Scroll:Measurements >> Trapezium >> mcq (4461)


Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.



 

1)  

 In an isosceles trapezium







(                    )




2)  

 The height of a trapezium whose sum of parallel sides is 40 cm and the area 190 cm2 is 







(                    )




3)  

 The sum of parallel sides of a trapezium is 22cm and height is 10cm. Then its area is...







(                    )




4)  

 The area of trapezium is ______ sq.units.

(A)  h(a+b)  (B) 12 h(a+b)   (C)  h(a+b)   (D)   12 h(a-b)







(                    )




5)  

 In an isosceles trapezium







(                    )




6)  

 The height of a trapezium whose sum of parallel sides is 10 cm and the area 140 cm2 is 







(                    )




7)  

 The sum of parallel sides of a trapezium is 16cm and height is 25cm. Then its area is...







(                    )




8)  

 The area of trapezium is ______ sq.units.

(A)  h(a+b)  (B) 12 h(a+b)   (C)  h(a+b)   (D)   12 h(a-b)







(                    )




9)  

 In an isosceles trapezium







(                    )




10)  

 The height of a trapezium whose sum of parallel sides is 20 cm and the area 130 cm2 is 







(                    )




 

1)  

 In an isosceles trapezium






Answer: 2


SOLUTION 1 :

Ans = non parallel sides are equal

 

In an isosceles trapezium, non-parallel sides are equal.



2)  

 The height of a trapezium whose sum of parallel sides is 40 cm and the area 190 cm2 is 






Answer: 3


SOLUTION 1 :

Given,

Area = 190 cm2    a + b = 40

Area of trapezium = 12 h (a+b)

                             = 12 x h x 40 = 190 cm2

                190 cm2 = 1 / 2 x h x 40 20

                          h  = 19020 = 9.5 cm.

The height of trapezium = 9.5 cm.                         



3)  

 The sum of parallel sides of a trapezium is 22cm and height is 10cm. Then its area is...






Answer: 4


SOLUTION 1 :

Given,

a + b  = 22 cm,   h = 10 cm.

Area of trapezium = 12 h(a+b)

                             = 1/2 10 x 22 11

                             =  10 x 11

Area of trapezium    = 110 cm2



4)  

 The area of trapezium is ______ sq.units.

(A)  h(a+b)  (B) 12 h(a+b)   (C)  h(a+b)   (D)   12 h(a-b)






Answer: 3


SOLUTION 1 :

Ans = B

Area of trapezium = 12 h(a+b) sq.units.



5)  

 In an isosceles trapezium






Answer: 3


SOLUTION 1 :

Ans = non parallel sides are equal

 

In an isosceles trapezium, non-parallel sides are equal.



6)  

 The height of a trapezium whose sum of parallel sides is 10 cm and the area 140 cm2 is 






Answer: 2


SOLUTION 1 :

Given,

Area = 140 cm2    a + b = 10

Area of trapezium = 12 h (a+b)

                             = 12 x h x 10 = 140 cm2

                140 cm2 = 1 / 2 x h x 10 5

                          h  = 1405 = 28 cm.

The height of trapezium = 28 cm.                         



7)  

 The sum of parallel sides of a trapezium is 16cm and height is 25cm. Then its area is...






Answer: 1


SOLUTION 1 :

Given,

a + b  = 16 cm,   h = 25 cm.

Area of trapezium = 12 h(a+b)

                             = 1/2 25 x 16 8

                             =  25 x 8

Area of trapezium    = 200 cm2



8)  

 The area of trapezium is ______ sq.units.

(A)  h(a+b)  (B) 12 h(a+b)   (C)  h(a+b)   (D)   12 h(a-b)






Answer: 3


SOLUTION 1 :

Ans = B

Area of trapezium = 12 h(a+b) sq.units.



9)  

 In an isosceles trapezium






Answer: 3


SOLUTION 1 :

Ans = non parallel sides are equal

 

In an isosceles trapezium, non-parallel sides are equal.



10)  

 The height of a trapezium whose sum of parallel sides is 20 cm and the area 130 cm2 is 






Answer: 3


SOLUTION 1 :

Given,

Area = 130 cm2    a + b = 20

Area of trapezium = 12 h (a+b)

                             = 12 x h x 20 = 130 cm2

                130 cm2 = 1 / 2 x h x 20 10

                          h  = 13010 = 13 cm.

The height of trapezium = 13 cm.