Scroll:Life mathematics >> profit and loss >> saq (4270)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.


 

1)  

 At what rate per annum will 213 amount to 650 in 2 years , when interest is being compounted annually

%


Answer:_______________




2)  

 At what rate per annum will 204 amount to 652 in 2 years , when interest is being compounted annually

%


Answer:_______________




3)  

 At what rate per annum will 375 amount to 648 in 2 years , when interest is being compounted annually

%


Answer:_______________




4)  

 At what rate per annum will 277 amount to 766 in 2 years , when interest is being compounted annually

%


Answer:_______________




5)  

 At what rate per annum will 385 amount to 624 in 2 years , when interest is being compounted annually

%


Answer:_______________




6)  

 At what rate per annum will 262 amount to 775 in 2 years , when interest is being compounted annually

%


Answer:_______________




7)  

 At what rate per annum will 337 amount to 684 in 2 years , when interest is being compounted annually

%


Answer:_______________




8)  

 At what rate per annum will 263 amount to 701 in 2 years , when interest is being compounted annually

%


Answer:_______________




9)  

 At what rate per annum will 263 amount to 649 in 2 years , when interest is being compounted annually

%


Answer:_______________




10)  

 At what rate per annum will 339 amount to 692 in 2 years , when interest is being compounted annually

%


Answer:_______________




 

1)  

 At what rate per annum will 213 amount to 650 in 2 years , when interest is being compounted annually

Answer: 205 %


SOLUTION 1 :

Given :

  Given  

        P   =   213

        A   =   650

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   650   =   213[1+(r÷100)]2    

650÷ 213 =  [1+(r÷100)]2  

3.0516431924883                = [1+(r÷100)]2

(3.0516431924883)½ = 1+(r÷100)

3.0516431924883            =   1+(r÷100)

(3.0516431924883)-1        =    r÷100

2.0516431924883 x 100  = r

205 %     =  r

 



2)  

 At what rate per annum will 204 amount to 652 in 2 years , when interest is being compounted annually

Answer: 220 %


SOLUTION 1 :

Given :

  Given  

        P   =   204

        A   =   652

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   652   =   204[1+(r÷100)]2    

652÷ 204 =  [1+(r÷100)]2  

3.1960784313725                = [1+(r÷100)]2

(3.1960784313725)½ = 1+(r÷100)

3.1960784313725            =   1+(r÷100)

(3.1960784313725)-1        =    r÷100

2.1960784313725 x 100  = r

220 %     =  r

 



3)  

 At what rate per annum will 375 amount to 648 in 2 years , when interest is being compounted annually

Answer: 73 %


SOLUTION 1 :

Given :

  Given  

        P   =   375

        A   =   648

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   648   =   375[1+(r÷100)]2    

648÷ 375 =  [1+(r÷100)]2  

1.728                = [1+(r÷100)]2

(1.728)½ = 1+(r÷100)

1.728            =   1+(r÷100)

(1.728)-1        =    r÷100

0.728 x 100  = r

73 %     =  r

 



4)  

 At what rate per annum will 277 amount to 766 in 2 years , when interest is being compounted annually

Answer: 177 %


SOLUTION 1 :

Given :

  Given  

        P   =   277

        A   =   766

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   766   =   277[1+(r÷100)]2    

766÷ 277 =  [1+(r÷100)]2  

2.7653429602888                = [1+(r÷100)]2

(2.7653429602888)½ = 1+(r÷100)

2.7653429602888            =   1+(r÷100)

(2.7653429602888)-1        =    r÷100

1.7653429602888 x 100  = r

177 %     =  r

 



5)  

 At what rate per annum will 385 amount to 624 in 2 years , when interest is being compounted annually

Answer: 62 %


SOLUTION 1 :

Given :

  Given  

        P   =   385

        A   =   624

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   624   =   385[1+(r÷100)]2    

624÷ 385 =  [1+(r÷100)]2  

1.6207792207792                = [1+(r÷100)]2

(1.6207792207792)½ = 1+(r÷100)

1.6207792207792            =   1+(r÷100)

(1.6207792207792)-1        =    r÷100

0.62077922077922 x 100  = r

62 %     =  r

 



6)  

 At what rate per annum will 262 amount to 775 in 2 years , when interest is being compounted annually

Answer: 196 %


SOLUTION 1 :

Given :

  Given  

        P   =   262

        A   =   775

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   775   =   262[1+(r÷100)]2    

775÷ 262 =  [1+(r÷100)]2  

2.9580152671756                = [1+(r÷100)]2

(2.9580152671756)½ = 1+(r÷100)

2.9580152671756            =   1+(r÷100)

(2.9580152671756)-1        =    r÷100

1.9580152671756 x 100  = r

196 %     =  r

 



7)  

 At what rate per annum will 337 amount to 684 in 2 years , when interest is being compounted annually

Answer: 103 %


SOLUTION 1 :

Given :

  Given  

        P   =   337

        A   =   684

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   684   =   337[1+(r÷100)]2    

684÷ 337 =  [1+(r÷100)]2  

2.0296735905045                = [1+(r÷100)]2

(2.0296735905045)½ = 1+(r÷100)

2.0296735905045            =   1+(r÷100)

(2.0296735905045)-1        =    r÷100

1.0296735905045 x 100  = r

103 %     =  r

 



8)  

 At what rate per annum will 263 amount to 701 in 2 years , when interest is being compounted annually

Answer: 167 %


SOLUTION 1 :

Given :

  Given  

        P   =   263

        A   =   701

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   701   =   263[1+(r÷100)]2    

701÷ 263 =  [1+(r÷100)]2  

2.6653992395437                = [1+(r÷100)]2

(2.6653992395437)½ = 1+(r÷100)

2.6653992395437            =   1+(r÷100)

(2.6653992395437)-1        =    r÷100

1.6653992395437 x 100  = r

167 %     =  r

 



9)  

 At what rate per annum will 263 amount to 649 in 2 years , when interest is being compounted annually

Answer: 147 %


SOLUTION 1 :

Given :

  Given  

        P   =   263

        A   =   649

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   649   =   263[1+(r÷100)]2    

649÷ 263 =  [1+(r÷100)]2  

2.467680608365                = [1+(r÷100)]2

(2.467680608365)½ = 1+(r÷100)

2.467680608365            =   1+(r÷100)

(2.467680608365)-1        =    r÷100

1.467680608365 x 100  = r

147 %     =  r

 



10)  

 At what rate per annum will 339 amount to 692 in 2 years , when interest is being compounted annually

Answer: 104 %


SOLUTION 1 :

Given :

  Given  

        P   =   339

        A   =   692

        n   =   2 years

        r    =  

       A   =   P[1+(r÷100)]n

   692   =   339[1+(r÷100)]2    

692÷ 339 =  [1+(r÷100)]2  

2.0412979351032                = [1+(r÷100)]2

(2.0412979351032)½ = 1+(r÷100)

2.0412979351032            =   1+(r÷100)

(2.0412979351032)-1        =    r÷100

1.0412979351032 x 100  = r

104 %     =  r