Sasi Math (Revised for 1024)

Scroll:Life mathematics >> profit and loss >> saq (4310)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Imran deposits 305 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 246 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 567 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 531 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 526 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 489 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 214 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 406 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 300 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

10)

Imran deposits 596 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 305 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 7777.5

SOLUTION 1 :

Given:

P = 305

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (305 x 25 x $\frac{6)}{100}$

= $\frac{45750}{100}$

= 457.5

A = (P x n) +I

= (305 x 24) + 457.5

= 7320 + 457.5

= 7777.5

Imran deposits 246 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 6273

SOLUTION 1 :

Given:

P = 246

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (246 x 25 x $\frac{6)}{100}$

= $\frac{36900}{100}$

= 369

A = (P x n) +I

= (246 x 24) + 369

= 5904 + 369

= 6273

Imran deposits 567 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 14316.75

SOLUTION 1 :

Given:

P = 567

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (567 x 25 x $\frac{5)}{100}$

= $\frac{70875}{100}$

= 708.75

A = (P x n) +I

= (567 x 24) + 708.75

= 13608 + 708.75

= 14316.75

Imran deposits 531 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 13009.5

SOLUTION 1 :

Given:

P = 531

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (531 x 25 x $\frac{2)}{100}$

= $\frac{26550}{100}$

= 265.5

A = (P x n) +I

= (531 x 24) + 265.5

= 12744 + 265.5

= 13009.5

Imran deposits 526 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 13281.5

SOLUTION 1 :

Given:

P = 526

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (526 x 25 x $\frac{5)}{100}$

= $\frac{65750}{100}$

= 657.5

A = (P x n) +I

= (526 x 24) + 657.5

= 12624 + 657.5

= 13281.5

Imran deposits 489 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 11980.5

SOLUTION 1 :

Given:

P = 489

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (489 x 25 x $\frac{2)}{100}$

= $\frac{24450}{100}$

= 244.5

A = (P x n) +I

= (489 x 24) + 244.5

= 11736 + 244.5

= 11980.5

Imran deposits 214 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 5243

SOLUTION 1 :

Given:

P = 214

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (214 x 25 x $\frac{2)}{100}$

= $\frac{10700}{100}$

= 107

A = (P x n) +I

= (214 x 24) + 107

= 5136 + 107

= 5243

Imran deposits 406 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 10251.5

SOLUTION 1 :

Given:

P = 406

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (406 x 25 x $\frac{5)}{100}$

= $\frac{50750}{100}$

= 507.5

A = (P x n) +I

= (406 x 24) + 507.5

= 9744 + 507.5

= 10251.5

Imran deposits 300 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 7350

SOLUTION 1 :

Given:

P = 300

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (300 x 25 x $\frac{2)}{100}$

= $\frac{15000}{100}$

= 150

A = (P x n) +I

= (300 x 24) + 150

= 7200 + 150

= 7350

10)

Imran deposits 596 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 15049

SOLUTION 1 :

Given:

P = 596

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (596 x 25 x $\frac{5)}{100}$

= $\frac{74500}{100}$

= 745

A = (P x n) +I

= (596 x 24) + 745

= 14304 + 745

= 15049