Sasi Math (Revised for 1024)

Scroll:Measurements >> area >> saq (4345)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

In a right triangular ground, the sides adjacent to the right angle are 17 m and 25m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 15 m and 28m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 10 m and 26m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 11 m and 29m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 18 m and 25m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 18 m and 30m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 14 m and 25m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 18 m and 25m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 11 m and 27m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

10)

In a right triangular ground, the sides adjacent to the right angle are 18 m and 27m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 17 m and 25m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer: 1912.5

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (17 x 25)

= $\frac{1}{2}$ x 425

= 212.5 m²

Cost of cementing 1 sq,m = 9

Cost of cementing 9 sq. m = 212.5 x 9

= 1912.5

In a right triangular ground, the sides adjacent to the right angle are 15 m and 28m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer: 840

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (15 x 28)

= $\frac{1}{2}$ x 420

= 210 m²

Cost of cementing 1 sq,m = 4

Cost of cementing 4 sq. m = 210 x 4

= 840

In a right triangular ground, the sides adjacent to the right angle are 10 m and 26m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer: 390

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (10 x 26)

= $\frac{1}{2}$ x 260

= 130 m²

Cost of cementing 1 sq,m = 3

Cost of cementing 3 sq. m = 130 x 3

= 390

In a right triangular ground, the sides adjacent to the right angle are 11 m and 29m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 1595

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (11 x 29)

= $\frac{1}{2}$ x 319

= 159.5 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 159.5 x 10

= 1595

In a right triangular ground, the sides adjacent to the right angle are 18 m and 25m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer: 900

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (18 x 25)

= $\frac{1}{2}$ x 450

= 225 m²

Cost of cementing 1 sq,m = 4

Cost of cementing 4 sq. m = 225 x 4

= 900

In a right triangular ground, the sides adjacent to the right angle are 18 m and 30m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 2700

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (18 x 30)

= $\frac{1}{2}$ x 540

= 270 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 270 x 10

= 2700

In a right triangular ground, the sides adjacent to the right angle are 14 m and 25m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 1750

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (14 x 25)

= $\frac{1}{2}$ x 350

= 175 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 175 x 10

= 1750

In a right triangular ground, the sides adjacent to the right angle are 18 m and 25m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 1125

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (18 x 25)

= $\frac{1}{2}$ x 450

= 225 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 225 x 5

= 1125

In a right triangular ground, the sides adjacent to the right angle are 11 m and 27m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 742.5

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (11 x 27)

= $\frac{1}{2}$ x 297

= 148.5 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 148.5 x 5

= 742.5

10)

In a right triangular ground, the sides adjacent to the right angle are 18 m and 27m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer: 1458

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (18 x 27)

= $\frac{1}{2}$ x 486

= 243 m²

Cost of cementing 1 sq,m = 6

Cost of cementing 6 sq. m = 243 x 6

= 1458