Sasi Math (Revised for 1024)

Scroll:Probability >> probability >> ps (4494)

Written Instructions:

For each Multiple Choice Question (MCQ), four options are given. One of them is the correct answer. Make your choice (1,2,3 or 4). Write your answers in the brackets provided..

For each Short Answer Question(SAQ) and Long Answer Question(LAQ), write your answers in the blanks provided.

Leave your answers in the simplest form or correct to two decimal places.

Piggy bank contains 150 fifty-paise coins, 70 one-rupee coins, 30 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 190 fifty-paise coins, 50 one-rupee coins, 30 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 250 fifty-paise coins, 70 one-rupee coins, 35 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 230 fifty-paise coins, 65 one-rupee coins, 30 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 130 fifty-paise coins, 65 one-rupee coins, 40 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 100 fifty-paise coins, 65 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 220 fifty-paise coins, 50 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 270 fifty-paise coins, 60 one-rupee coins, 30 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 180 fifty-paise coins, 60 one-rupee coins, 30 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

10)

Piggy bank contains 260 fifty-paise coins, 65 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin =

Will not be a five-ruoees coin =

Answer:_______________

Piggy bank contains 150 fifty-paise coins, 70 one-rupee coins, 30 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{15}{26}$

Will not be a five-ruoees coin = Answer: $\frac{25}{26}$

SOLUTION 1 :

Sample space, S has 260 coins which 10 fifty-paise coins, 70 one rupee coins, 30 two rupees coins and 10 five rupee coins.

n(S) = 150 + 70 + 30 + 10

= 260.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 260.

P(A) = n(A) / n(S) = $\frac{150}{260}$ = $\frac{15}{26}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 260 - 10 = 250.

P(B) = n(B) / n(S) = $\frac{250}{260}$ = $\frac{25}{26}$ .

Piggy bank contains 190 fifty-paise coins, 50 one-rupee coins, 30 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{2}{3}$

Will not be a five-ruoees coin = Answer: $\frac{18}{19}$

SOLUTION 1 :

Sample space, S has 285 coins which 15 fifty-paise coins, 50 one rupee coins, 30 two rupees coins and 15 five rupee coins.

n(S) = 190 + 50 + 30 + 15

= 285.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 285.

P(A) = n(A) / n(S) = $\frac{190}{285}$ = $\frac{2}{3}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 15

= 285 - 15 = 270.

P(B) = n(B) / n(S) = $\frac{270}{285}$ = $\frac{18}{19}$ .

Piggy bank contains 250 fifty-paise coins, 70 one-rupee coins, 35 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{25}{37}$

Will not be a five-ruoees coin = Answer: $\frac{71}{74}$

SOLUTION 1 :

Sample space, S has 370 coins which 15 fifty-paise coins, 70 one rupee coins, 35 two rupees coins and 15 five rupee coins.

n(S) = 250 + 70 + 35 + 15

= 370.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 370.

P(A) = n(A) / n(S) = $\frac{250}{370}$ = $\frac{25}{37}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 15

= 370 - 15 = 355.

P(B) = n(B) / n(S) = $\frac{355}{370}$ = $\frac{71}{74}$ .

Piggy bank contains 230 fifty-paise coins, 65 one-rupee coins, 30 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{46}{67}$

Will not be a five-ruoees coin = Answer: $\frac{65}{67}$

SOLUTION 1 :

Sample space, S has 335 coins which 10 fifty-paise coins, 65 one rupee coins, 30 two rupees coins and 10 five rupee coins.

n(S) = 230 + 65 + 30 + 10

= 335.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 335.

P(A) = n(A) / n(S) = $\frac{230}{335}$ = $\frac{46}{67}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 335 - 10 = 325.

P(B) = n(B) / n(S) = $\frac{325}{335}$ = $\frac{65}{67}$ .

Piggy bank contains 130 fifty-paise coins, 65 one-rupee coins, 40 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{13}{25}$

Will not be a five-ruoees coin = Answer: $\frac{47}{50}$

SOLUTION 1 :

Sample space, S has 250 coins which 15 fifty-paise coins, 65 one rupee coins, 40 two rupees coins and 15 five rupee coins.

n(S) = 130 + 65 + 40 + 15

= 250.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 250.

P(A) = n(A) / n(S) = $\frac{130}{250}$ = $\frac{13}{25}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 15

= 250 - 15 = 235.

P(B) = n(B) / n(S) = $\frac{235}{250}$ = $\frac{47}{50}$ .

Piggy bank contains 100 fifty-paise coins, 65 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{10}{21}$

Will not be a five-ruoees coin = Answer: $\frac{20}{21}$

SOLUTION 1 :

Sample space, S has 210 coins which 10 fifty-paise coins, 65 one rupee coins, 35 two rupees coins and 10 five rupee coins.

n(S) = 100 + 65 + 35 + 10

= 210.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 210.

P(A) = n(A) / n(S) = $\frac{100}{210}$ = $\frac{10}{21}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 210 - 10 = 200.

P(B) = n(B) / n(S) = $\frac{200}{210}$ = $\frac{20}{21}$ .

Piggy bank contains 220 fifty-paise coins, 50 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{44}{63}$

Will not be a five-ruoees coin = Answer: $\frac{61}{63}$

SOLUTION 1 :

Sample space, S has 315 coins which 10 fifty-paise coins, 50 one rupee coins, 35 two rupees coins and 10 five rupee coins.

n(S) = 220 + 50 + 35 + 10

= 315.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 315.

P(A) = n(A) / n(S) = $\frac{220}{315}$ = $\frac{44}{63}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 315 - 10 = 305.

P(B) = n(B) / n(S) = $\frac{305}{315}$ = $\frac{61}{63}$ .

Piggy bank contains 270 fifty-paise coins, 60 one-rupee coins, 30 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{18}{25}$

Will not be a five-ruoees coin = Answer: $\frac{24}{25}$

SOLUTION 1 :

Sample space, S has 375 coins which 15 fifty-paise coins, 60 one rupee coins, 30 two rupees coins and 15 five rupee coins.

n(S) = 270 + 60 + 30 + 15

= 375.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 375.

P(A) = n(A) / n(S) = $\frac{270}{375}$ = $\frac{18}{25}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 15

= 375 - 15 = 360.

P(B) = n(B) / n(S) = $\frac{360}{375}$ = $\frac{24}{25}$ .

Piggy bank contains 180 fifty-paise coins, 60 one-rupee coins, 30 two-rupee coins and 15 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{12}{19}$

Will not be a five-ruoees coin = Answer: $\frac{18}{19}$

SOLUTION 1 :

Sample space, S has 285 coins which 15 fifty-paise coins, 60 one rupee coins, 30 two rupees coins and 15 five rupee coins.

n(S) = 180 + 60 + 30 + 15

= 285.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 285.

P(A) = n(A) / n(S) = $\frac{180}{285}$ = $\frac{12}{19}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 15

= 285 - 15 = 270.

P(B) = n(B) / n(S) = $\frac{270}{285}$ = $\frac{18}{19}$ .

10)

Piggy bank contains 260 fifty-paise coins, 65 one-rupee coins, 35 two-rupee coins and 10 five-rupee coins. One coin is drawn at random.Find the probability that the drawn coin

(i) will be a fifty-paise coin (ii) will not be a five-rupees coin.

Will be a fifty-paise coin = Answer: $\frac{26}{37}$

Will not be a five-ruoees coin = Answer: $\frac{36}{37}$

SOLUTION 1 :

Sample space, S has 370 coins which 10 fifty-paise coins, 65 one rupee coins, 35 two rupees coins and 10 five rupee coins.

n(S) = 260 + 65 + 35 + 10

= 370.

(i) .... Let A be the event of taking one coin which is fifty-paise coin.

n(A) = 370.

P(A) = n(A) / n(S) = $\frac{260}{370}$ = $\frac{26}{37}$

(ii) ..... Let B be the event of taking one coin which is not a five rupee coin.

n(B) = n(S) - 10

= 370 - 10 = 360.

P(B) = n(B) / n(S) = $\frac{360}{370}$ = $\frac{36}{37}$ .