Scroll:Life Mathematics >> Life Mathematics - variation >> saq (4336)


Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.



 

1)  

 A troop has provisions for 180  soldiers for 11 days. How many soldiers leave the troop so that the provisions may last for 21 days

soldiers


Answer:_______________




2)  

 A troop has provisions for 169  soldiers for 15 days. How many soldiers leave the troop so that the provisions may last for 24 days

soldiers


Answer:_______________




3)  

 A troop has provisions for 167  soldiers for 15 days. How many soldiers leave the troop so that the provisions may last for 23 days

soldiers


Answer:_______________




4)  

 A troop has provisions for 172  soldiers for 13 days. How many soldiers leave the troop so that the provisions may last for 30 days

soldiers


Answer:_______________




5)  

 A troop has provisions for 143  soldiers for 14 days. How many soldiers leave the troop so that the provisions may last for 28 days

soldiers


Answer:_______________




6)  

 A troop has provisions for 134  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 28 days

soldiers


Answer:_______________




7)  

 A troop has provisions for 124  soldiers for 13 days. How many soldiers leave the troop so that the provisions may last for 29 days

soldiers


Answer:_______________




8)  

 A troop has provisions for 102  soldiers for 11 days. How many soldiers leave the troop so that the provisions may last for 21 days

soldiers


Answer:_______________




9)  

 A troop has provisions for 156  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 28 days

soldiers


Answer:_______________




10)  

 A troop has provisions for 189  soldiers for 11 days. How many soldiers leave the troop so that the provisions may last for 25 days

soldiers


Answer:_______________




 

1)  

 A troop has provisions for 180  soldiers for 11 days. How many soldiers leave the troop so that the provisions may last for 21 days

Answer: 94 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       180  (y)      11 (x)
        (a)     21

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       11 x 180 = 21 x a

        (11 x180)/ 21  =  a

        198021               = a

      94   soldiers      =  a



2)  

 A troop has provisions for 169  soldiers for 15 days. How many soldiers leave the troop so that the provisions may last for 24 days

Answer: 106 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       169  (y)      15 (x)
        (a)     24

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       15 x 169 = 24 x a

        (15 x169)/ 24  =  a

        253524               = a

      106   soldiers      =  a



3)  

 A troop has provisions for 167  soldiers for 15 days. How many soldiers leave the troop so that the provisions may last for 23 days

Answer: 109 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       167  (y)      15 (x)
        (a)     23

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       15 x 167 = 23 x a

        (15 x167)/ 23  =  a

        250523               = a

      109   soldiers      =  a



4)  

 A troop has provisions for 172  soldiers for 13 days. How many soldiers leave the troop so that the provisions may last for 30 days

Answer: 75 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       172  (y)      13 (x)
        (a)     30

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       13 x 172 = 30 x a

        (13 x172)/ 30  =  a

        223630               = a

      75   soldiers      =  a



5)  

 A troop has provisions for 143  soldiers for 14 days. How many soldiers leave the troop so that the provisions may last for 28 days

Answer: 72 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       143  (y)      14 (x)
        (a)     28

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       14 x 143 = 28 x a

        (14 x143)/ 28  =  a

        200228               = a

      72   soldiers      =  a



6)  

 A troop has provisions for 134  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 28 days

Answer: 48 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       134  (y)      10 (x)
        (a)     28

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       10 x 134 = 28 x a

        (10 x134)/ 28  =  a

        134028               = a

      48   soldiers      =  a



7)  

 A troop has provisions for 124  soldiers for 13 days. How many soldiers leave the troop so that the provisions may last for 29 days

Answer: 56 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       124  (y)      13 (x)
        (a)     29

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       13 x 124 = 29 x a

        (13 x124)/ 29  =  a

        161229               = a

      56   soldiers      =  a



8)  

 A troop has provisions for 102  soldiers for 11 days. How many soldiers leave the troop so that the provisions may last for 21 days

Answer: 53 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       102  (y)      11 (x)
        (a)     21

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       11 x 102 = 21 x a

        (11 x102)/ 21  =  a

        112221               = a

      53   soldiers      =  a



9)  

 A troop has provisions for 156  soldiers for 10 days. How many soldiers leave the troop so that the provisions may last for 28 days

Answer: 56 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       156  (y)      10 (x)
        (a)     28

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       10 x 156 = 28 x a

        (10 x156)/ 28  =  a

        156028               = a

      56   soldiers      =  a



10)  

 A troop has provisions for 189  soldiers for 11 days. How many soldiers leave the troop so that the provisions may last for 25 days

Answer: 83 soldiers


SOLUTION 1 :

Given:

No of soldiersNo of days
       189  (y)      11 (x)
        (a)     25

As the No of days increases, No of soldiers decreases

It is in inverses variation.

So, xy  =  Constant

       11 x 189 = 25 x a

        (11 x189)/ 25  =  a

        207925               = a

      83   soldiers      =  a