Sasi Math (Revised for 1024)

Scroll:Life mathematics >> profit and loss >> saq (4310)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Imran deposits 273 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 443 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 437 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 469 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 267 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 216 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 363 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 407 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 387 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer:_______________

10)

Imran deposits 546 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer:_______________

Imran deposits 273 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 6893.25

SOLUTION 1 :

Given:

P = 273

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (273 x 25 x $\frac{5)}{100}$

= $\frac{34125}{100}$

= 341.25

A = (P x n) +I

= (273 x 24) + 341.25

= 6552 + 341.25

= 6893.25

Imran deposits 443 per month in a post office as R.D. for 2 years. If the rate of interest is 4% , find the amount he will receive at the end of 2 years.

Answer: 11075

SOLUTION 1 :

Given:

P = 443

n = 2 years = 24month

r = 4%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (443 x 25 x $\frac{4)}{100}$

= $\frac{44300}{100}$

= 443

A = (P x n) +I

= (443 x 24) + 443

= 10632 + 443

= 11075

Imran deposits 437 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer: 10815.75

SOLUTION 1 :

Given:

P = 437

n = 2 years = 24month

r = 3%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (437 x 25 x $\frac{3)}{100}$

= $\frac{32775}{100}$

= 327.75

A = (P x n) +I

= (437 x 24) + 327.75

= 10488 + 327.75

= 10815.75

Imran deposits 469 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 11842.25

SOLUTION 1 :

Given:

P = 469

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (469 x 25 x $\frac{5)}{100}$

= $\frac{58625}{100}$

= 586.25

A = (P x n) +I

= (469 x 24) + 586.25

= 11256 + 586.25

= 11842.25

Imran deposits 267 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 6741.75

SOLUTION 1 :

Given:

P = 267

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (267 x 25 x $\frac{5)}{100}$

= $\frac{33375}{100}$

= 333.75

A = (P x n) +I

= (267 x 24) + 333.75

= 6408 + 333.75

= 6741.75

Imran deposits 216 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 5292

SOLUTION 1 :

Given:

P = 216

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (216 x 25 x $\frac{2)}{100}$

= $\frac{10800}{100}$

= 108

A = (P x n) +I

= (216 x 24) + 108

= 5184 + 108

= 5292

Imran deposits 363 per month in a post office as R.D. for 2 years. If the rate of interest is 2% , find the amount he will receive at the end of 2 years.

Answer: 8893.5

SOLUTION 1 :

Given:

P = 363

n = 2 years = 24month

r = 2%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (363 x 25 x $\frac{2)}{100}$

= $\frac{18150}{100}$

= 181.5

A = (P x n) +I

= (363 x 24) + 181.5

= 8712 + 181.5

= 8893.5

Imran deposits 407 per month in a post office as R.D. for 2 years. If the rate of interest is 3% , find the amount he will receive at the end of 2 years.

Answer: 10073.25

SOLUTION 1 :

Given:

P = 407

n = 2 years = 24month

r = 3%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (407 x 25 x $\frac{3)}{100}$

= $\frac{30525}{100}$

= 305.25

A = (P x n) +I

= (407 x 24) + 305.25

= 9768 + 305.25

= 10073.25

Imran deposits 387 per month in a post office as R.D. for 2 years. If the rate of interest is 6% , find the amount he will receive at the end of 2 years.

Answer: 9868.5

SOLUTION 1 :

Given:

P = 387

n = 2 years = 24month

r = 6%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (387 x 25 x $\frac{6)}{100}$

= $\frac{58050}{100}$

= 580.5

A = (P x n) +I

= (387 x 24) + 580.5

= 9288 + 580.5

= 9868.5

10)

Imran deposits 546 per month in a post office as R.D. for 2 years. If the rate of interest is 5% , find the amount he will receive at the end of 2 years.

Answer: 13786.5

SOLUTION 1 :

Given:

P = 546

n = 2 years = 24month

r = 5%

For R.D ,

N = $\frac{1}{12}$ x [n(n+1)]/2

= $\frac{1}{12}$ x (24 x $\frac{25)}{2}$

= $\frac{1}{12}$ x $\frac{(600}{2)}$

= $\frac{1}{12}$ x 300

= 25

I = $\frac{Pnr}{100}$

= (546 x 25 x $\frac{5)}{100}$

= $\frac{68250}{100}$

= 682.5

A = (P x n) +I

= (546 x 24) + 682.5

= 13104 + 682.5

= 13786.5