Sasi Math (Revised for 1024)

Scroll:Measurements >> area >> saq (4345)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

In a right triangular ground, the sides adjacent to the right angle are 20 m and 30m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 15 m and 30m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 20 m and 25m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 18 m and 26m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 19 m and 25m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 20 m and 27m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 10 m and 26m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 13 m and 29m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 12 m and 30m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer:_______________

10)

In a right triangular ground, the sides adjacent to the right angle are 17 m and 29m. Find the cost of the cementing the grount at 8 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 20 m and 30m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer: 600

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (20 x 30)

= $\frac{1}{2}$ x 600

= 300 m²

Cost of cementing 1 sq,m = 2

Cost of cementing 2 sq. m = 300 x 2

= 600

In a right triangular ground, the sides adjacent to the right angle are 15 m and 30m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer: 675

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (15 x 30)

= $\frac{1}{2}$ x 450

= 225 m²

Cost of cementing 1 sq,m = 3

Cost of cementing 3 sq. m = 225 x 3

= 675

In a right triangular ground, the sides adjacent to the right angle are 20 m and 25m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 1250

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (20 x 25)

= $\frac{1}{2}$ x 500

= 250 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 250 x 5

= 1250

In a right triangular ground, the sides adjacent to the right angle are 18 m and 26m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 1170

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (18 x 26)

= $\frac{1}{2}$ x 468

= 234 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 234 x 5

= 1170

In a right triangular ground, the sides adjacent to the right angle are 19 m and 25m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer: 1425

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (19 x 25)

= $\frac{1}{2}$ x 475

= 237.5 m²

Cost of cementing 1 sq,m = 6

Cost of cementing 6 sq. m = 237.5 x 6

= 1425

In a right triangular ground, the sides adjacent to the right angle are 20 m and 27m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer: 1080

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (20 x 27)

= $\frac{1}{2}$ x 540

= 270 m²

Cost of cementing 1 sq,m = 4

Cost of cementing 4 sq. m = 270 x 4

= 1080

In a right triangular ground, the sides adjacent to the right angle are 10 m and 26m. Find the cost of the cementing the grount at 4 per sq,.m.

Answer: 520

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (10 x 26)

= $\frac{1}{2}$ x 260

= 130 m²

Cost of cementing 1 sq,m = 4

Cost of cementing 4 sq. m = 130 x 4

= 520

In a right triangular ground, the sides adjacent to the right angle are 13 m and 29m. Find the cost of the cementing the grount at 9 per sq,.m.

Answer: 1696.5

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (13 x 29)

= $\frac{1}{2}$ x 377

= 188.5 m²

Cost of cementing 1 sq,m = 9

Cost of cementing 9 sq. m = 188.5 x 9

= 1696.5

In a right triangular ground, the sides adjacent to the right angle are 12 m and 30m. Find the cost of the cementing the grount at 5 per sq,.m.

Answer: 900

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (12 x 30)

= $\frac{1}{2}$ x 360

= 180 m²

Cost of cementing 1 sq,m = 5

Cost of cementing 5 sq. m = 180 x 5

= 900

10)

In a right triangular ground, the sides adjacent to the right angle are 17 m and 29m. Find the cost of the cementing the grount at 8 per sq,.m.

Answer: 1972

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (17 x 29)

= $\frac{1}{2}$ x 493

= 246.5 m²

Cost of cementing 1 sq,m = 8

Cost of cementing 8 sq. m = 246.5 x 8

= 1972