   =   776

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   776   =   342[1+(r÷100)]2    

776÷ 342 =  [1+(r÷100)]2  

2.26900584795                = [1+(r÷100)]2

(2.26900584795)½ = 1+(r÷100)

2.26900584795            =   1+(r÷100)

(2.26900584795)-1        =    r÷100

1.26900584795 x 100  = r

127 %     =  r

 



10)  

 At what rate per annum will 489 amount to 652 in 2 years , when interest is being compounted annually

Answer: 33 %


SOLUTION 1 :

Given :

  Given  

        P   =   489

        A   =   652

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   652   =   489[1+(r÷100)]2    

652÷ 489 =  [1+(r÷100)]2  

1.33333333333                = [1+(r÷100)]2

(1.33333333333)½ = 1+(r÷100)

1.33333333333            =   1+(r÷100)

(1.33333333333)-1        =    r÷100

0.333333333333 x 100  = r

33 %     =  r