Sasi Math (Revised for 1024)

Scroll:Life mathematics >> profit and loss >> saq (4310)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Imran deposits 493 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 546 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 384 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 425 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 302 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 588 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 316 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 253 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 521 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

10)

Imran deposits 365 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 493 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer: 12201.75

SOLUTION 1 :

Given:

P = 493

n = 2 years = 24month

r = 3%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (493 x 25 x $\frac{3)}{100}$

= $\frac{36975}{100}$

= 369.75

A = (P x n) +I

= (493 x 24) + 369.75

= 11832 + 369.75

= 12201.75

Imran deposits 546 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 13377

SOLUTION 1 :

Given:

P = 546

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (546 x 25 x $\frac{2)}{100}$

= $\frac{27300}{100}$

= 273

A = (P x n) +I

= (546 x 24) + 273

= 13104 + 273

= 13377

Imran deposits 384 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer: 9600

SOLUTION 1 :

Given:

P = 384

n = 2 years = 24month

r = 4%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (384 x 25 x $\frac{4)}{100}$

= $\frac{38400}{100}$

= 384

A = (P x n) +I

= (384 x 24) + 384

= 9216 + 384

= 9600

Imran deposits 425 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 10731.25

SOLUTION 1 :

Given:

P = 425

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (425 x 25 x $\frac{5)}{100}$

= $\frac{53125}{100}$

= 531.25

A = (P x n) +I

= (425 x 24) + 531.25

= 10200 + 531.25

= 10731.25

Imran deposits 302 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 7701

SOLUTION 1 :

Given:

P = 302

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (302 x 25 x $\frac{6)}{100}$

= $\frac{45300}{100}$

= 453

A = (P x n) +I

= (302 x 24) + 453

= 7248 + 453

= 7701

Imran deposits 588 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 14994

SOLUTION 1 :

Given:

P = 588

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (588 x 25 x $\frac{6)}{100}$

= $\frac{88200}{100}$

= 882

A = (P x n) +I

= (588 x 24) + 882

= 14112 + 882

= 14994

Imran deposits 316 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 7742

SOLUTION 1 :

Given:

P = 316

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (316 x 25 x $\frac{2)}{100}$

= $\frac{15800}{100}$

= 158

A = (P x n) +I

= (316 x 24) + 158

= 7584 + 158

= 7742

Imran deposits 253 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 6198.5

SOLUTION 1 :

Given:

P = 253

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (253 x 25 x $\frac{2)}{100}$

= $\frac{12650}{100}$

= 126.5

A = (P x n) +I

= (253 x 24) + 126.5

= 6072 + 126.5

= 6198.5

Imran deposits 521 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 12764.5

SOLUTION 1 :

Given:

P = 521

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (521 x 25 x $\frac{2)}{100}$

= $\frac{26050}{100}$

= 260.5

A = (P x n) +I

= (521 x 24) + 260.5

= 12504 + 260.5

= 12764.5

10)

Imran deposits 365 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 9307.5

SOLUTION 1 :

Given:

P = 365

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (365 x 25 x $\frac{6)}{100}$

= $\frac{54750}{100}$

= 547.5

A = (P x n) +I

= (365 x 24) + 547.5

= 8760 + 547.5

= 9307.5