Sasi Math (Revised for 1024)

Scroll:Measurements >> area >> saq (4345)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

In a right triangular ground, the sides adjacent to the right angle are 18 m and 26m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 15 m and 27m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 11 m and 28m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 18 m and 30m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 19 m and 28m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 12 m and 29m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 13 m and 29m. Find the cost of the cementing the grount at 8 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 12 m and 27m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 10 m and 25m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer:_______________

10)

In a right triangular ground, the sides adjacent to the right angle are 16 m and 29m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer:_______________

In a right triangular ground, the sides adjacent to the right angle are 18 m and 26m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 2340

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (18 x 26)

= $\frac{1}{2}$ x 468

= 234 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 234 x 10

= 2340

In a right triangular ground, the sides adjacent to the right angle are 15 m and 27m. Find the cost of the cementing the grount at 3 per sq,.m.

Answer: 607.5

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (15 x 27)

= $\frac{1}{2}$ x 405

= 202.5 m²

Cost of cementing 1 sq,m = 3

Cost of cementing 3 sq. m = 202.5 x 3

= 607.5

In a right triangular ground, the sides adjacent to the right angle are 11 m and 28m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 1540

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (11 x 28)

= $\frac{1}{2}$ x 308

= 154 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 154 x 10

= 1540

In a right triangular ground, the sides adjacent to the right angle are 18 m and 30m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 2700

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (18 x 30)

= $\frac{1}{2}$ x 540

= 270 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 270 x 10

= 2700

In a right triangular ground, the sides adjacent to the right angle are 19 m and 28m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer: 532

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (19 x 28)

= $\frac{1}{2}$ x 532

= 266 m²

Cost of cementing 1 sq,m = 2

Cost of cementing 2 sq. m = 266 x 2

= 532

In a right triangular ground, the sides adjacent to the right angle are 12 m and 29m. Find the cost of the cementing the grount at 2 per sq,.m.

Answer: 348

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (12 x 29)

= $\frac{1}{2}$ x 348

= 174 m²

Cost of cementing 1 sq,m = 2

Cost of cementing 2 sq. m = 174 x 2

= 348

In a right triangular ground, the sides adjacent to the right angle are 13 m and 29m. Find the cost of the cementing the grount at 8 per sq,.m.

Answer: 1508

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (13 x 29)

= $\frac{1}{2}$ x 377

= 188.5 m²

Cost of cementing 1 sq,m = 8

Cost of cementing 8 sq. m = 188.5 x 8

= 1508

In a right triangular ground, the sides adjacent to the right angle are 12 m and 27m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 1620

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (12 x 27)

= $\frac{1}{2}$ x 324

= 162 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 162 x 10

= 1620

In a right triangular ground, the sides adjacent to the right angle are 10 m and 25m. Find the cost of the cementing the grount at 10 per sq,.m.

Answer: 1250

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (10 x 25)

= $\frac{1}{2}$ x 250

= 125 m²

Cost of cementing 1 sq,m = 10

Cost of cementing 10 sq. m = 125 x 10

= 1250

10)

In a right triangular ground, the sides adjacent to the right angle are 16 m and 29m. Find the cost of the cementing the grount at 6 per sq,.m.

Answer: 1392

SOLUTION 1 :

For finding the cost of cementing, we need to find the area and then multiply it by the rate for cementing.

Area of right triangular = $\frac{1}{2}$ x b x h

Where b and h are adjacent sides of the right angles.

= $\frac{1}{2}$ x (bx h)

= $\frac{1}{2}$ x (16 x 29)

= $\frac{1}{2}$ x 464

= 232 m²

Cost of cementing 1 sq,m = 6

Cost of cementing 6 sq. m = 232 x 6

= 1392