Sasi Math (Revised for 1024)

Scroll:Measurements >> Trapezium >> mcq (4461)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

The area of trapezium is ______ sq.units.

(A) h(a+b) (B) $\frac{1}{2}$ h(a+b) (C) h(a+b) (D) $\frac{1}{2}$ h(a-b)

1) D
2) B
3) A
4) C

( )

The height of a trapezium whose sum of parallel sides is 20 cm and the area 100 cm² is

1) 9
2) 11
3) 10
4) 12

( )

In an isosceles trapezium

1) parallel sides are equal
2) non parallel sides are equal
3) height = base
4) parallel side = non parallel side

( )

The sum of parallel sides of a trapezium is 18cm and height is 5cm. Then its area is...

1) 45
2) 47
3) 50
4) 40

( )

The area of trapezium is ______ sq.units.

(A) h(a+b) (B) $\frac{1}{2}$ h(a+b) (C) h(a+b) (D) $\frac{1}{2}$ h(a-b)

1) D
2) B
3) C
4) A

( )

The height of a trapezium whose sum of parallel sides is 40 cm and the area 110 cm² is

1) 5.5
2) 4.5
3) 6.5
4) 7.5

( )

In an isosceles trapezium

1) parallel sides are equal
2) parallel side = non parallel side
3) non parallel sides are equal
4) height = base

( )

The sum of parallel sides of a trapezium is 28cm and height is 20cm. Then its area is...

1) 285
2) 275
3) 282
4) 280

( )

The area of trapezium is ______ sq.units.

(A) h(a+b) (B) $\frac{1}{2}$ h(a+b) (C) h(a+b) (D) $\frac{1}{2}$ h(a-b)

1) B
2) A
3) C
4) D

( )

10)

The height of a trapezium whose sum of parallel sides is 10 cm and the area 70 cm² is

1) 15
2) 16
3) 13
4) 14

( )

The area of trapezium is ______ sq.units.

(A) h(a+b) (B) $\frac{1}{2}$ h(a+b) (C) h(a+b) (D) $\frac{1}{2}$ h(a-b)

1) C
2) B
3) A
4) D

Answer: 2

SOLUTION 1 :

Ans = B

Area of trapezium = $\frac{1}{2}$ h(a+b) sq.units.

The height of a trapezium whose sum of parallel sides is 20 cm and the area 100 cm² is

1) 12
2) 11
3) 10
4) 9

Answer: 3

SOLUTION 1 :

Given,

Area = 100 cm² a + b = 20

Area of trapezium = $\frac{1}{2}$ h (a+b)

= $\frac{1}{2}$ x h x 20 = 100 cm²

100 cm² = 1 / 2 x h x 20 ¹⁰

h = $\frac{100}{10}$ = 10 cm.

The height of trapezium = 10 cm.

In an isosceles trapezium

1) non parallel sides are equal
2) parallel side = non parallel side
3) height = base
4) parallel sides are equal

Answer: 1

SOLUTION 1 :

Ans = non parallel sides are equal

In an isosceles trapezium, non-parallel sides are equal.

The sum of parallel sides of a trapezium is 18cm and height is 5cm. Then its area is...

1) 45
2) 40
3) 50
4) 47

Answer: 1

SOLUTION 1 :

Given,

a + b = 18 cm, h = 5 cm.

Area of trapezium = $\frac{1}{2}$ h(a+b)

= 1/2 5 x 18 ⁹

= 5 x 9

Area of trapezium = 45 cm²

The area of trapezium is ______ sq.units.

(A) h(a+b) (B) $\frac{1}{2}$ h(a+b) (C) h(a+b) (D) $\frac{1}{2}$ h(a-b)

1) C
2) B
3) A
4) D

Answer: 2

SOLUTION 1 :

Ans = B

Area of trapezium = $\frac{1}{2}$ h(a+b) sq.units.

The height of a trapezium whose sum of parallel sides is 40 cm and the area 110 cm² is

1) 6.5
2) 7.5
3) 4.5
4) 5.5

Answer: 4

SOLUTION 1 :

Given,

Area = 110 cm² a + b = 40

Area of trapezium = $\frac{1}{2}$ h (a+b)

= $\frac{1}{2}$ x h x 40 = 110 cm²

110 cm² = 1 / 2 x h x 40 ²⁰

h = $\frac{110}{20}$ = 5.5 cm.

The height of trapezium = 5.5 cm.

In an isosceles trapezium

1) parallel side = non parallel side
2) non parallel sides are equal
3) height = base
4) parallel sides are equal

Answer: 2

SOLUTION 1 :

Ans = non parallel sides are equal

In an isosceles trapezium, non-parallel sides are equal.

The sum of parallel sides of a trapezium is 28cm and height is 20cm. Then its area is...

1) 285
2) 282
3) 275
4) 280

Answer: 4

SOLUTION 1 :

Given,

a + b = 28 cm, h = 20 cm.

Area of trapezium = $\frac{1}{2}$ h(a+b)

= 1/2 20 x 28 ¹⁴

= 20 x 14

Area of trapezium = 280 cm²

The area of trapezium is ______ sq.units.

(A) h(a+b) (B) $\frac{1}{2}$ h(a+b) (C) h(a+b) (D) $\frac{1}{2}$ h(a-b)

1) D
2) B
3) A
4) C

Answer: 2

SOLUTION 1 :

Ans = B

Area of trapezium = $\frac{1}{2}$ h(a+b) sq.units.

10)

The height of a trapezium whose sum of parallel sides is 10 cm and the area 70 cm² is

1) 15
2) 14
3) 13
4) 16

Answer: 2

SOLUTION 1 :

Given,

Area = 70 cm² a + b = 10

Area of trapezium = $\frac{1}{2}$ h (a+b)

= $\frac{1}{2}$ x h x 10 = 70 cm²

70 cm² = 1 / 2 x h x 10 ⁵

h = $\frac{70}{5}$ = 14 cm.

The height of trapezium = 14 cm.