Written Instructions:
For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..
For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.
Leave your answers in the simplest form or correct to two decimal places.
| 1) Using laws of exponents, simplify in the exponential form v3xv1xv4xv6 v to the power Answer:_______________ |
| 2) Using laws of exponents, simplify in the exponential form w3xw5xw2xw7 w to the power Answer:_______________ |
| 3) Using laws of exponents, simplify in the exponential form f1xf3xf2xf8 f to the power Answer:_______________ |
| 4) Using laws of exponents, simplify in the exponential form s4xs6xs2xs3 s to the power Answer:_______________ |
| 5) Using laws of exponents, simplify in the exponential form y3xy2xy4xy5 y to the power Answer:_______________ |
| 6) Using laws of exponents, simplify in the exponential form r5xr1xr3xr0 r to the power Answer:_______________ |
| 7) Using laws of exponents, simplify in the exponential form j4xj1xj4xj8 j to the power Answer:_______________ |
| 8) Using laws of exponents, simplify in the exponential form v2xv3xv2xv1 v to the power Answer:_______________ |
| 9) Using laws of exponents, simplify in the exponential form u4xu1xu3xu0 u to the power Answer:_______________ |
| 10) Using laws of exponents, simplify in the exponential form a5xa2xa3xa6 a to the power Answer:_______________ |
| 1) Using laws of exponents, simplify in the exponential form z3xz1xz4xz6 z to the power Answer: 14 SOLUTION 1 : Soln : z3xz1xz4xz6 = z(3+1+4+6) = z14 |
| 2) Using laws of exponents, simplify in the exponential form d3xd5xd2xd7 d to the power Answer: 17 SOLUTION 1 : Soln : d3xd5xd2xd7 = d(3+5+2+7) = d17 |
| 3) Using laws of exponents, simplify in the exponential form w1xw3xw2xw8 w to the power Answer: 14 SOLUTION 1 : Soln : w1xw3xw2xw8 = w(1+3+2+8) = w14 |
| 4) Using laws of exponents, simplify in the exponential form h4xh6xh2xh3 h to the power Answer: 15 SOLUTION 1 : Soln : h4xh6xh2xh3 = h(4+6+2+3) = h15 |
| 5) Using laws of exponents, simplify in the exponential form c3xc2xc4xc5 c to the power Answer: 14 SOLUTION 1 : Soln : c3xc2xc4xc5 = c(3+2+4+5) = c14 |
| 6) Using laws of exponents, simplify in the exponential form i5xi1xi3xi0 i to the power Answer: 9 SOLUTION 1 : Soln : i5xi1xi3xi0 = i(5+1+3+0) = i9 |
| 7) Using laws of exponents, simplify in the exponential form m4xm1xm4xm8 m to the power Answer: 17 SOLUTION 1 : Soln : m4xm1xm4xm8 = m(4+1+4+8) = m17 |
| 8) Using laws of exponents, simplify in the exponential form r2xr3xr2xr1 r to the power Answer: 8 SOLUTION 1 : Soln : r2xr3xr2xr1 = r(2+3+2+1) = r8 |
| 9) Using laws of exponents, simplify in the exponential form s4xs1xs3xs0 s to the power Answer: 8 SOLUTION 1 : Soln : s4xs1xs3xs0 = s(4+1+3+0) = s8 |
| 10) Using laws of exponents, simplify in the exponential form v5xv2xv3xv6 v to the power Answer: 16 SOLUTION 1 : Soln : v5xv2xv3xv6 = v(5+2+3+6) = v16 |