Scroll:Life mathematics >> profit and loss >> saq (4273)


Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.



 

1)  

 The population of a village increases at the rate of 2% every year. If the present population is 33212,what will be the population after 2 years


Answer:_______________




2)  

 The population of a village increases at the rate of 3% every year. If the present population is 20125,what will be the population after 4 years


Answer:_______________




3)  

 The population of a village increases at the rate of 3% every year. If the present population is 36536,what will be the population after 4 years


Answer:_______________




4)  

 The population of a village increases at the rate of 3% every year. If the present population is 46599,what will be the population after 4 years


Answer:_______________




5)  

 The population of a village increases at the rate of 6% every year. If the present population is 13843,what will be the population after 2 years


Answer:_______________




6)  

 The population of a village increases at the rate of 6% every year. If the present population is 12243,what will be the population after 4 years


Answer:_______________




7)  

 The population of a village increases at the rate of 3% every year. If the present population is 19025,what will be the population after 4 years


Answer:_______________




8)  

 The population of a village increases at the rate of 4% every year. If the present population is 26758,what will be the population after 4 years


Answer:_______________




9)  

 The population of a village increases at the rate of 4% every year. If the present population is 17030,what will be the population after 4 years


Answer:_______________




10)  

 The population of a village increases at the rate of 2% every year. If the present population is 45190,what will be the population after 3 years


Answer:_______________




 

1)  

 The population of a village increases at the rate of 2% every year. If the present population is 33212,what will be the population after 2 years

Answer: 34554


SOLUTION 1 :

Given  :

Present population P  =  33212

Rate of increase r       =   2%

Number of years n     =   2 years

The population after n years  =   P[1+(r÷100)]n

                                               =  33212[1+(2÷100)]2

                                               =  33212[1+0.02]2

                                               =  33212(1.02)2

                                               = 33212 x 1.0404

                                               = 34554



2)  

 The population of a village increases at the rate of 3% every year. If the present population is 20125,what will be the population after 4 years

Answer: 22651


SOLUTION 1 :

Given  :

Present population P  =  20125

Rate of increase r       =   3%

Number of years n     =   4 years

The population after n years  =   P[1+(r÷100)]n

                                               =  20125[1+(3÷100)]4

                                               =  20125[1+0.03]4

                                               =  20125(1.03)4

                                               = 20125 x 1.12550881

                                               = 22651



3)  

 The population of a village increases at the rate of 3% every year. If the present population is 36536,what will be the population after 4 years

Answer: 41122


SOLUTION 1 :

Given  :

Present population P  =  36536

Rate of increase r       =   3%

Number of years n     =   4 years

The population after n years  =   P[1+(r÷100)]n

                                               =  36536[1+(3÷100)]4

                                               =  36536[1+0.03]4

                                               =  36536(1.03)4

                                               = 36536 x 1.12550881

                                               = 41122



4)  

 The population of a village increases at the rate of 3% every year. If the present population is 46599,what will be the population after 4 years

Answer: 52448


SOLUTION 1 :

Given  :

Present population P  =  46599

Rate of increase r       =   3%

Number of years n     =   4 years

The population after n years  =   P[1+(r÷100)]n

                                               =  46599[1+(3÷100)]4

                                               =  46599[1+0.03]4

                                               =  46599(1.03)4

                                               = 46599 x 1.12550881

                                               = 52448



5)  

 The population of a village increases at the rate of 6% every year. If the present population is 13843,what will be the population after 2 years

Answer: 15554


SOLUTION 1 :

Given  :

Present population P  =  13843

Rate of increase r       =   6%

Number of years n     =   2 years

The population after n years  =   P[1+(r÷100)]n

                                               =  13843[1+(6÷100)]2

                                               =  13843[1+0.06]2

                                               =  13843(1.06)2

                                               = 13843 x 1.1236

                                               = 15554



6)  

 The population of a village increases at the rate of 6% every year. If the present population is 12243,what will be the population after 4 years

Answer: 15457


SOLUTION 1 :

Given  :

Present population P  =  12243

Rate of increase r       =   6%

Number of years n     =   4 years

The population after n years  =   P[1+(r÷100)]n

                                               =  12243[1+(6÷100)]4

                                               =  12243[1+0.06]4

                                               =  12243(1.06)4

                                               = 12243 x 1.26247696

                                               = 15457



7)  

 The population of a village increases at the rate of 3% every year. If the present population is 19025,what will be the population after 4 years

Answer: 21413


SOLUTION 1 :

Given  :

Present population P  =  19025

Rate of increase r       =   3%

Number of years n     =   4 years

The population after n years  =   P[1+(r÷100)]n

                                               =  19025[1+(3÷100)]4

                                               =  19025[1+0.03]4

                                               =  19025(1.03)4

                                               = 19025 x 1.12550881

                                               = 21413



8)  

 The population of a village increases at the rate of 4% every year. If the present population is 26758,what will be the population after 4 years

Answer: 31303


SOLUTION 1 :

Given  :

Present population P  =  26758

Rate of increase r       =   4%

Number of years n     =   4 years

The population after n years  =   P[1+(r÷100)]n

                                               =  26758[1+(4÷100)]4

                                               =  26758[1+0.04]4

                                               =  26758(1.04)4

                                               = 26758 x 1.16985856

                                               = 31303



9)  

 The population of a village increases at the rate of 4% every year. If the present population is 17030,what will be the population after 4 years

Answer: 19923


SOLUTION 1 :

Given  :

Present population P  =  17030

Rate of increase r       =   4%

Number of years n     =   4 years

The population after n years  =   P[1+(r÷100)]n

                                               =  17030[1+(4÷100)]4

                                               =  17030[1+0.04]4

                                               =  17030(1.04)4

                                               = 17030 x 1.16985856

                                               = 19923



10)  

 The population of a village increases at the rate of 2% every year. If the present population is 45190,what will be the population after 3 years

Answer: 47956


SOLUTION 1 :

Given  :

Present population P  =  45190

Rate of increase r       =   2%

Number of years n     =   3 years

The population after n years  =   P[1+(r÷100)]n

                                               =  45190[1+(2÷100)]3

                                               =  45190[1+0.02]3

                                               =  45190(1.02)3

                                               = 45190 x 1.061208

                                               = 47956