Sasi Math (Revised for 1024)

Scroll:Probability >> probability >> ps (4493)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

A bag consists of 150 shirts of which 78 are good, 16 have minor defects and 11 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 133 shirts of which 71 are good, 25 have minor defects and 8 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 135 shirts of which 78 are good, 24 have minor defects and 12 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 140 shirts of which 94 are good, 21 have minor defects and 13 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 125 shirts of which 70 are good, 15 have minor defects and 11 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 133 shirts of which 73 are good, 16 have minor defects and 9 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 137 shirts of which 94 are good, 19 have minor defects and 7 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 149 shirts of which 89 are good, 21 have minor defects and 13 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A bag consists of 125 shirts of which 92 are good, 23 have minor defects and 6 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

10)

A bag consists of 133 shirts of which 90 are good, 22 have minor defects and 8 have major defects. A trader A will accept only the shirt which are good, but the trader B will not accept the shirts which have major defects. One shirt is drawn at random. what is the probability that it is acceptable by (i) A (ii) B .

A =

B =

Answer:_______________

A = Answer: $\frac{13}{25}$

B = Answer: $\frac{47}{75}$

SOLUTION 1 :

A bag consists of 150 shirts.

n(S) = 150.

(i) ..... A trader A will accept only good shirts

n(A) = 78.

P(A) = n(A) / a(S) = $\frac{78}{150}$ = $\frac{13}{25}$ .

A will accept only good shirts = $\frac{13}{25}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 78 + 16 ( B accepts good and minor defects shirts)

= 94.

P(B) = n(B) / n(S) = $\frac{94}{150}$ = $\frac{47}{75}$

Trader B will accept the shirts which have minor defects = $\frac{47}{75}$ .

A = Answer: $\frac{71}{133}$

B = Answer: $\frac{96}{133}$

SOLUTION 1 :

A bag consists of 133 shirts.

n(S) = 133.

(i) ..... A trader A will accept only good shirts

n(A) = 71.

P(A) = n(A) / a(S) = $\frac{71}{133}$ = $\frac{71}{133}$ .

A will accept only good shirts = $\frac{71}{133}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 71 + 25 ( B accepts good and minor defects shirts)

= 96.

P(B) = n(B) / n(S) = $\frac{96}{133}$ = $\frac{96}{133}$

Trader B will accept the shirts which have minor defects = $\frac{96}{133}$ .

A = Answer: $\frac{26}{45}$

B = Answer: $\frac{34}{45}$

SOLUTION 1 :

A bag consists of 135 shirts.

n(S) = 135.

(i) ..... A trader A will accept only good shirts

n(A) = 78.

P(A) = n(A) / a(S) = $\frac{78}{135}$ = $\frac{26}{45}$ .

A will accept only good shirts = $\frac{26}{45}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 78 + 24 ( B accepts good and minor defects shirts)

= 102.

P(B) = n(B) / n(S) = $\frac{102}{135}$ = $\frac{34}{45}$

Trader B will accept the shirts which have minor defects = $\frac{34}{45}$ .

A = Answer: $\frac{47}{70}$

B = Answer: $\frac{23}{28}$

SOLUTION 1 :

A bag consists of 140 shirts.

n(S) = 140.

(i) ..... A trader A will accept only good shirts

n(A) = 94.

P(A) = n(A) / a(S) = $\frac{94}{140}$ = $\frac{47}{70}$ .

A will accept only good shirts = $\frac{47}{70}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 94 + 21 ( B accepts good and minor defects shirts)

= 115.

P(B) = n(B) / n(S) = $\frac{115}{140}$ = $\frac{23}{28}$

Trader B will accept the shirts which have minor defects = $\frac{23}{28}$ .

A = Answer: $\frac{14}{25}$

B = Answer: $\frac{17}{25}$

SOLUTION 1 :

A bag consists of 125 shirts.

n(S) = 125.

(i) ..... A trader A will accept only good shirts

n(A) = 70.

P(A) = n(A) / a(S) = $\frac{70}{125}$ = $\frac{14}{25}$ .

A will accept only good shirts = $\frac{14}{25}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 70 + 15 ( B accepts good and minor defects shirts)

= 85.

P(B) = n(B) / n(S) = $\frac{85}{125}$ = $\frac{17}{25}$

Trader B will accept the shirts which have minor defects = $\frac{17}{25}$ .

A = Answer: $\frac{73}{133}$

B = Answer: $\frac{89}{133}$

SOLUTION 1 :

A bag consists of 133 shirts.

n(S) = 133.

(i) ..... A trader A will accept only good shirts

n(A) = 73.

P(A) = n(A) / a(S) = $\frac{73}{133}$ = $\frac{73}{133}$ .

A will accept only good shirts = $\frac{73}{133}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 73 + 16 ( B accepts good and minor defects shirts)

= 89.

P(B) = n(B) / n(S) = $\frac{89}{133}$ = $\frac{89}{133}$

Trader B will accept the shirts which have minor defects = $\frac{89}{133}$ .

A = Answer: $\frac{94}{137}$

B = Answer: $\frac{113}{137}$

SOLUTION 1 :

A bag consists of 137 shirts.

n(S) = 137.

(i) ..... A trader A will accept only good shirts

n(A) = 94.

P(A) = n(A) / a(S) = $\frac{94}{137}$ = $\frac{94}{137}$ .

A will accept only good shirts = $\frac{94}{137}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 94 + 19 ( B accepts good and minor defects shirts)

= 113.

P(B) = n(B) / n(S) = $\frac{113}{137}$ = $\frac{113}{137}$

Trader B will accept the shirts which have minor defects = $\frac{113}{137}$ .

A = Answer: $\frac{89}{149}$

B = Answer: $\frac{110}{149}$

SOLUTION 1 :

A bag consists of 149 shirts.

n(S) = 149.

(i) ..... A trader A will accept only good shirts

n(A) = 89.

P(A) = n(A) / a(S) = $\frac{89}{149}$ = $\frac{89}{149}$ .

A will accept only good shirts = $\frac{89}{149}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 89 + 21 ( B accepts good and minor defects shirts)

= 110.

P(B) = n(B) / n(S) = $\frac{110}{149}$ = $\frac{110}{149}$

Trader B will accept the shirts which have minor defects = $\frac{110}{149}$ .

A = Answer: $\frac{92}{125}$

B = Answer: $\frac{23}{25}$

SOLUTION 1 :

A bag consists of 125 shirts.

n(S) = 125.

(i) ..... A trader A will accept only good shirts

n(A) = 92.

P(A) = n(A) / a(S) = $\frac{92}{125}$ = $\frac{92}{125}$ .

A will accept only good shirts = $\frac{92}{125}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 92 + 23 ( B accepts good and minor defects shirts)

= 115.

P(B) = n(B) / n(S) = $\frac{115}{125}$ = $\frac{23}{25}$

Trader B will accept the shirts which have minor defects = $\frac{23}{25}$ .

10)

A = Answer: $\frac{90}{133}$

B = Answer: $\frac{16}{19}$

SOLUTION 1 :

A bag consists of 133 shirts.

n(S) = 133.

(i) ..... A trader A will accept only good shirts

n(A) = 90.

P(A) = n(A) / a(S) = $\frac{90}{133}$ = $\frac{90}{133}$ .

A will accept only good shirts = $\frac{90}{133}$

(ii) .... A trader B will not accept the shirts which have major defects.

Trader B will accept the shirts which have minor defects.

n(B) = 90 + 22 ( B accepts good and minor defects shirts)

= 112.

P(B) = n(B) / n(S) = $\frac{112}{133}$ = $\frac{16}{19}$

Trader B will accept the shirts which have minor defects = $\frac{16}{19}$ .