Scroll:Algebra >> Term III Ex 1.2 >> saq (4451)


Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.



 

1)  

2 times a number decreased by 8 gives 22. Find the number.


Answer:_______________




2)  

3 times a number decreased by 6 gives 30. Find the number.


Answer:_______________




3)  

5 times a number decreased by 10 gives 40. Find the number.


Answer:_______________




4)  

6 times a number decreased by 6 gives 36. Find the number.


Answer:_______________




5)  

4 times a number decreased by 4 gives 32. Find the number.


Answer:_______________




6)  

2 times a number decreased by 2 gives 24. Find the number.


Answer:_______________




7)  

3 times a number decreased by 9 gives 27. Find the number.


Answer:_______________




8)  

5 times a number decreased by 5 gives 55. Find the number.


Answer:_______________




9)  

6 times a number decreased by 6 gives 24. Find the number.


Answer:_______________




10)  

4 times a number decreased by 8 gives 44. Find the number.


Answer:_______________




 

1)  

2 times a number decreased by 8 gives 22. Find the number.

Answer: 15


SOLUTION 1 :

Let the required number be y. ⇒ 2 times = 2y

Given:

2y - 8 = 22 

⇒ 2y = 22 + 8     ( on transposing - 8 becomes + 8 )

⇒ 2y = 30

2y2 = 302        ( Dividing by 2, both the sides )

y = 15.

Hence, the required number is 15.

 

 



2)  

3 times a number decreased by 6 gives 30. Find the number.

Answer: 12


SOLUTION 1 :

Let the required number be y. ⇒ 3 times = 3y

Given:

3y - 6 = 30 

⇒ 3y = 30 + 6     ( on transposing - 6 becomes + 6 )

⇒ 3y = 36

3y3 = 363        ( Dividing by 3, both the sides )

y = 12.

Hence, the required number is 12.

 

 



3)  

5 times a number decreased by 10 gives 40. Find the number.

Answer: 10


SOLUTION 1 :

Let the required number be x. ⇒ 5 times = 5x

Given:

5x - 10 = 40 

⇒ 5x = 40 + 10     ( on transposing - 10 becomes + 10 )

⇒ 5x = 50

5x5 = 505        ( Dividing by 5, both the sides )

x = 10.

Hence, the required number is 10.

 

 



4)  

6 times a number decreased by 6 gives 36. Find the number.

Answer: 7


SOLUTION 1 :

Let the required number be y. ⇒ 6 times = 6y

Given:

6y - 6 = 36 

⇒ 6y = 36 + 6     ( on transposing - 6 becomes + 6 )

⇒ 6y = 42

6y6 = 426        ( Dividing by 6, both the sides )

y = 7.

Hence, the required number is 7.

 

 



5)  

4 times a number decreased by 4 gives 32. Find the number.

Answer: 9


SOLUTION 1 :

Let the required number be x. ⇒ 4 times = 4x

Given:

4x - 4 = 32 

⇒ 4x = 32 + 4     ( on transposing - 4 becomes + 4 )

⇒ 4x = 36

4x4 = 364        ( Dividing by 4, both the sides )

x = 9.

Hence, the required number is .

 

 



6)  

2 times a number decreased by 2 gives 24. Find the number.

Answer: 13


SOLUTION 1 :

Let the required number be y. ⇒ 2 times = 2y

Given:

2y - 2 = 24 

⇒ 2y = 24 + 2     ( on transposing - 2 becomes + 2 )

⇒ 2y = 26

2y2 = 262        ( Dividing by 2, both the sides )

y = 13.

Hence, the required number is 13.

 

 



7)  

3 times a number decreased by 9 gives 27. Find the number.

Answer: 12


SOLUTION 1 :

Let the required number be y. ⇒ 3 times = 3y

Given:

3y - 9 = 27 

⇒ 3y = 27 + 9     ( on transposing - 9 becomes + 9 )

⇒ 3y = 36

3y3 = 363        ( Dividing by 3, both the sides )

y = 12.

Hence, the required number is 12.

 

 



8)  

5 times a number decreased by 5 gives 55. Find the number.

Answer: 12


SOLUTION 1 :

Let the required number be x. ⇒ 5 times = 5x

Given:

5x - 5 = 55 

⇒ 5x = 55 + 5     ( on transposing - 5 becomes + 5 )

⇒ 5x = 60

5x5 = 605        ( Dividing by 5, both the sides )

x = 12.

Hence, the required number is 12.

 

 



9)  

6 times a number decreased by 6 gives 24. Find the number.

Answer: 5


SOLUTION 1 :

Let the required number be x. ⇒ 6 times = 6x

Given:

6x - 6 = 24 

⇒ 6x = 24 + 6     ( on transposing - 6 becomes + 6 )

⇒ 6x = 30

6x6 = 306        ( Dividing by 6, both the sides )

x = 5.

Hence, the required number is 5.

 

 



10)  

4 times a number decreased by 8 gives 44. Find the number.

Answer: 13


SOLUTION 1 :

Let the required number be y. ⇒ 4 times = 4y

Given:

4y - 8 = 44 

⇒ 4y = 44 + 8     ( on transposing - 8 becomes + 8 )

⇒ 4y = 52

4y4 = 524        ( Dividing by 4, both the sides )

y = 13.

Hence, the required number is .