Sasi Math (Revised for 1024)

Scroll:Measurements >> area >> saq (4345)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

In a right triangular ground, the sides adjacent to the right angle are 11 m and 26m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 15 m and 29m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 18 m and 26m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 14 m and 26m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 19 m and 27m. Find the cost of the cementing the grount at 8 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 16 m and 29m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 12 m and 28m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 12 m and 28m. Find the cost of the cementing the grount at 7 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 12 m and 29m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer:_______________

10)

In a right triangular ground, the sides adjacent to the right angle are 14 m and 25m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 11 m and 26m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 1430

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (11 x 26)

= $\frac{1}{2}$ x 286

= 143 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 143 x 10

= 1430

In a right triangular ground, the sides adjacent to the right angle are 15 m and 29m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer: 870

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (15 x 29)

= $\frac{1}{2}$ x 435

= 217.5 m²

Cost of cementing 1 sq,m = 4

Cost of cementing 4 sq. m = 217.5 x 4

= 870

In a right triangular ground, the sides adjacent to the right angle are 18 m and 26m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 2340

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (18 x 26)

= $\frac{1}{2}$ x 468

= 234 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 234 x 10

= 2340

In a right triangular ground, the sides adjacent to the right angle are 14 m and 26m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 910

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (14 x 26)

= $\frac{1}{2}$ x 364

= 182 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 182 x 5

= 910

In a right triangular ground, the sides adjacent to the right angle are 19 m and 27m. Find the cost of the cementing the grount at 8 per sq,.m.

Answer: 2052

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (19 x 27)

= $\frac{1}{2}$ x 513

= 256.5 m²

Cost of cementing 1 sq,m = 8

Cost of cementing 8 sq. m = 256.5 x 8

= 2052

In a right triangular ground, the sides adjacent to the right angle are 16 m and 29m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 2320

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (16 x 29)

= $\frac{1}{2}$ x 464

= 232 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 232 x 10

= 2320

In a right triangular ground, the sides adjacent to the right angle are 12 m and 28m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer: 336

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (12 x 28)

= $\frac{1}{2}$ x 336

= 168 m²

Cost of cementing 1 sq,m = 2

Cost of cementing 2 sq. m = 168 x 2

= 336

In a right triangular ground, the sides adjacent to the right angle are 12 m and 28m. Find the cost of the cementing the grount at 7 per sq,.m.

Answer: 1176

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (12 x 28)

= $\frac{1}{2}$ x 336

= 168 m²

Cost of cementing 1 sq,m = 7

Cost of cementing 7 sq. m = 168 x 7

= 1176

In a right triangular ground, the sides adjacent to the right angle are 12 m and 29m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer: 522

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (12 x 29)

= $\frac{1}{2}$ x 348

= 174 m²

Cost of cementing 1 sq,m = 3

Cost of cementing 3 sq. m = 174 x 3

= 522

10)

In a right triangular ground, the sides adjacent to the right angle are 14 m and 25m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer: 350

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (14 x 25)

= $\frac{1}{2}$ x 350

= 175 m²

Cost of cementing 1 sq,m = 2

Cost of cementing 2 sq. m = 175 x 2

= 350