Sasi Math (Revised for 1024)

Scroll:Probability >> probability >> ps (4493)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A bag consists of 136 shirts of which 93 are good, 22 have minor defects and 13 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 134 shirts of which 81 are good, 19 have minor defects and 12 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 122 shirts of which 83 are good, 23 have minor defects and 6 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 141 shirts of which 96 are good, 15 have minor defects and 7 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 147 shirts of which 91 are good, 18 have minor defects and 10 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 122 shirts of which 77 are good, 25 have minor defects and 8 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 143 shirts of which 83 are good, 24 have minor defects and 8 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 126 shirts of which 100 are good, 19 have minor defects and 13 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 148 shirts of which 76 are good, 23 have minor defects and 9 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

10)

A bag consists of 134 shirts of which 90 are good, 23 have minor defects and 9 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A = Answer: $\frac{93}{136}$

B = Answer: $\frac{115}{136}$

SOLUTION 1 :

A bag consists of 136 shirts.

n(S) = 136.

(i) ..... A trader A will accept only good shirts

n(A) = 93.

P(A) = n(A) / a(S) = $\frac{93}{136}$ = $\frac{93}{136}$ .

A will accept only good shirts = $\frac{93}{136}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 93 + 22 ( B accepts good and minor defects shirts)

= 115.

P(B) = n(B) / n(S) = $\frac{115}{136}$ = $\frac{115}{136}$

Trader B will accept the shirts which have minor defects = $\frac{115}{136}$ .

A = Answer: $\frac{81}{134}$

B = Answer: $\frac{50}{67}$

SOLUTION 1 :

A bag consists of 134 shirts.

n(S) = 134.

(i) ..... A trader A will accept only good shirts

n(A) = 81.

P(A) = n(A) / a(S) = $\frac{81}{134}$ = $\frac{81}{134}$ .

A will accept only good shirts = $\frac{81}{134}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 81 + 19 ( B accepts good and minor defects shirts)

= 100.

P(B) = n(B) / n(S) = $\frac{100}{134}$ = $\frac{50}{67}$

Trader B will accept the shirts which have minor defects = $\frac{50}{67}$ .

A = Answer: $\frac{83}{122}$

B = Answer: $\frac{53}{61}$

SOLUTION 1 :

A bag consists of 122 shirts.

n(S) = 122.

(i) ..... A trader A will accept only good shirts

n(A) = 83.

P(A) = n(A) / a(S) = $\frac{83}{122}$ = $\frac{83}{122}$ .

A will accept only good shirts = $\frac{83}{122}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 83 + 23 ( B accepts good and minor defects shirts)

= 106.

P(B) = n(B) / n(S) = $\frac{106}{122}$ = $\frac{53}{61}$

Trader B will accept the shirts which have minor defects = $\frac{53}{61}$ .

A = Answer: $\frac{32}{47}$

B = Answer: $\frac{37}{47}$

SOLUTION 1 :

A bag consists of 141 shirts.

n(S) = 141.

(i) ..... A trader A will accept only good shirts

n(A) = 96.

P(A) = n(A) / a(S) = $\frac{96}{141}$ = $\frac{32}{47}$ .

A will accept only good shirts = $\frac{32}{47}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 96 + 15 ( B accepts good and minor defects shirts)

= 111.

P(B) = n(B) / n(S) = $\frac{111}{141}$ = $\frac{37}{47}$

Trader B will accept the shirts which have minor defects = $\frac{37}{47}$ .

A = Answer: $\frac{13}{21}$

B = Answer: $\frac{109}{147}$

SOLUTION 1 :

A bag consists of 147 shirts.

n(S) = 147.

(i) ..... A trader A will accept only good shirts

n(A) = 91.

P(A) = n(A) / a(S) = $\frac{91}{147}$ = $\frac{13}{21}$ .

A will accept only good shirts = $\frac{13}{21}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 91 + 18 ( B accepts good and minor defects shirts)

= 109.

P(B) = n(B) / n(S) = $\frac{109}{147}$ = $\frac{109}{147}$

Trader B will accept the shirts which have minor defects = $\frac{109}{147}$ .

A = Answer: $\frac{77}{122}$

B = Answer: $\frac{51}{61}$

SOLUTION 1 :

A bag consists of 122 shirts.

n(S) = 122.

(i) ..... A trader A will accept only good shirts

n(A) = 77.

P(A) = n(A) / a(S) = $\frac{77}{122}$ = $\frac{77}{122}$ .

A will accept only good shirts = $\frac{77}{122}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 77 + 25 ( B accepts good and minor defects shirts)

= 102.

P(B) = n(B) / n(S) = $\frac{102}{122}$ = $\frac{51}{61}$

Trader B will accept the shirts which have minor defects = $\frac{51}{61}$ .

A = Answer: $\frac{83}{143}$

B = Answer: $\frac{107}{143}$

SOLUTION 1 :

A bag consists of 143 shirts.

n(S) = 143.

(i) ..... A trader A will accept only good shirts

n(A) = 83.

P(A) = n(A) / a(S) = $\frac{83}{143}$ = $\frac{83}{143}$ .

A will accept only good shirts = $\frac{83}{143}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 83 + 24 ( B accepts good and minor defects shirts)

= 107.

P(B) = n(B) / n(S) = $\frac{107}{143}$ = $\frac{107}{143}$

Trader B will accept the shirts which have minor defects = $\frac{107}{143}$ .

A = Answer: $\frac{50}{63}$

B = Answer: $\frac{17}{18}$

SOLUTION 1 :

A bag consists of 126 shirts.

n(S) = 126.

(i) ..... A trader A will accept only good shirts

n(A) = 100.

P(A) = n(A) / a(S) = $\frac{100}{126}$ = $\frac{50}{63}$ .

A will accept only good shirts = $\frac{50}{63}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 100 + 19 ( B accepts good and minor defects shirts)

= 119.

P(B) = n(B) / n(S) = $\frac{119}{126}$ = $\frac{17}{18}$

Trader B will accept the shirts which have minor defects = $\frac{17}{18}$ .

A = Answer: $\frac{19}{37}$

B = Answer: $\frac{99}{148}$

SOLUTION 1 :

A bag consists of 148 shirts.

n(S) = 148.

(i) ..... A trader A will accept only good shirts

n(A) = 76.

P(A) = n(A) / a(S) = $\frac{76}{148}$ = $\frac{19}{37}$ .

A will accept only good shirts = $\frac{19}{37}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 76 + 23 ( B accepts good and minor defects shirts)

= 99.

P(B) = n(B) / n(S) = $\frac{99}{148}$ = $\frac{99}{148}$

Trader B will accept the shirts which have minor defects = $\frac{99}{148}$ .

10)

A = Answer: $\frac{45}{67}$

B = Answer: $\frac{113}{134}$

SOLUTION 1 :

A bag consists of 134 shirts.

n(S) = 134.

(i) ..... A trader A will accept only good shirts

n(A) = 90.

P(A) = n(A) / a(S) = $\frac{90}{134}$ = $\frac{45}{67}$ .

A will accept only good shirts = $\frac{45}{67}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 90 + 23 ( B accepts good and minor defects shirts)

= 113.

P(B) = n(B) / n(S) = $\frac{113}{134}$ = $\frac{113}{134}$

Trader B will accept the shirts which have minor defects = $\frac{113}{134}$ .