Scroll:Life Mathematics >> Life Mathematics - variation >> saq (4336)


Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.



 

1)  

 A troop has provisions for 123  soldiers for 15 days. How many soldiers leave the troop so that the provisions may last for 24 days

soldiers


Answer:_______________




2)  

 A troop has provisions for 171  soldiers for 15 days. How many soldiers leave the troop so that the provisions may last for 28 days

soldiers


Answer:_______________




3)  

 A troop has provisions for 119  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 30 days

soldiers


Answer:_______________




4)  

 A troop has provisions for 136  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 21 days

soldiers


Answer:_______________




5)  

 A troop has provisions for 188  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 25 days

soldiers


Answer:_______________




6)  

 A troop has provisions for 156  soldiers for 12 days. How many soldiers leave the troop so that the provisions may last for 22 days

soldiers


Answer:_______________




7)  

 A troop has provisions for 134  soldiers for 13 days. How many soldiers leave the troop so that the provisions may last for 24 days

soldiers


Answer:_______________




8)  

 A troop has provisions for 108  soldiers for 11 days. How many soldiers leave the troop so that the provisions may last for 26 days

soldiers


Answer:_______________




9)  

 A troop has provisions for 162  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 26 days

soldiers


Answer:_______________




10)  

 A troop has provisions for 169  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 28 days

soldiers


Answer:_______________




 

1)  

 A troop has provisions for 123  soldiers for 15 days. How many soldiers leave the troop so that the provisions may last for 24 days

Answer: 77 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       123  (y)      15 (x)
        (a)     24

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       15 x 123 = 24 x a

        (15 x123)/ 24  =  a

        184524               = a

      77   soldiers      =  a



2)  

 A troop has provisions for 171  soldiers for 15 days. How many soldiers leave the troop so that the provisions may last for 28 days

Answer: 92 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       171  (y)      15 (x)
        (a)     28

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       15 x 171 = 28 x a

        (15 x171)/ 28  =  a

        256528               = a

      92   soldiers      =  a



3)  

 A troop has provisions for 119  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 30 days

Answer: 40 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       119  (y)      10 (x)
        (a)     30

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       10 x 119 = 30 x a

        (10 x119)/ 30  =  a

        119030               = a

      40   soldiers      =  a



4)  

 A troop has provisions for 136  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 21 days

Answer: 65 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       136  (y)      10 (x)
        (a)     21

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       10 x 136 = 21 x a

        (10 x136)/ 21  =  a

        136021               = a

      65   soldiers      =  a



5)  

 A troop has provisions for 188  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 25 days

Answer: 75 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       188  (y)      10 (x)
        (a)     25

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       10 x 188 = 25 x a

        (10 x188)/ 25  =  a

        188025               = a

      75   soldiers      =  a



6)  

 A troop has provisions for 156  soldiers for 12 days. How many soldiers leave the troop so that the provisions may last for 22 days

Answer: 85 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       156  (y)      12 (x)
        (a)     22

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       12 x 156 = 22 x a

        (12 x156)/ 22  =  a

        187222               = a

      85   soldiers      =  a



7)  

 A troop has provisions for 134  soldiers for 13 days. How many soldiers leave the troop so that the provisions may last for 24 days

Answer: 73 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       134  (y)      13 (x)
        (a)     24

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       13 x 134 = 24 x a

        (13 x134)/ 24  =  a

        174224               = a

      73   soldiers      =  a



8)  

 A troop has provisions for 108  soldiers for 11 days. How many soldiers leave the troop so that the provisions may last for 26 days

Answer: 46 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       108  (y)      11 (x)
        (a)     26

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       11 x 108 = 26 x a

        (11 x108)/ 26  =  a

        118826               = a

      46   soldiers      =  a



9)  

 A troop has provisions for 162  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 26 days

Answer: 62 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       162  (y)      10 (x)
        (a)     26

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       10 x 162 = 26 x a

        (10 x162)/ 26  =  a

        162026               = a

      62   soldiers      =  a



10)  

 A troop has provisions for 169  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 28 days

Answer: 60 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       169  (y)      10 (x)
        (a)     28

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       10 x 169 = 28 x a

        (10 x169)/ 28  =  a

        169028               = a

      60   soldiers      =  a